checkio （tic-tac-toe）

Tic-Tac-Toe, sometimes also known as Xs and Os, is a game for two players (X and O) who take turns marking the spaces in a 3×3 grid. The player who succeeds in placing three respective marks in a horizontal, vertical, or diagonal rows (NW-SE and NE-SW) wins the game.

But we will not be playing this game. You will be the referee for this games results. You are given a result of a game and you must determine if the game ends in a win or a draw as well as who will be the winner. Make sure to return "X" if the X-player wins and "O" if the O-player wins. If the game is a draw, return "D."

A game's result is presented as a list of strings, where "X" and "O" are players' marks and "." is the empty cell.

Input: A game's result. A list of strings (Unicode).

Output: "X", "O" or "D". A string.

Example:

checkio([
    "X.O",
    "XX.",
    "XOO"]) == "X", "Xs wins"
checkio([
    "OO.",
    "XOX",
    "XOX"]) == "O"
checkio([
    "OOX",
    "XXO",
    "OXX"]) == "D"

How it is used: The concepts in this task will help you when iterating data types. They can also used in game algorithms, allowing you to know how to check results.

开始写的略复杂，A了后看下网上高手做的这题代码，真是涨姿势

def checkio(game_result):
    r = [[game_result[0][0],game_result[1][1],game_result[2][2]],[game_result[0][2],game_result[1][1],game_result[2][0]]]
    for i in range(3):
        r.append([x for x in game_result[i]])
        r += [[row[i] for row in game_result]]

    if ['X','X','X'] in r:
        return 'X'
    if ['O','O','O'] in r:
        return 'O'
    return 'D'

#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio([
        u"X.O",
        u"XX.",
        u"XOO"]) == "X", "Xs wins"
    assert checkio([
        u"OO.",
        u"XOX",
        u"XOX"]) == "O", "Os wins"

    assert checkio([
        u"OOX",
        u"XXO",
        u"OXX"]) == "D", "Draw"
    assert checkio([
        u"O.X",
        u"XX.",
        u"XOO"]) == "X", "Xs wins again"