Climbing

LeetCode之Climbing Stairs与斐波那契数列的联想

题目：Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?看到题目之后，毫不犹豫想出公式：f(n)=f(n-1)+f(n-2)，明显用动态规划算法，而且巧合的是，这公式跟斐波那契数列一模一
xanxus46·2016-01-03 21:00

HDOJ 1049-Climbing Worm【数学】

ClimbingWormTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):15450    AcceptedSubmission(s):10488ProblemDescriptionAninchwormisatthebottomofawellninchesd
qq_29600137·2015-12-29 17:00

Climbing Stairs 解题报告

题目链接：https://leetcode.com/problems/climbing-stairs/Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop
qq508618087·2015-12-22 05:00

[leetcode]Climbing Stairs

题目描述如下：Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?简单的动归题，上n节台阶可以分为上n-2个台阶，然后2步直接上最后一步；或者上n-1个台阶，再单独上一步。则动归方程如下：re
u012505618·2015-12-19 20:00

Climbing Stairs

70.ClimbingStairsMySubmissionsQuestionTotalAccepted:88315TotalSubmissions:246989Difficulty:EasyYouareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinc
EbowTang·2015-12-16 20:26

Climbing Stairs

70.ClimbingStairsMySubmissionsQuestionTotalAccepted: 88315 TotalSubmissions: 246989 Difficulty: EasyYouareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmany
EbowTang·2015-12-16 20:00

Climbing Stairs

70.ClimbingStairsMySubmissionsQuestionTotalAccepted: 88315 TotalSubmissions: 246989 Difficulty: EasyYouareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmany
EbowTang·2015-12-16 20:00

【Leetcode】Climbing Stairs

题目链接：https://leetcode.com/problems/climbing-stairs/题目：Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop
yeqiuzs·2015-12-15 11:00

LeetCode 70:Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?//设f(n)表示爬n阶楼梯的不同方法，有两种选择： //1.从第n-1阶，前进1步到达第n阶； //2.从第n-2阶，前进2步到达第n
geekmanong·2015-12-11 16:00

leetcode -- Climbing Stairs -- 简单重要

https://leetcode.com/problems/climbing-stairs/简单的dp思路d[n]=d[n-1]+d[n-2]classSolution(object): defclimbStairs
xyqzki·2015-12-08 23:00

Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?classSolution{ public: intclimbStairs(intn){ if(n==0||n==1) return1;
qq_18343569·2015-12-03 17:00

HDOJ 5433 Xiao Ming climbing (BFS+三维标记)

XiaoMingclimbingTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:65536/65536K(Java/Others)TotalSubmission(s):1139    AcceptedSubmission(s):305ProblemDescriptionDuetothecursemadebythedevil,XiaoMingiss
helloiamclh·2015-12-03 09:00

【LEETCODE】70-Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?http://www.zhihu.com/question/23995189什么是动态规划？动态规划的意义是什么？动态规划的本质，是对问题状
aliceyangxi1987·2015-11-30 19:00

《leetCode》：Climbing Stairs

题目Youareclimbingastaircase.Ittakesnstepstoreachtothetop. Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?题目大意：每步只能爬一个或者是两个台阶，爬到顶端n个台阶有多少中方法？思路利用DP的方法，一个台阶的方法次数为1次，两个台阶的方法次
u010412719·2015-11-29 17:00

Climbing Stairs

问题描述Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?算法有n阶，第一次迈一阶，剩余的跟n-1的次数相同，或者第一次迈2阶，剩余的跟n-2的次数相同。斐波那契数列。代码一：1publ
qiaoshanzi·2015-11-26 15:00

[HDU 2312]Cliff Climbing[BFS]

题目链接：[HDU2312]CliffClimbing[BFS]题意分析：杰克可以从为'S'的点用任意一只脚向上爬，规定左脚爬完得用右脚，问：到达'T'的点需要的最少时间为多少？解题思路：从'S‘的点开始，向左右两边进行搜索。dis[i][j][2]代表，某只脚到达该点需要的最少时间，转移为dis[i][j][1-sta]=min(dis[i][j][1-sta],dis[i][j][sta]+t
CatGlory·2015-11-21 10:00

LeetCode 刷题： Climbing Stairs --- 类似于Fibonacci 数列

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?这道题目类似于Fibonacci数列。解法有两种，一种是递归，一种是非递归：非递归：classSolution{ public: int
guilanl·2015-11-20 23:00

Climbing Stairs

问题：上楼每次能走一步或两步，有多少种走法 class Solution { public: int a[1000]; int dfs(int n) { if(n<0) return 0; if(n==0) return 1; if(a[n]) return a[n]; return
·2015-11-13 15:29

leetcode------Climbing Stairs

标题： Climbing Stairs 通过率： 34% 难度： 简单 You are climbing a stair case.
·2015-11-13 15:19

【BZOJ】1665: [Usaco2006 Open]The Climbing Wall 攀岩（spfa）

http://www.lydsy.com/JudgeOnline/problem.php?id=1665 这题只要注意到“所有的落脚点至少相距300”就可以大胆的暴力了。 对于每个点，我们枚举比他的x轴小1000内和大1000内的点连边，然后直接暴力出奇迹。 #include <cstdio> #include <cstring> #include <cm
·2015-11-13 11:02

LeetCode: Climbing Stairs

一开始用dfs结果large超时，马上就想到dp了。。哎，下次先得去想dp啊。。 1 class Solution { 2 public: 3 int climbStairs(int n) { 4 // Start typing your C/C++ solution below 5 // DO NOT write int main()
·2015-11-13 10:49

leetcode[68] Climbing Stairs

n个台阶，每次可以走一步或者两步，总共有多少种走法。 第一感觉想到的是递归，n为1的时候1种，2的时候2中。其他时候就是 fun(n) = fun(n-1) + fun(n-2);递归的代码很简单。如下 class Solution { public: int climbStairs(int n) { if (n == 0) return 0;
·2015-11-13 08:14

LeetCode Online Judge 题目C# 练习 - Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-13 08:43

[LeetCode]Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-13 07:44

大白话解析模拟退火算法

爬山算法 ( Hill Climbing )          介绍模拟退火前，先介绍爬山算法。
·2015-11-13 05:01

BZOJ 1665: [Usaco2006 Open]The Climbing Wall 攀岩

题目 1665: [Usaco2006 Open]The Climbing Wall 攀岩 Time Limit: 5 Sec  Memory Limit: 
·2015-11-13 03:45

Climbing Stairs

题目： You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-13 03:57

[LeetCode#]Climbing Stairs

The problem: You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-13 01:52

LeetCode_Climbing Stairs

1 class Solution { 2 public: 3 int climbStairs(int n) { 4 // Start typing your C/C++ solution below 5 // DO NOT write int main() function 6 if(n ==0) return 0;
·2015-11-12 23:16

leetcode_question_70 Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-12 21:21

HDU 1049 Climbing Worm

#include <cstdio> int main() { int cnt,h,d,u; while(scanf("%d%d%d",&h,&d,&u)!=EOF) if (h!=0) { cnt=0; cnt+=(2*((h-d)/(d-u)));
·2015-11-12 20:25

Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-12 17:50

LeetCode_Climbing Stairs

ou are climbing a stair case. It takes n steps to reach to the top.
·2015-11-12 16:44

Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-12 16:24

Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-12 14:27

[leetcode]Climbing Stairs

class Solution { public: int climbStairs(int n) { // Start typing your C/C++ solution below // DO NOT write int main() function if(n <= 2) return n;
·2015-11-12 11:51

【LeetCode练习题】Climbing Stairs

Climbing Stairs You are climbing a stair case.
·2015-11-12 11:58

GRUB4DOS中文自述文档;Grub4dos中文ReadMe

中文自述文档 版本：0.4.4-2009-03-18英文版作者：tinybit ([email protected])中文版译者：zw2312914([email protected])在线文档创建者：Climbing
·2015-11-12 08:08

大白话解析模拟退火算法

爬山算法 ( Hill Climbing )          介绍模拟退火前，先介绍爬山算法。
·2015-11-11 19:29

hdu 4315 Climbing the Hill（阶梯博弈转nim博弈）

Climbing the Hill Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768
·2015-11-11 19:22

HDUOJ-----Climbing Worm

Climbing Worm Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768
·2015-11-11 19:05

Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-11 18:40

Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-11 15:51

[LeetCode OJ]-Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-11 12:08

Climbing Stairs

Question: You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-11 10:11

LeetCode 70 Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-11 03:02

Climbing Stairs - Print Path

stair climbing， print out all of possible solutions of the methods to climb a stars, you are allowed
·2015-11-11 01:11

Leetcode: Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-11 01:37

[leetcode]Climbing Stairs

秒杀，斐波那契数列。而且，其实不用像我的答案那也开数组的，用几个变量存就行了。 public class Solution { public int climbStairs(int n) { // Start typing your Java solution below // DO NOT write main() function
·2015-11-10 21:52

[LeetCode] Climbing Stairs （Sequence DP）

Climbing Stairs https://oj.leetcode.com/problems/climbing-stairs/ You are climbing a stair case
·2015-11-09 14:36
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