NYOJ 218 Dinner

Dinner

时间限制： 100 ms  |  内存限制： 65535 KB

难度： 1

描述

Little A is one member of ACM team. He had just won the gold in World Final. To celebrate, he decided to invite all to have one meal. As bowl, knife and other tableware is not enough in the kitchen, Little A goes to take backup tableware in warehouse. There are many boxes in warehouse, one box contains only one thing, and each box is marked by the name of things inside it. For example, if "basketball" is written on the box, which means the box contains only basketball. With these marks, Little A wants to find out the tableware easily. So, the problem for you is to help him, find out all the tableware from all boxes in the warehouse.

输入

There are many test cases. Each case contains one line, and one integer N at the first, N indicates that there are N boxes in the warehouse. Then N strings follow, each string is one name written on the box.

输出

For each test of the input, output all the name of tableware.

样例输入

3 basketball fork chopsticks
2 bowl letter

样例输出

fork chopsticks
bowl

提示

The tableware only contains: bowl, knife, fork and chopsticks.

水题，在南阳OJ的贪心分类里，丝毫没看见哪里用到了贪心的思想，是我太笨了吗?

不过已AC，代码如下：

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
char str[100][100];
int main()
{
	int n,i;
	while(scanf("%d",&n)!=EOF)
	{
		for(i=0;i<n;i++)
	        scanf("%s",str[i]);
	    int k=0;
	    for(i=0;i<n;i++)
	    {
		     if(strcmp(str[i],"bowl")==0||strcmp(str[i],"knife")==0||strcmp(str[i],"fork")==0||strcmp(str[i],"chopsticks")==0)
		     {
		     	if(k==0)
		     	   printf("%s",str[i]);
		     	else printf(" %s",str[i]);
		     	k++;//南阳的测试不严格，不用这么处理空格也能过 
		     }
	    }
	    printf("\n");
	}
	return 0;
}