做着做着卡住了。。。。。。
本来以为是三分的,结果发现错了。。。。。
这题不仅要枚举精度,还要枚举做法QAQ
或者说是我太弱了,根本没想到旋转卡壳。
第一次知道旋转卡壳还可以这么玩,左卡卡,右卡卡,上卡卡,哎然后一个矩形就卡好了。
听说SPJ很好玩的样子233333
#include<iostream> #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> using namespace std; const double eps=1e-9; const int N=50000+5; int dcmp(double x){ if(fabs(x)<eps)return 0; return x<0?-1:1; } struct point{ double x,y; bool operator < (const point &rhs)const{ if(dcmp(x-rhs.x))return x<rhs.x; return y<rhs.y; } }p[N],ch[N],rec[4]; point operator - (point a,point b){ return (point){a.x-b.x,a.y-b.y}; } point operator * (point a,double k){ return (point){a.x*k,a.y*k}; } point operator / (point a,double k){ return (point){a.x/k,a.y/k}; } point operator + (point a,point b){ return (point){a.x+b.x,a.y+b.y}; } double cross(point a,point b){ return a.x*b.y-a.y*b.x; } double cross(point a,point b,point c){ return cross(b-a,c-a); } double dot(point a,point b){ return a.x*b.x+a.y*b.y; } double dot(point a,point b,point c){ return dot(b-a,c-a); } double sqr(double x){return x*x;} double length(point p){ return sqrt(sqr(p.x)+sqr(p.y)); } double length(point a,point b){ return length(a-b); } double area(point a,point b,point c){ return fabs(cross(a,b,c)); } int n,m; void Andrew(){ sort(p+1,p+1+n); for(int i=1;i<=n;i++){ while(m>1&&dcmp(cross(ch[m-2],ch[m-1],p[i]))<=0)m--; ch[m++]=p[i]; } int k=m; for(int i=n-1;i>=1;i--){ while(m>k&&dcmp(cross(ch[m-2],ch[m-1],p[i]))<=0)m--; ch[m++]=p[i]; } if(n)m--; } double rotating(){ double ans=1e60; int p=1,q=1,r=1; ch[m]=ch[0]; for(int i=0;i<m;i++){ double len=length(ch[i],ch[i+1]); while(dcmp(cross(ch[i],ch[i+1],ch[r])-cross(ch[i],ch[i+1],ch[r+1]))<=0)r=(r+1)%m; while(dcmp(dot(ch[i],ch[i+1],ch[p])-dot(ch[i],ch[i+1],ch[p+1]))<=0)p=(p+1)%m; if(!i)q=r; while(dcmp(dot(ch[i],ch[i+1],ch[q])-dot(ch[i],ch[i+1],ch[q+1]))>=0)q=(q+1)%m; double h=area(ch[i],ch[i+1],ch[r])/len; double ll=fabs(dot(ch[i],ch[i+1],ch[q])/len); double rl=dot(ch[i],ch[i+1],ch[p])/len; double w=ll+rl; if(h*w<ans){ ans=h*w; rec[0]=ch[i]+(ch[i+1]-ch[i])*(rl/len); rec[1]=rec[0]+(ch[p]-rec[0])*(h/length(rec[0],ch[p])); rec[2]=rec[1]+(ch[r]-rec[1])*(w/length(rec[1],ch[r])); rec[3]=rec[2]+(ch[q]-rec[2])*(h/length(rec[2],ch[q])); } } return ans; } int main(){ //freopen("a.in","r",stdin); scanf("%d",&n); for(int i=1;i<=n;i++) scanf("%lf%lf",&p[i].x,&p[i].y); Andrew(); printf("%.5lf\n",rotating()); int st=0; for(int i=1;i<4;i++){ int d1=dcmp(rec[i].y-rec[st].y),d2=dcmp(rec[i].x-rec[st].x); if(d1<0)st=i; else if(!d1&&d2<0)st=i; } for(int i=1;i<=4;i++){ printf("%.5lf %.5lf\n",rec[st].x,rec[st].y); st=(st+1)%4; } return 0; }