Climbing

Climbing Stairs

Link:https://leetcode.com/problems/climbing-stairs/An
NNNNNNNNNNNNY·2016-05-21 17:00

LeetCode Climbing Stairs（经典动态规划）

传送门：https://leetcode.com/problems/climbing-stairs/题目大意：题意很简单易懂，有N阶楼梯，每步只能跨一阶或者两阶，问有多少种走法。
Yick is a AI·2016-05-18 14:51

Climbing Stairs 爬楼梯 解题报告

1解题思想现在需要怕一个层高为n的楼梯，每次你能爬一楼或两楼，问你有几种方式到顶楼。动态规划：当你在i楼是，你可以选择从i-1爬一步也可以从i-2爬两步，所以在到位置i的方式是爬到i-1与i-2方式只和，以此类推2原题Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.In
MebiuW·2016-05-12 23:00

LeetCode:Climbing Stairs

ClimbingStairsTotalAccepted: 107240 TotalSubmissions: 291664 Difficulty: EasyYouareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimb
itismelzp·2016-05-06 14:00

LeetCode------Climbing Stairs

题目简介Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?题目的意思就是一个数字n，你可以用1或2，总共有多少种组合方式自己的解法publicclassSolution{publicintc
Iron_Tie·2016-05-05 22:01

[Leetcode]Climbing Stairs

题意：一次只能走1级，或者2级，给你一个n级的楼梯，一共有多少种走完的方法我的算法：一开始肯定是想用递归，递归会很简答的写完，但是发现，到44这个测试样例就超时了所以得用非递归，经过前面几个题的提醒，先试试找规律1-1|2-2|3-3|4-5|5-8|6-13….斐波那契数列啊！//我选择使用递归的算法 //可以是可以，但是会超时 //所以想想非递归的算法 //发现是个斐波那契数列问题啊 //所以
qq_28057541·2016-05-04 13:00

Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?我的解答：classSolution{ public: intclimbStairs(intn){ double*map; map=newd
gdmmzmj·2016-05-02 15:00

Climbing Stairs 解题报告（Java & Python）

http://fuxuemingzhu.cn/目录题目大意题目大意解题方法递归记忆化搜索动态规划空间压缩DP日期[LeetCode]题目地址：https://leetcode.com/problems/climbing-stairs
负雪明烛·2016-05-01 16:51

【LeetCode】Climbing Stairs 解题报告

ClimbingStairs[LeetCode]https://leetcode.com/problems/climbing-stairs/TotalAccepted:106510TotalSubmissions
fuxuemingzhu·2016-05-01 16:00

41-Climbing Stairs-leetcode

ClimbingStairsMySubmissionsQuestionEditorialSolutionTotalAccepted:106498TotalSubmissions:290003Difficulty:EasyYouareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.I
justdoithai·2016-05-01 12:00

爬山演算法

爬山演算法AlgorithmHill-Climbing(pi)p=pi//設定粒子p
garfielder007·2016-04-25 19:05

HDU 1004 Toxophily

ProblemDescriptionTherecreationcenterofWHUACMTeamhasindoorbilliards,PingPang,chessandbridge,toxophily,deluxeballroomsKTVrooms,fishing,climbing
Eburs·2016-04-24 22:27

1004Toxophily

ProblemDescriptionTherecreationcenterofWHUACMTeamhasindoorbilliards,PingPang,chessandbridge,toxophily,deluxeballroomsKTVrooms,fishing,climbing
yjz_sdau·2016-04-24 15:00

专题二 1004

1004ToxophilyProblemDescriptionTherecreationcenterofWHUACMTeamhasindoorbilliards,PingPang,chessandbridge,toxophily,deluxeballroomsKTVrooms,fishing,climbing
ML_ACM·2016-04-24 10:00

Climbing Stairs

1.题目描述Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?2.解题思路非常easy的一道题目，可以很容易得到转移方程：f[i]=f[i−1]+f[i−2]3.codeclassSolut
zhyh1435589631·2016-04-22 20:00

Toxophily 物理问题

TherecreationcenterofWHUACMTeamhasindoorbilliards,PingPang,chessandbridge,toxophily,deluxeballroomsKTVrooms,fishing,climbing
mRango·2016-04-21 19:00

Toxophily

ProblemDescriptionTherecreationcenterofWHUACMTeamhasindoorbilliards,PingPang,chessandbridge,toxophily,deluxeballroomsKTVrooms,fishing,climbing
tansanity·2016-04-21 18:00

爬楼梯的问题Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?Subscribetoseewhichcompaniesaskedthisquestion=========================
JD_peterLi·2016-04-21 17:38

Leetcode - Climbing Stairs

QuestionYouareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?JavaCode//版本一:寻找递推公式，使用for循环统计不同的走法 publicintclimbStairs(intn)
roamer_nuptgczx·2016-04-18 13:00

2004

2004ProblemDescriptionTherecreationcenterofWHUACMTeamhasindoorbilliards,PingPang,chessandbridge,toxophily,deluxeballroomsKTVrooms,fishing,climbing
Kidult_·2016-04-17 15:00

Climbing Stairs

ProblemhereProblemYouareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?Solution這題之前做過就是超級樓梯那條classSolution{ public: intclim
LeongHouHeng·2016-04-17 00:00

Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?建表，查表法搞定，用递归会做重复工作，效率不高。publicstaticintclimbStairs(intn){ int[]result=
Xd_Yu·2016-04-15 23:00

Toxophily

ProblemDescriptionTherecreationcenterofWHUACMTeamhasindoorbilliards,PingPang,chessandbridge,toxophily,deluxeballroomsKTVrooms,fishing,climbing
qq_27478063·2016-04-15 18:00

Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?ClassicalDPproblemintclimbStairs(intn){ vectordp(n+1,0); dp[1]=1; dp[0
github_34333284·2016-04-12 00:00

1004

ProblemDescriptionTherecreationcenterofWHUACMTeamhasindoorbilliards,PingPang,chessandbridge,toxophily,deluxeballroomsKTVrooms,fishing,climbing
nierunjie·2016-04-11 17:00

Climbing Stairs

70.ClimbingStairsYouareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?【分析】  题意：爬一个有n级阶梯的楼梯，每一步只能上一级或者两级，问一共有多少种不同爬楼方式。  这
Jin_Kwok·2016-04-09 10:00

leetcode——70——Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop? 相当于求Fabonacci数列classSolution{ public: intclimbStairs(intn){ intstepo
happyxuma1991·2016-04-06 21:00

LeetCode之旅（16）-Climbing Stairs

题目描述：Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?先验知识：斐波那契数列斐波那契数列（Fibonaccisequence），又称黄金分割数列、因数学家列昂纳多·斐波那契（Leona
u010321471·2016-03-31 12:00

leetcod--Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?解题思路：这是一个裴波那契数列。java版本：publicclassSolution{ publicintclimbStairs(intn)
a1b2c3d4123456·2016-03-20 17:00

LeetCode-70-Climbing Stairs(动态规划)-Easy

1.题意理解每次可以上1个台阶或2个台阶，如果要上n个台阶，有多少种走法？2.题目分析：1.动态规划；2.使用递归方法会超时：climbStairs(n)=climbStairs(n-1)+climbStairs(n-2);3.使用非递归方式实现（动规要善用已计算结果）；解题代码：publicclassSolution{publicintclimbStairs(intn){if(n==0||n==
EddyLiu-csdn·2016-03-19 13:05

leetCode 70.Climbing Stairs （爬楼梯） 解题思路和方法

ClimbingStairs Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?思路：题目也比較简单。类似斐波那契。代码例如以下：publicclassSolution{ publicint
mengfanrong·2016-03-17 10:00

leetcode：Climbing Stairs 【Java】

一、问题描述Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?二、问题分析此问题实际为斐波那契数列问题。注意不能使用递归算法，会报超时错误，需要采用缓存中间结果的策略。三、算法代码代码一
tterminator·2016-03-13 21:00

HDU 1049 Climbing Worm（简单的规律题）

本题是一个简单的规律题，，题意我就不多解释了。直接给大家写上AC代码吧#include intmain() { intn,u,d; while(~scanf("%d%d%d",&n,&u,&d)) { if(n==0&&u==0&&d==0) break; intsumtime=0,sum=0; while(1) { sum+=u; if(sum>=n) break; elsesum-=d; s
qq_32866009·2016-03-11 21:00

HDU 5433 Xiao Ming climbing 动态规划

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=5433XiaoMingclimbingTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/65536K(Java/Others)TotalSubmission(s):1346    AcceptedSubmission(s):384Proble
fenicnn·2016-03-10 15:00

Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?【思路】斐波那契数列，第n阶是由第n-1阶和n-2阶的方法求和而成。classSolution{ public: intclimbSta
qq_27991659·2016-03-09 14:00

70 - Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?Subscribe toseewhichcompaniesaskedthisquestion思路分析：利用DP的方法，一个台阶的方法次数
hellochenlu·2016-03-08 11:00

Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?利用递归的思想：逆向思想。如果你想上到第n个台阶，有几种可能？答案是，2种可能：从（n-1）号台阶跨一阶上来，或是，从（n-2）号台阶一步跨
Dustin_CDS·2016-03-07 18:00

Climbing Stairs

70.ClimbingStairsMySubmissionsQuestionTotalAccepted: 96079 TotalSubmissions: 265268 Difficulty: EasyYouareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmany
Dr_Unknown·2016-03-01 11:00

Climbing Stairs [Difficulty: Easy]

题目：Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?翻译：你在爬一个楼梯。到达顶部有n级阶梯。每次你可以选择爬一级或者二级。在多少不同的方式去到达顶部？分析：当n=1，无疑只有一种方式，
Lnho2015·2016-02-27 17:00

Climbing Stairs [Difficulty: Easy]

题目：Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?翻译：你在爬一个楼梯。到达顶部有n级阶梯。每次你可以选择爬一级或者二级。在多少不同的方式去到达顶部？分析：当n=1，无疑只有一种方式，
Lnho2015·2016-02-27 17:00

leetcode Climbing Stairs

classSolution{ public: intclimbStairs(intn){ if(n==0)return0; if(n==1)return1; if(n==2)return2; intprepre=1; intpre=2; intcur=0; for(inti=3;i<=n;i++){ cur=prepre+pre; prepre=pre; pre=cur; } returncur
wait_never·2016-02-14 11:00

Climbing Stairs

只能用1、2相加得到n，求有几种加法。ver0：递归，意料之中的TLE1classSolution{ 2public: 3intclimbStairs(intn){ 4if(n==1)return1; 5if(n==2)return2; 6returnclimbStairs(n-1)+climbStairs(n-2); 7} 8};ver1：略加修改1classSolution{
co0oder·2016-02-13 22:00

HDU 5433 Xiao Ming climbing（BFS）

XiaoMingclimbingTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/65536K(Java/Others)TotalSubmission(s):1227    AcceptedSubmission(s):344ProblemDescriptionDuetothecursemadebythedevil,XiaoMingiss
aozil_yang·2016-02-04 18:00

Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?动态规划考虑第n步分为两种情况，即第n-1步+1步或者n-2步+2步，所以f[n]=f[n-1]+f[n-2]classSolution{
偏爱纯白色·2016-02-02 11:00

Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?爬楼梯的问题，思路和UniquePaths问题类似。我们假设到了第i个台阶，因为每次只能走一步和两步，因此到第i个台阶的方式等于到第i-1个
KickCode·2016-02-02 09:23

Climbing Stairs

这题是简单的动态规划问题classSolution{ public: intclimbStairs(intn){ //动态规划s[n]=s[n-1]+s[n-2] if(n<=2)returnn; ints[n]={0},i=2; s[0]=1; s[1]=2; while(i
xl2432·2016-01-27 20:00

leetcode70-Climbing Stairs(斐波那契数列)

问题描述：Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?问题求解：设ways[n]表示登完n个台阶的方法。考虑最后一步：（1）登一个阶梯。ways[n]=ways[n-1]（2）登2个阶
will130·2016-01-27 16:00

LeetCode Climbing Stairs

LeetCode解题之ClimbingStairs原题一共有n级楼梯，每次能够爬一级或两级，共有多少种不同的爬法爬到顶端。注意点：无例子：输入:n=6输出:13解题思路典型的动态规划题，递推表达式为dp[i]=dp[i-1]+dp[i-2]，n为1时只有一种方法，n为2时有两种方法。AC源码classSolution(object): defclimbStairs(self,n): """:typ
u013291394·2016-01-19 20:00

LeetCode 70 Climbing Stairs（爬楼梯）（动态规划）（*）

翻译你正在爬一个楼梯。它需要n步才能到底顶部。每次你可以爬1步或者2两步。那么你有多少种不同的方法爬到顶部呢？原文Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?分析动态规划基础题，首先设
nomasp·2016-01-14 07:13

LeetCode 70 Climbing Stairs（爬楼梯）（动态规划）（*）

翻译你正在爬一个楼梯。它需要n步才能到底顶部。 每次你可以爬1步或者2两步。 那么你有多少种不同的方法爬到顶部呢？原文Youareclimbingastaircase.Ittakesnstepstoreachtothetop. Eachtimeyoucaneitherclimb1or2steps. Inhowmanydistinctwayscanyouclimbtothetop?分析动态规
NoMasp·2016-01-14 07:00
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