UVa 10361 Automatic Poetry

UVa 10361 Automatic Poetry

简述题目大意：两个字符串，一个是s1<s2>s3<s4>s5，另一个是s'...，输出s1s2s3s4s5和s's4s3s2s5。It's so easy!Do you think so?

以下是我的代码：

#include < iostream >
#include < string >
using   namespace  std;
int  main()
{
    long n;
    cin>>n;
    getchar();
    for(long cas=1;cas<=n;cas++)
    {
        string a,b,ans;
        getline(cin,a);
        for(long i=0;a[i];i++)
          if(a[i]!='<'&&a[i]!='>')
            cout<<a[i];
        cout<<endl;
        // Print the First Line
        getline(cin,b);
        // Read In stringA and stringB
        
        long j,pos[5]={0};
        j=0;
        for(long i=0;a[i];i++)
          if(a[i]=='<'||a[i]=='>')
          {
             j++;
             pos[j]=i;
          }
        // Get Four Positions
        
        string _1="",_2="",_3="",_4="";
        for(long i=pos[1]+1;i<=pos[2]-1;i++)
          _1+=a[i];
        for(long i=pos[2]+1;i<=pos[3]-1;i++)
          _2+=a[i];
        for(long i=pos[3]+1;i<=pos[4]-1;i++)
          _3+=a[i];
        for(long i=pos[4]+1;a[i];i++)
          _4+=a[i];
        
        ans="";
        for(long i=0;b[i];i++)
        {
           if(b[i]!='.')
             ans+=b[i];
           else
           {
              ans+=_3+_2+_1+_4;
              break;
           }
        }
        cout<<ans<<endl;
        // Print the Secont Line
    }
return 0;
}