条码(code128)的不同版本实现
好久没写Blog了，这次写写条码（code128)打印的实现。条码在工业应用方面很广泛，所以我们在编写程序时，特别是打印报表时，经常用到。
#region "本段为转载" 转自:http://kaliking.blog.51cto.com/58641/33734
先简述一下CODE128的原理吧,分别以一个unicode字符作为起始符(Ì)和终止符(Î),
然后需要根据你的字符串, 计算出当前字符集的校验码:
ode 128 Barcode Table
| Value |
Code Set A |
Code Set B |
Code Set C |
Bar/Space Pattern B S B S B S |
|---|---|---|---|---|
| 0 |
SP |
SP |
00 |
2 1 2 2 2 2 |
| 1 |
! |
! |
01 |
2 2 2 1 2 2 |
| 2 |
" |
" |
02 |
2 2 2 2 2 1 |
| 3 |
# |
# |
03 |
1 2 1 2 2 3 |
| 4 |
$ |
$ |
04 |
1 2 1 3 2 2 |
| 5 |
% |
% |
05 |
1 3 1 2 2 2 |
| 6 |
& |
& |
06 |
1 2 2 2 1 3 |
| 7 |
' |
' |
07 |
1 2 2 3 1 2 |
| 8 |
( |
( |
08 |
1 3 2 2 1 2 |
| 9 |
) |
) |
09 |
2 2 1 2 1 3 |
| 10 |
* |
* |
10 |
2 2 1 3 1 2 |
| 11 |
+ |
+ |
11 |
2 3 1 2 1 2 |
| 12 |
, |
, |
12 |
1 1 2 2 3 2 |
| 13 |
- |
- |
13 |
1 2 2 1 3 2 |
| 14 |
. |
. |
14 |
1 2 2 2 3 1 |
| 15 |
/ |
/ |
15 |
1 1 3 2 2 2 |
| 16 |
0 |
0 |
16 |
1 2 3 1 2 2 |
| 17 |
1 |
1 |
17 |
1 2 3 2 2 1 |
| 18 |
2 |
2 |
18 |
2 2 3 2 1 1 |
| 19 |
3 |
3 |
19 |
2 2 1 1 3 2 |
| 20 |
4 |
4 |
20 |
2 2 1 2 3 1 |
| 21 |
5 |
5 |
21 |
2 1 3 2 1 2 |
| 22 |
6 |
6 |
22 |
2 2 3 1 1 2 |
| 23 |
7 |
7 |
23 |
3 1 2 1 3 1 |
| 24 |
8 |
8 |
24 |
3 1 1 2 2 2 |
| 25 |
9 |
9 |
25 |
3 2 1 1 2 2 |
| 26 |
: |
: |
26 |
3 2 1 2 2 1 |
| 27 |
; |
; |
27 |
3 1 2 2 1 2 |
| 28 |
< |
< |
28 |
3 2 2 1 1 2 |
| 29 |
= |
= |
29 |
3 2 2 2 1 1 |
| 30 |
> |
> |
30 |
2 1 2 1 2 3 |
| 31 |
? |
? |
31 |
2 1 2 3 2 1 |
| 32 |
@ |
@ |
32 |
2 3 2 1 2 1 |
| 33 |
A |
A |
33 |
1 1 1 3 2 3 |
| 34 |
B |
B |
34 |
1 3 1 1 2 3 |
| 35 |
C |
C |
35 |
1 3 1 3 2 1 |
| 36 |
D |
D |
36 |
1 1 2 3 1 3 |
| 37 |
E |
E |
37 |
1 3 2 1 1 3 |
| 38 |
F |
F |
38 |
1 3 2 3 1 1 |
| 39 |
G |
G |
39 |
2 1 1 3 1 3 |
| 40 |
H |
H |
40 |
2 3 1 1 1 3 |
| 41 |
I |
I |
41 |
2 3 1 3 1 1 |
| 42 |
J |
J |
42 |
1 1 2 1 3 3 |
| 43 |
K |
K |
43 |
1 1 2 3 3 1 |
| 44 |
L |
L |
44 |
1 3 2 1 3 1 |
| 45 |
M |
M |
45 |
1 1 3 1 2 3 |
| 46 |
N |
N |
46 |
1 1 3 3 2 1 |
| 47 |
O |
O |
47 |
1 3 3 1 2 1 |
| 48 |
P |
P |
48 |
3 1 3 1 2 1 |
| 49 |
Q |
Q |
49 |
2 1 1 3 3 1 |
| 50 |
R |
R |
50 |
2 3 1 1 3 1 |
| 51 |
S |
S |
51 |
2 1 3 1 1 3 |
| 52 |
T |
T |
52 |
2 1 3 3 1 1 |
| 53 |
U |
U |
53 |
2 1 3 1 3 1 |
| 54 |
V |
V |
54 |
3 1 1 1 2 3 |
| 55 |
W |
W |
55 |
3 1 1 3 2 1 |
| 56 |
X |
X |
56 |
3 3 1 1 2 1 |
| 57 |
Y |
Y |
57 |
3 1 2 1 1 3 |
| 58 |
Z |
Z |
58 |
3 1 2 3 1 1 |
| 59 |
[ |
[ |
59 |
3 3 2 1 1 1 |
| 60 |
/ |
/ |
60 |
3 1 4 1 1 1 |
| 61 |
] |
] |
61 |
2 2 1 4 1 1 |
| 62 |
^ |
^ |
62 |
4 3 1 1 1 1 |
| 63 |
_ |
_ |
63 |
1 1 1 2 2 4 |
| 64 |
NUL |
` |
64 |
1 1 1 4 2 2 |
| 65 |
SOH |
a |
65 |
1 2 1 1 2 4 |
| 66 |
STX |
b |
66 |
1 2 1 4 2 1 |
| 67 |
ETX |
c |
67 |
1 4 1 1 2 2 |
| 68 |
EOT |
d |
68 |
1 4 1 2 2 1 |
| 69 |
ENQ |
e |
69 |
1 1 2 2 1 4 |
| 70 |
ACK |
f |
70 |
1 1 2 4 1 2 |
| 71 |
BEL |
g |
71 |
1 2 2 1 1 4 |
| 72 |
BS |
h |
72 |
1 2 2 4 1 1 |
| 73 |
HT |
i |
73 |
1 4 2 1 1 2 |
| 74 |
LF |
j |
74 |
1 4 2 2 1 1 |
| 75 |
VT |
k |
75 |
2 4 1 2 1 1 |
| 76 |
FF |
I |
76 |
2 2 1 1 1 4 |
| 77 |
CR |
m |
77 |
4 1 3 1 1 1 |
| 78 |
SO |
n |
78 |
2 4 1 1 1 2 |
| 79 |
SI |
o |
79 |
1 3 4 1 1 1 |
| 80 |
DLE |
p |
80 |
1 1 1 2 4 2 |
| 81 |
DC1 |
q |
81 |
1 2 1 1 4 2 |
| 82 |
DC2 |
r |
82 |
1 2 1 2 4 1 |
| 83 |
DC3 |
s |
83 |
1 1 4 2 1 2 |
| 84 |
DC4 |
t |
84 |
1 2 4 1 1 2 |
| 85 |
NAK |
u |
85 |
1 2 4 2 1 1 |
| 86 |
SYN |
v |
86 |
4 1 1 2 1 2 |
| 87 |
ETB |
w |
87 |
4 2 1 1 1 2 |
| 88 |
CAN |
x |
88 |
4 2 1 2 1 1 |
| 89 |
EM |
y |
89 |
2 1 2 1 4 1 |
| 90 |
SUB |
z |
90 |
2 1 4 1 2 1 |
| 91 |
ESC |
{ |
91 |
4 1 2 1 2 1 |
| 92 |
FS |
| |
92 |
1 1 1 1 4 3 |
| 93 |
GS |
} |
93 |
1 1 1 3 4 1 |
| 94 |
RS |
~ |
94 |
1 3 1 1 4 1 |
| 95 |
US |
DEL |
95 |
1 1 4 1 1 3 |
| 96 |
FNC 3 |
FNC 3 |
96 |
1 1 4 3 1 1 |
| 97 |
FNC 2 |
FNC 2 |
97 |
4 1 1 1 1 3 |
| 98 |
SHIFT |
SHIFT |
98 |
4 1 1 3 1 1 |
| 99 |
CODE C |
CODE C |
99 |
1 1 3 1 4 1 |
| 100 |
CODE B |
FNC 4 |
CODE B |
1 1 4 1 3 1 |
| 101 |
FNC 4 |
CODE A |
CODE A |
3 1 1 1 4 1 |
| 102 |
FNC 1 |
FNC 1 |
FNC 1 |
4 1 1 1 3 1 |
| 103 |
Start A |
Start A |
Start A |
2 1 1 4 1 2 |
| 104 |
Start B |
Start B |
Start B |
2 1 1 2 1 4 |
| 105 |
Start C |
Start C |
Start C |
2 1 1 2 3 2 |
| 106 |
Stop |
Stop |
Stop |
2 3 3 1 1 1 2 |
Example... To calculate the check digit for the barcode data string 'Code 128'
Value Total
===== =====
Start Code B 104 104
Position 1 C 35 1 x 35 = 35
Position 2 o 79 2 x 79 = 158
Position 3 d 68 3 x 68 = 204
Position 4 e 69 4 x 69 = 276
Position 5 0 5 x 0 = 0
Position 6 1 17 6 x 17 = 102
Position 7 2 18 7 x 18 = 126
Position 8 8 24 8 x 24 = 192
=====
1197
=====
1197/103 = 11 remainder 64
根据上表, 把没个字符的value值 乘上 字符在字符串中的位置(从1开始算)
把没个乘积加起来
因为CODESET B 为104(这是规定, 不要问我为什么)
所以, 还要加上 104
最后, 除以103, 所得的余数就是 校验码 的value值, 然后在表中找到对应的字符
就可以了.
有心人应该注意到了, value>=95的时候, 是没有字符的(事实上还是有的,
只不过是unicode字符)
好了, 原理就阐述到这里, 还有什么不懂的话, 大家看看代码好了.
至于用在水晶报表上的问题, 我这里是配合条码字体的, 我会上传一个我正在用的字体.
代码如下:
Public Function StringToCode128(ByVal input As String) As String
Try
Dim endchar As Char
Dim total As Int64 = 104
Dim tmp As Integer
For i As Int16 = 1 To input.Length
tmp = Asc(input.Substring(i - 1, 1))
If tmp >= 32 Then
total += (tmp - 32) * i
Else
total += (tmp + 64) * i
End If
Next
Dim endAsc = total Mod 103
If endAsc >= 95 Then
Select Case endAsc
Case 95
endchar = "Ã"
Case 96
endchar = "Ä"
Case 97
endchar = "Å"
Case 98
endchar = "Æ"
Case 99
endchar = "Ç"
Case 100
endchar = "È"
Case 101
endchar = "É"
Case 102
endchar = "Ê"
End Select
Else
endAsc += 32
endchar = Chr(endAsc)
End If
Return "Ì" & input & endchar.ToString() & "Î"
Catch ex As Exception
WriteLog(ex.Message, ex.StackTrace)
Return String.Empty
Finally
End Try
End Function
我放大一下上面用到的特殊字符,大家看看清楚:
起始符:Ì
终止符:Î
value95:Ã
value96:Ä
value97:Å
value98:Æ
value99:Ç
value100:È
value101:É
value102:Ê
#endregion
根据以上代码，这作了几个转换的版本，用于不同的环境，
C#版本：
private string StringToCode128(string input)
{
try
{
char endChar=(char)0;
Int64 total = 104;
int tmp;
Int64 endAsc;
for (int i = 0; i < input.Length; i++)
{
tmp = (int)(Convert.ToChar(input.Substring(i, 1)));
if (tmp >= 32)
{
total += (tmp - 32) * (i + 1);
}
else
{
total += (tmp + 64) * (i + 1);
}
}
endAsc = total % 103;
if (endAsc >= 95)
{
switch (endAsc)
{
case 95:
endChar = 'Ã';
break;
case 96:
endChar = 'Ä';
break;
case 97:
endChar = 'Å';
break;
case 98:
endChar = 'Æ';
break;
case 99:
endChar = 'Ç';
break;
case 100:
endChar = 'È';
break;
case 101:
endChar = 'É';
break;
case 102:
endChar = 'Ê';
break;
}
}
else
{
endAsc += 32;
endChar = (char)endAsc;
}
return "Ì" + input + endChar.ToString() + "Î";
}
catch (Exception ex)
{
MessageBox.Show("Error");
return string.Empty;
}
}
Office 中Excel版本：
Public Function Code128b(DataToEncode As String) As String
Dim endchar As string
Dim total As Integer
total = 104
Dim tmp As Integer
dim i as integer
dim Ito as integer
Ito = Len(dataToEncode)
dim tempstring as string
dim j as integer
For i = 1 To Ito
tempstring = Mid(DataToEncode, i, 1)
tmp = AscW(tempstring)
If tmp >= 32 Then
total =total+ (tmp - 32) * i
Else
total =total+ (tmp + 64) * i
End If
Next
dim endasc as integer
endAsc = total Mod 103
If endAsc >= 95 Then
Select Case endAsc
Case 95
endchar = ChrW(195)
Case 96
endchar = ChrW(196)
Case 97
endchar = ChrW(197)
Case 98
endchar = ChrW(198)
Case 99
endchar = ChrW(199)
Case 100
endchar = ChrW(200)
Case 101
endchar = ChrW(201)
Case 102
endchar = ChrW(202)
End Select
Else
endAsc =endasc + 32
endchar = ChrW(endAsc)
End If
Code128a=ChrW(204) + DataToEncode + endchar + ChrW(206)
end function
OpenOffice版本（注：此版本只能在支持VBA的OxygenOffice中应用）：
Public Function Code128a(DataToEncode As String) As String
Dim endchar As string
Dim total As Integer
total = 104
Dim tmp As Integer
dim i as integer
dim Ito as integer
Ito = Len(DataToEncode)
dim tempstring as string
dim j as integer
For i = 1 To Ito
tempstring = Mid(DataToEncode, i, 1)
tmp = AscW(tempstring)
If tmp >= 32 Then
total =total+ (tmp - 32) * i
Else
total =total+ (tmp + 64) * i
End If
Next
dim endasc as integer
endAsc = total Mod 103
If endAsc >= 95 Then
Select Case endAsc
Case 95
endchar = "Ã"
Case 96
endchar = "Ä"
Case 97
endchar = "Å"
Case 98
endchar = "Æ"
Case 99
endchar = "Ç"
Case 100
endchar = "È"
Case 101
endchar = "É"
Case 102
endchar = "Ê"
End Select
Else
endAsc =endasc + 32
endchar = ChrW(endAsc)
End If
Code128a= "Ì" + DataToEncode + endchar + "Î"
end function