题目链接:点击打开链接
思路:求面积最小的凸多边形把所有箱子围起来, 这不就是凸包的定义吗。 模板题。
细节参见代码:
#include <cstdio> #include <cstring> #include <algorithm> #include <iostream> #include <string> #include <vector> #include <stack> #include <bitset> #include <cstdlib> #include <cmath> #include <set> #include <list> #include <deque> #include <map> #include <queue> #define Max(a,b) ((a)>(b)?(a):(b)) #define Min(a,b) ((a)<(b)?(a):(b)) using namespace std; typedef long long ll; typedef long double ld; const double eps = 1e-10; const double PI = acos(-1); const int mod = 1000000000 + 7; const int INF = 0x3f3f3f3f; const int seed = 131; const ll INF64 = ll(1e18); const int maxn = 2500; int T,n,m; struct point { double x, y; point(double x=0, double y=0):x(x), y(y) {} } p[maxn], ch[maxn]; typedef point Vector; Vector operator + (Vector A, Vector B) { return Vector(A.x+B.x, A.y+B.y); } Vector operator - (Vector A, Vector B) { return Vector(A.x-B.x, A.y-B.y); } Vector operator * (Vector A, double p) { return Vector(A.x*p, A.y*p); } Vector operator / (Vector A, double p) { return Vector(A.x/p, A.y/p); } bool operator < (const point& a, const point& b) { return a.x < b.x || (a.x == b.x && a.y < b.y); } int dcmp(double x) { if(fabs(x) < eps) return 0; else return x < 0 ? -1 : 1; } bool operator == (const point& a, const point& b) { return dcmp(a.x-b.x) == 0 && dcmp(a.y-b.y) == 0; } double cross(Vector A, Vector B) { return A.x*B.y - A.y*B.x; } double torad(double deg) { return deg / 180 * PI; } double area(point* p, int n) { double area = 0; for(int i = 1; i < n-1; i++) { area += cross(p[i]-p[0], p[i+1]-p[0]); } return area / 2; } int convexhull(point* p, int n, point* ch) { sort(p, p+n); int m = 0; for(int i = 0; i < n; i++) { while(m > 1 && cross(ch[m-1]-ch[m-2], p[i]-ch[m-2]) <= 0) m--; ch[m++] = p[i]; } int k = m; for(int i = n-2; i >= 0; i--) { while(m > k && cross(ch[m-1]-ch[m-2], p[i]-ch[m-2]) <= 0) m--; ch[m++] = p[i]; } if(n > 1) m--; return m; } Vector Rotate(Vector A, double rad) { return Vector(A.x*cos(rad)-A.y*sin(rad), A.x*sin(rad)+A.y*cos(rad)); } double x, y, w, h, j, ang; int main() { scanf("%d",&T); while(T--) { int pc = 0; double area1 = 0; scanf("%d",&n); for(int i = 0; i < n; i++) { scanf("%lf%lf%lf%lf%lf", &x, &y, &w, &h, &j); point o(x, y); ang = -torad(j); p[pc++] = o + Rotate(Vector(-w/2, -h/2), ang); p[pc++] = o + Rotate(Vector(w/2, -h/2), ang); p[pc++] = o + Rotate(Vector(-w/2, h/2), ang); p[pc++] = o + Rotate(Vector(w/2, h/2), ang); area1 += w * h; } int m = convexhull(p, pc, ch); double area2 = area(ch, m); printf("%.1f %%\n", area1 * 100 / area2); } return 0; }