Climbing

20.Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?分析：f(n)=f(n-1)+f(n-2)。方法一：看到这题目之后第一反应是用递归的方法做。/** *递归的思想做f(n)=f(n-1)
u010339647·2015-10-18 10:00

LeetCode -- Climbing Stairs

题目描述：Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?就是有n阶楼梯，求出不同上法的次数，每次只能上1或2阶楼梯。要求上楼梯的情况数，即求下楼梯的情况数，即对于n阶楼梯的下楼情况数来说
csharp25·2015-10-17 00:00

leetcode 70.Climbing Stairs-爬楼梯|动态规划

原题链接：70.ClimbingStairs【思路】题目提示动态规划。我们知道第n阶只与第n-1阶和第n-2阶有关，关系为ways[n]=ways[n-1]+ways[n-2]，存储的时候只需要2个存储单元，本题用ways[0]存n-2阶的走法数，ways[1]存储n-1阶走法数：publicclassSolution{  publicintclimbStairs(intn){    int[]w
Code_Granker·2015-10-07 13:01

Climbing Stairs | leetcode 70 【Java解题报告】

原题链接：70.ClimbingStairs【思路】题目提示动态规划。我们知道第n阶只与第n-1阶和第n-2阶有关，关系为ways[n]=ways[n-1]+ways[n-2]，存储的时候只需要2个存储单元，本题用ways[0]存n-2阶的走法数，ways[1]存储n-1阶走法数：publicclassSolution{   publicintclimbStairs(intn){     int
happyaaaaaaaaaaa·2015-10-07 13:00

hdu 5433 Xiao Ming climbing（优先队列+BFS）

题目链接问题描述小明因为受到大魔王的诅咒,被困到了一座荒无人烟的山上并无法脱离.这座山很奇怪: 这座山的底面是矩形的,而且矩形的每一小块都有一个特定的坐标(x,y)(x,y)(x,y)和一个高度HHH. 为了逃离这座山,小明必须找到大魔王,并消灭它以消除诅咒. 小明一开始有一个斗志值kkk,如果斗志为0则无法与大魔王战斗,也就意味着失败. 小明每一步都能从他现在的位置走到他的(N,E,S,W)(N
qq_26564523·2015-09-22 16:00

ES权威指南（中文版）学习_搜索_2

         "last_name" :  "Smith",         "age" :        25,         "about" :      "I love to go rock climbing
MrYx3en·2015-09-21 14:00

hdu 5433 Xiao Ming climbing （BFS+dp）

题意：小明因为受到大魔王的诅咒，被困到了一座荒无人烟的山上并无法脱离。这座山很奇怪:这座山的底面是矩形的，而且矩形的每一小块都有一个特定的坐标(x,y)和一个高度H。为了逃离这座山，小明必须找到大魔王，并消灭它以消除诅咒。小明一开始有一个斗志值k，如果斗志为0则无法与大魔王战斗，也就意味着失败。小明每一步都能从他现在的位置走到他的(N,E,S,W)四个位置中的一个,会消耗(abs(H​1​​−H​
HelloWorld10086·2015-09-16 14:00

HDU 5433 Xiao Ming climbing

ProblemDescriptionDuetothecursemadebythedevil,XiaoMingisstrandedonamountainandcanhardlyescape.Thismountainisprettystrangethatitsundersideisarectanglewhichsizeis n∗m andeverylittleparthasaspecialcoordi
jtjy568805874·2015-09-16 13:00

HDU - bc - Xiao Ming climbing (优先队列)

XiaoMingclimbingTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/65536K(Java/Others)TotalSubmission(s):853    AcceptedSubmission(s):226ProblemDescriptionDuetothecursemadebythedevil,XiaoMingisst
qq_18661257·2015-09-16 11:00

leetcode笔记：Climbing Stairs（斐波那契数列问题）

一.题目描述Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?题目的大意是，已知有n阶楼梯，每次只能爬1阶或2阶楼梯，问爬到第n阶楼梯共有几种爬法-_-||。题目可以看成是，设f(n)表示爬
liyuefeilong·2015-09-16 00:00

LeetCode----Climbing Stairs

ClimbingStairsYouareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?分析：简单的爬楼梯问题，如果这算DP题的话，那这应该是我见过的最简单DP题了。令f[i]表示到第i个楼梯时不
whiterbear·2015-09-15 23:00

HDU 5433 Xiao Ming climbing

XiaoMingclimbing问题描述小明因为受到大魔王的诅咒,被困到了一座荒无人烟的山上并无法脱离.这座山很奇怪:这座山的底面是矩形的,而且矩形的每一小块都有一个特定的坐标(x,y)(x,y)和一个高度HH.为了逃离这座山,小明必须找到大魔王,并消灭它以消除诅咒.小明一开始有一个斗志值kk,如果斗志为0则无法与大魔王战斗,也就意味着失败.小明每一步都能从他现在的位置走到他的(N,E,S,W)(
q610376681·2015-09-14 20:00

hdu2433Xiao Ming climbing

XiaoMingclimbingTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/65536K(Java/Others)TotalSubmission(s):593    AcceptedSubmission(s):155ProblemDescriptionDuetothecursemadebythedevil,XiaoMingisst
acm_fighting·2015-09-14 16:00

dp hdu5433 Xiao Ming climbing

传送门：点击打开链接题意：告诉你图，然后告诉你初始斗气，你当前的位置，终点位置，每走一步所需要的体力等于两个位置的权值之差除以当前斗气k，然后斗气减一思路：因为数据很小，所以最简单的方法当然是动态规划去做设d[i][j][k]表示当前在(i,j)且斗气为k时消耗的最小体力，然后向4个方向转移就行了#include #include #include #include #include #inclu
qwb492859377·2015-09-14 10:00

HDU 5433（Xiao Ming climbing）（费用最短路：BFS+优先队列）

昨天晚上比赛的时候被hack了，然后就wa到睡觉。。。wa的做法是每次只记录斗志允许情况下到达(x,y)的最短路，然后找到终点之后就是答案。错误的原因呢是因为poj上的一个费用最短路数据太水，让我给水过去了，没仔细考虑。一种特殊情况是：从源点S到一个点u，斗志k限制下的最短路为dis1，但是这个限制下不能从u到终点E。而从源点S到点u，斗志k限制下的另外一条路径为长度dis2(dis2>dis1)
acraz·2015-09-13 21:00

hdu5433 Xiao Ming climbing（BestCoder Round #55 ($) ）

XiaoMingclimbingTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/65536K(Java/Others)TotalSubmission(s):489AcceptedSubmission(s):120ProblemDescriptionDuetothecursemadebythedevil,XiaoMingisstrandedon
d_x_d·2015-09-13 21:00

hdu5433 Xiao Ming climbing

TimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/65536K(Java/Others)TotalSubmission(s):438    AcceptedSubmission(s):108ProblemDescriptionDuetothecursemadebythedevil,XiaoMingisstrandedonamountai
Kirito_Acmer·2015-09-13 19:00

HDU 5433 Xiao Ming climbing

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=5433题面：XiaoMingclimbingTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/65536K(Java/Others)TotalSubmission(s):404    AcceptedSubmission(s):93Probl
David_Jett·2015-09-13 16:00

hdu 5433 Xiao Ming climbing（最短路）

题目链接：hdu5433XiaoMingclimbing三维状态，x，y，k，用优先队列优化的dijkstra做一遍。#include #include #include #include #include #include usingnamespacestd; constintmaxn=55; constdoubleeps=1e-6; constdoubleinf=1e20; constint
u011328934·2015-09-12 22:00

Climbing Stairs

原题链接在这里：https://leetcode.com/problems/climbing-stairs/题目：Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop
Dylan_Java_NYC·2015-09-11 09:00

HDU 1049 Climbing Worm（水~）

Description一只蠕虫掉到了深度为n米的井中，这只蠕虫开始往上爬，一秒可以爬u米，但这只虫每爬一秒就要休息一秒，而每休息一秒就会往下掉d米，问蠕虫需要多少秒才能爬出深井Input多组用例，每组用例占一行占一行包括三个整数n,u,d，以000结束输入Output对于每组用例，输出蠕虫爬出深井用时SampleInput10212031000SampleOutput1719Solution小学数
V5ZSQ·2015-09-05 23:00

HDU 1049.Climbing Worm【水！水！水！】【8月25】

ClimbingWormProblemDescriptionAninchwormisatthebottomofawellninchesdeep.Ithasenoughenergytoclimbuincheseveryminute,butthenhastorestaminutebeforeclimbingagain.Duringtherest,itslipsdowndinches.Theproces
a995549572·2015-08-25 20:00

LeetCode（70） Climbing Stairs

题目Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?分析这个题目是一个计算n层阶梯情况下，走到顶端的路径种数（要求每次只能上1层或者2层阶梯）。这是一个动态规划的题目：n=1时ways=1
逆風的薔薇·2015-08-19 21:20

LeetCode（70） Climbing Stairs

题目Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?分析这个题目是一个计算n层阶梯情况下，走到顶端的路径种数（要求每次只能上1层或者2层阶梯）。这是一个动态规划的题目：n=1时ways=1
fly_yr·2015-08-19 21:00

hdu -1049 Climbing Worm

ClimbingWormTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):14400    AcceptedSubmission(s):9719ProblemDescriptionAninchwormisatthebottomofawellninchesdeep
wind14·2015-08-05 17:00

【LeetCode-面试算法经典-Java实现】【073-Climbing Stairs（爬楼梯）】

【073-ClimbingStairs（爬楼梯）】【LeetCode-面试算法经典-Java实现】【所有题目目录索引】原题Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?题目大意你正在爬一
derrantcm·2015-08-03 07:37

【LeetCode-面试算法经典-Java实现】【073-Climbing Stairs（爬楼梯）】

【073-ClimbingStairs（爬楼梯）】【LeetCode-面试算法经典-Java实现】【所有题目目录索引】原题Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?题目大意你正在爬一
derrantcm·2015-08-03 07:37

【LeetCode-面试算法经典-Java实现】【073-Climbing Stairs（爬楼梯）】

【073-ClimbingStairs（爬楼梯）】【LeetCode-面试算法经典-Java实现】【所有题目目录索引】原题Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?题目大意你正在爬一
DERRANTCM·2015-08-03 07:00

【LeetCode-面试算法经典-Java实现】【073-Climbing Stairs（爬楼梯）】

【073-ClimbingStairs（爬楼梯）】【LeetCode-面试算法经典-Java实现】【所有题目目录索引】原题Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?题目大意你正在爬一
DERRANTCM·2015-08-03 07:00

[leetcode 70]Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?爬台阶，你每次可以上一层或者两层，问上n层你共有多少何种方法f(n)=f(n-1)+f(n-2)动规，记得保存n-1和n-2的结果，直接
ER_Plough·2015-08-01 19:00

LeetCode#70 Climbing Stairs

Problem Definition: You are climbing a stair case. It takes n steps to reach to the top.
·2015-07-23 19:00

[LeetCode] Climbing Stairs

Note: If you feel unwilling to read the long codes, just take the idea with you. The codes are unnecessarily long due to the inconvenient handle of matrices. Well, a classic and interesting problem.
·2015-07-15 00:00

Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
hcx2013·2015-06-28 22:00

LeetCode70:Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?设到第i台阶有A[i]那么到第1台阶有A[1]=1种方法那么到第2台阶有A[2]=2种方法那么到第3台阶有A[3]=A[1]+A[2]=
u012501459·2015-06-14 23:00

Leetcode[70]-Climbing Stairs

Link:https://leetcode.com/problems/climbing-stairs/Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop
Dream_angel_Z·2015-06-14 12:00

leetcode Climbing Stairs

题目链接这里这是我第一个超时需要算法的程序。使用的是有记录的动态规划问题。publicclassSolution{ publicstaticintrecords[]; publicstaticintclimbStairs(intn){ records=newint[n+1]; Arrays.fill(records,0); for(inti=1;i<=n;i++) { process(i)
bleuesprit·2015-06-08 15:00

leetcode--Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?publicclassSolution{ publicintclimbStairs(intn){ if(n==1)return1; int[
kangaroo835127729·2015-06-05 13:00

Climbing Worm

TimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):14065    AcceptedSubmission(s):9500ProblemDescriptionAninchwormisatthebottomofawellninchesdeep.Ithasenough
l15738519366·2015-05-31 14:00

LeetCode - Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?Solution:状态转移方程：f(n)=f(n-1)+f(n-2)，等等，这不就是斐波那契数列吗？！那我们就用不着数组了。public
yuanhisn·2015-05-28 09:00

2.1.17 Climbing Stairs

Notes:Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?Solution:Climeonestepfromlaststairorclime2stepsfromthelastlastst
ZhikangFu·2015-05-12 16:00

Leetcode#70Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?分析，该问题类似于斐波那契序列问题，直观上采用递归来做，f(n)=f(n-1)+f(m-2)，然而时间复杂度太大，因此类似问题可以采用动
谧晦·2015-04-30 10:10

leetcode 70 Climbing Stairs

ClimbingStairs                     Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?HideTagsDynamicProgramming这个题面试题还
wangyaninglm·2015-04-29 17:00

Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
kainever7·2015-04-22 11:00

Leetcode - Climbing Stairs

[题目] You are climbing a stair case. It takes n steps to reach to the top.
likesky3·2015-04-10 10:00

leetcode || 70、 Climbing Stairs

problem：Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?HideTags DynamicProgramming题意：爬上一个n阶的楼梯，每次爬一阶或者两阶，求一共有多少不同的方
hustyangju·2015-04-08 10:00

【贪心专题】HDU 1049 Climbing Worm （爬井趣题）

链接：clickhere~~题意：题目大致意思是一个虫子掉在了一个n长度深的井中，然后它每分钟可以爬u长度，然后要休息一分钟，在此期间它会掉下d长度，问最终爬出井需要多久。简单模拟：代码： #include #include #include #include #include usingnamespacestd; intmain() { inta,b,c,i,j; while(~scanf("%
u013050857·2015-04-06 21:00

leetcode_Climbing Stairs

描述：Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?思路：变形的斐波那契代码：publicintclimbStairs(intn){ if(n<3) returnn; intarr[
dfb198998·2015-04-04 20:00

leetcode:Climbing Stairs

classSolution{ public: intclimbStairs(intn){ vectortable; table.push_back(0); table.push_back(1); table.push_back(2); if(n<=2) returntable[n]; for(inti=3;i<=n;i++) { table.push_back(table[i-1]+table[i
majing19921103·2015-04-03 21:00

Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?这道题其实考的就是青蛙跳台阶的问题，本质是斐波那契数列。f(n+2)=f(n)+f(n+1).C++AC代码如下：classSolution
guang09080908·2015-04-03 11:00

[leetcode]41 Climbing Stairs

题目链接：https://leetcode.com/problems/climbing-stairs/Runtimes：2ms1、问题Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop
shawjan·2015-03-31 10:00
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