pku 1141_DP

pku 1141_DP

//黑书有介绍，参考，但要添加对相应串的存储，黑书的代码有可改进的...

#include < iostream >
#include < string >
using   namespace  std;
#define  INF 2000000000

char  str[ 102 ];
int  d[ 102 ][ 102 ];
string  ans[ 102 ][ 102 ];

void  dp()
{
    int i,j,k,p,n;
    n=strlen(str+1);
    for(i=1;i<=n;i++) 
    {
        d[i][i-1]=0;
        d[i][i]=1;
        if(str[i]=='(') ans[i][i]="()";
        if(str[i]==')') ans[i][i]="()";
        if(str[i]=='[') ans[i][i]="[]";
        if(str[i]==']') ans[i][i]="[]";
    }
    for(p=1;p<n;p++)
    {
        for(i=1;i<=n-p;i++)
        {
            j=i+p;
            d[i][j]=INF;
            if(str[i]=='(' && str[j]==')')
            {
                if(d[i+1][j-1]<d[i][j])
                {
                    d[i][j]=d[i+1][j-1];
                    ans[i][j]='('+ans[i+1][j-1]+')';
                }
            }
            else {
                if(str[i]=='[' && str[j]==']')
                {
                    if(d[i+1][j-1]<d[i][j])
                    {
                        d[i][j]=d[i+1][j-1];
                        ans[i][j]='['+ans[i+1][j-1]+']';
                    }
                }
            }
            for(k=i;k<=j-1;k++)
            {
                if(d[i][k]+d[k+1][j]<d[i][j])
                {
                    d[i][j]=d[i][k]+d[k+1][j];
                    ans[i][j]=ans[i][k]+ans[k+1][j];
                }
            }
        }
    }
    cout<<ans[1][n]<<endl;
}

int  main()
{
    scanf("%s",str+1);
    dp();
    return 0;
}