杭电ACM1021裴波纳挈数AGAIN

 #include<iostream>
 using namespace std;

 int main()
 {
     int n;
     while(cin>>n&&n < 1000000)
    if(n%8==2||n%8==6)
    cout<<"yes"<<endl;
    else
    cout<<"no"<<endl;
     return 0;
 }