ACM--三角形重心--HDOJ 2105--The Center of Gravity

HDOJ题目地址：传送门

The Center of Gravity

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 5487    Accepted Submission(s): 3129

Problem Description

Everyone know the story that how Newton discovered the Universal Gravitation. One day, Newton walked 
leisurely, suddenly, an apple hit his head. Then Newton discovered the Universal Gravitation.From then
on,people have sovled many problems by the the theory of the Universal Gravitation. What's more, wo also
have known every object has its Center of Gravity.
Now,you have been given the coordinates of three points of a triangle. Can you calculate the center 
of gravity of the triangle?

 

Input

The first line is an integer n,which is the number of test cases.
Then n lines follow. Each line has 6 numbers x1,y1,x2,y2,x3,y3,which are the coordinates of three points.
The input is terminated by n = 0.

 

Output

For each case, print the coordinate, accurate up to 1 decimal places.

 

Sample Input

   
   
   
   

    
    
    
    2
1.0 2.0 3.0 4.0 5.0 2.0
1.0 1.0 4.0 1.0 1.0 5.0
0
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    3.0 2.7
2.0 2.3
   
   
   
   

题解：就是求三角形的重心，但是这个题目要注意下一键盘录入。

#include<iostream>
#include<stdio.h>
using namespace std;
int main(){
   int n;
   double x1,x2,x3,y1,y2,y3;
   while(cin>>n){
       if(n==0)
          break;
       while(n--){
         cin>>x1>>y1>>x2>>y2>>x3>>y3;
         printf("%.1lf %.1lf\n",(x1+x2+x3)/3,(y1+y2+y3)/3);
     }
   }
   return 0;
}