Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 33539 | Accepted: 13568 |
Description
The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.
Input
The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
Output
For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.
Sample Input
3 BAPC BAPC AZA AZAZAZA VERDI AVERDXIVYERDIAN
Sample Output
1 3 0
题意:第一行输入测试数据的组数,接下来有T组测试数据,每一组先输入模式串,然后输入主串,问模式串在主串中出现的次数。
解题思路:最基础的KMP模式串匹配问题,先求出模式串的 next 数组,然后根据 next 数组遍历主串,避免不必要的匹配
其中next数组的具体 求法 和 含义
参考博文:http://blog.csdn.net/liu940204/article/details/51318281
http://blog.csdn.net/liu940204/article/details/51333045
具体代码: #include <stdio.h> #include <string.h> char s1[10005]; char s2[1000005]; int next[10005]; void Make_next(int lm) { int i=0,j=-1; memset(next,0,sizeof(next)); next[0]=-1; while(i<lm) { if(j==-1 || s1[i]==s1[j]) { i++; j++; next[i]=j; } else j=next[j]; } } int Kmp(int ln,int lm) { Make_next(lm); int i=0,j=0; int count=0; while(i<ln) { if(j==-1 || s2[i]==s1[j]) { i++; j++; } else j=next[j]; if(j==lm) count++; } return count; } int main() { int T; scanf("%d",&T); while(T--) { scanf("\n%s\n%s",s1,s2); int ln=strlen(s2); int lm=strlen(s1); printf("%d\n",Kmp(ln,lm)); } return 0; }