hdu1247Hat’s Words

先对把每个单词都放到字典树中去，然后就是对每个单词进行切割，判断是否两部分都在字典树中。

/*****************************************
Author      :Crazy_AC(JamesQi)
Time        :2016
File Name   :
*****************************************/
// #pragma comment(linker, "/STACK:1024000000,1024000000")
#include <iostream>
#include <algorithm>
#include <iomanip>
#include <sstream>
#include <string>
#include <stack>
#include <queue>
#include <deque>
#include <vector>
#include <map>
#include <set>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <cstdlib>
#include <climits>
using namespace std;
#define MEM(x,y) memset(x, y,sizeof x)
#define pk push_back
typedef long long LL;
typedef unsigned long long ULL;
typedef pair<int,int> ii;
typedef pair<ii,int> iii;
const double eps = 1e-10;
const int inf = 1 << 30;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + 7;
const int maxn = 5e4 + 10;
const int maxm = 105;
char str[maxn][maxm];
char ans[maxm];
struct node {
	int val;
	node *nxt[26];
};
struct Tire {
	node *rt;

	void init() {
		rt = new node();
	}

	void insert(char *s) {
		node* p = rt;
		int len = strlen(s);
		for (int i = 0;i < len;++i) {
			int id = s[i] - 'a';
			if (p->nxt[id] == NULL) p->nxt[id] = new node();
			p = p->nxt[id];
		}
		p->val = 1;
	}

	bool find(char *s) {
		node *p = rt;
		int len = strlen(s);
		for (int i = 0;i < len;++i) {
			int id = s[i] - 'a';
			if (p->nxt[id] == NULL) return false;
			p = p->nxt[id];
		}
		return p->val == 1;
	}
}solve;
void del(node *t) {
	for (int i = 0;i < 26;++i) {
		if (t->nxt[i] != NULL) del(t->nxt[i]);
	}
	delete t;
}
int main()
{	
	// freopen("in.txt","r",stdin);
	// freopen("out.txt","w",stdout);
	int n = 0;
	solve.init();
	while(scanf("%s",str[n]) != EOF) {
		solve.insert(str[n]);
		n++;
	}
	for (int i = 0;i < n;++i) {
		int len = strlen(str[i]);
		for (int j = 1;j < len - 1;++j) {
			strncpy(ans,str[i],j);
			ans[j] = '\0';
			if (solve.find(ans) && solve.find(str[i] + j)) {
				puts(str[i]);
				break;
			}
		}
	}
	del(solve.rt);
	return 0;
}