HDOJ_ACM_steps——Identity Card

 

没什么难的，不过一个cout<<让我纠结了很久

学到一个新函数：

“

函数名: strncmp

功 能: 串比较

用 法: int strncmp(char *str1, char *str2, int maxlen);

说明:此函数功能即比较 字符串str1和str2的前maxlen个字符。如果前maxlen 字节完全相等，返回值就=0；在前maxlen字节比较过程中，如果出现str1[n]与str2[n]不等，则返回（str1[n]-str2[n]）。

”

#include <iostream>
#include <stdio.h>
#include <cstring>
using namespace std;


int main() {
	int count;
	char s[20];
	string id[8] = {"33", "11", "71", "81", "82", "54", "21", "31"};
	string place[8]={"Zhejiang","Beijing","Taiwan","Hong Kong","Macao","Tibet","Liaoning","Shanghai"};
	scanf("%d",&count);
	while(count--){
		scanf("%s",&s);
		printf("He/She is from ");
		for(int i=0;i<8;i++){
			if(strncmp(s, id[i].c_str(), 2) ==0 ){
				cout<<place[i];//可能会有问题
			}
		}
		printf(",and his/her birthday is on ");
		printf("%c%c,%c%c,%c%c%c%c",s[10],s[11],s[12],s[13],s[6],s[7],s[8],s[9]);
		printf(" based on the table.");
	}
	return 0;
}