Climbing

Climbing Stairs

    爬楼梯，就是斐波纳契数列。 // f(n) = f(n - 1) + f(n - 2). // f(1) = 1. // f(2) = 2. int climbStairs(int n) { int a = 1, b = 2; int c = 0; if (n == 1) return
·2015-11-09 12:22

HDU 2298 Toxophily

has indoor billiards, Ping Pang, chess and bridge, toxophily, deluxe ballrooms KTV rooms, fishing, climbing
·2015-11-08 15:56

3月3日(6) Climbing Stairs

原题 Climbing Stairs 求斐波那契数列的第N项，开始想用通项公式求解，其实一个O(n)就搞定了。
·2015-11-08 14:09

CDZSC_2015寒假新人（1）——基础 f

It has enough energy to climb u inches every minute, but then has to rest a minute before climbing again
·2015-11-08 11:45

Climbing Stairs

Climbing Stairs You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-08 11:37

Leetcode#70 Climbing Stairs

原题地址   基本动归题 可以压缩状态空间   代码： 1 int climbStairs(int n) { 2 if (n <= 0) 3 return 0; 4 5 int count = 1; 6 int tmp = 1; 7
·2015-11-08 10:01

Climbing Stairs

https://oj.leetcode.com/problems/climbing-stairs/ You are climbing a stair case.
·2015-11-08 09:50

HDU-1049

It has enough energy to climb u inches every minute, but then has to rest a minute before climbing again
·2015-11-07 14:42

hdu 4315 Climbing the Hill 博弈论

题意：有n个人爬山，山顶坐标为0，其他人按升序给出，不同的坐标只能容纳一个人（山顶不限），Alice和Bob轮流选择一个人让他移动任意步，但不能越过前面的人，且不能和前面一个人在相同的位置。现在有一个人是king，给出king是哪个人（id），谁能将国王移动到山顶谁胜。   解题思路：先考虑简化版，没有king，谁先不能移动谁输掉。和阶梯博弈类似http://blog.csdn.ne
·2015-11-07 14:30

模拟退火算法

爬山算法 ( Hill Climbing )          介绍模拟退火前，先介绍爬山算法。
·2015-11-07 10:26

Climbing Stairs

Climbing Stairs  问题： You are climbing a stair case.
·2015-11-03 21:26

Hdu 1049 Climbing Worm

CODE: #include <stdio.h> #include <stdlib.h> #include < string.h> #include <algorithm> using  namespace std; int n, u, 
·2015-11-02 18:02

【leetcode】Climbing Stairs

题目简述： You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-02 17:15

[LeetCode]Climbing Stairs

称号：给定一个int整数类型n，它代表了楼梯的阶。每一个可能的步骤时，楼梯，有可能采取两个步骤，求完成n楼梯有多少种不同的方法 算法：递归是最简单的方法，但超时。递归转换的递推公式：f(n) = f(n-1)+f(n-2) public class Solution { public int climbStairs(int n) { final int STAIRS = 50
·2015-11-02 16:31

大白话解析模拟退火算法

爬山算法 ( Hill Climbing )          介绍模拟退火前，先介绍爬山算法。
·2015-11-02 15:27

[LeetCode] Climbing Stairs 斐波那契数列

You are climbing a stair case. It takes n steps to reach to the top.
·2015-11-01 14:04

模拟退火算法

爬山算法 ( Hill Climbing )          介绍模拟退火前，先介绍爬山算法。
·2015-11-01 10:20

Codeforces Round #283 (Div. 2) A. Minimum Difficulty 暴力水题

per test 256 megabytes input standard input output standard output Mike is trying rock climbing
·2015-11-01 09:58

[置顶] hdu 1049 Climbing Worm

ProblemDescriptionAninchwormisatthebottomofawellninchesdeep.Ithasenoughenergytoclimbuincheseveryminute,butthenhastorestaminutebeforeclimbingagain.Duringtherest,itslipsdowndinches.Theprocessofclimbinga
wind_2008_06_29·2015-10-31 22:00

leetcode Climbing Stairs python

Climbing Stairs You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-31 16:27

Leetcode_num13_Climbing Stairs

称号： You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-31 13:50

Climbing Stairs

public class Solution { public int climbStairs(int n) { int[] res =new int[n+3]; // 因为如果n<3,至少希望把前三个位置做出来 res[0] = 0; res[1] =1; res[2] = 2; if(n
·2015-10-31 12:15

Climbing Stairs

Description: You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-31 12:47

（HDOJ 1049）Climbing Worm

 Climbing Worm Problem Description An inch worm is at the bottom of a well n inches deep.
·2015-10-31 11:37

BZOJ1665 : [Usaco2006 Open]The Climbing Wall 攀岩

直接BFS貌似复杂度飞起来了，于是我们用k-d tree优化找点的过程即可。时间复杂度$O(n\sqrt{n})$。   #include<cstdio> #include<algorithm> const int N=10010,H=1000,R=1000000; int n,m,i,root,cmp_d,h=1,t,q[N],f[N],mx,my,
·2015-10-31 11:52

leetcode[70]Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-31 11:30

杭电1049

17  *    作者：SJF  *    题号：杭电1049  *    题目：Climbing
·2015-10-31 11:53

【leetcode】Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-31 10:37

【LeetCode】70 - Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-31 10:19

LeetCode --- Climbing Stairs

题目链接 简单递推 附上代码： 1 class Solution { 2 public: 3 int climbStairs(int n) { 4 int f0 = 1, f1 = 1, f2 = 1; 5 for (int i = 2; i <= n; i++) { 6 f2 = f0 + f1; 7
·2015-10-31 09:28

HDU 1049 Climbing Worm（水题）

Climbing Worm Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768
·2015-10-31 09:14

[Leetcode] Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-30 14:09

LeetCode - Climbing Stairs

Climbing Stairs 2013.12.22 04:13 You are climbing a stair case.
·2015-10-30 13:00

leetcode_70题——Climbing Stairs（简单DP题）

Climbing Stairs   Total Accepted: 54579 Total Submissions: 158996 My Submissions
·2015-10-30 13:03

LeetCode Climbing Stairs 爬楼梯

  递归法（TLE代码）： 1 class Solution { 2 public: 3 int climbStairs(int n) { 4 if(n==0) 5 return 1; 6 if(n<0) 7 return 0; 8 retur
·2015-10-30 13:01

模拟退火算法

爬山算法 ( Hill Climbing )       作为对比，先介绍爬山算法。
·2015-10-30 12:22

模拟退火算法

爬山算法 ( Hill Climbing )          介绍模拟退火前，先介绍爬山算法。
·2015-10-30 11:32

LeetCode:Climbing Stairs

问题描述：Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?Subscribe toseewhichcompaniesaskedthisquestion思路：这道题是一道老题目改变而来，
u014744118·2015-10-29 09:00

大白话解析模拟退火算法

爬山算法 ( Hill Climbing )          介绍模拟退火前，先介绍爬山算法。
·2015-10-28 08:04

Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-28 08:10

Codeforces Round #283 (Div. 2) 题解

Minimum Difficulty   Mike is trying rock climbing but he is awful at it.
·2015-10-28 08:53

LeetCode Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-27 16:53

【leetcode】Climbing Stairs (easy)

You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-27 15:28

[LeetCode] Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-27 15:47

Climbing Stairs 爬楼梯问题，每次可以走1或2步，爬上n层楼梯总方法 （变相fibonacci）

You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-23 08:48

[Leetcode] Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?题意：台阶总数为n，每次爬1阶或者2阶层，求爬完台阶的不同的方法数。第一次爬1阶，则剩下n-1阶；第一次爬2阶，则剩下n-2阶；递推表达式为
Javasus·2015-10-21 18:10

Leetcode:Climbing Stairs 斐波那契数

戳我去解题 You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-21 13:01

[leedcode 70] Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top.
·2015-10-21 12:37

ZOJ-3103 Cliff Climbing 最短路

题意：从若干个S点出发到达T点，稍有不同的是，要区分该点落脚有左脚和右脚两种情况。 解法：从题目中给定的S出发，左脚和右脚都可以踏上去，全部入队列后再spfa即可。做了这题发现使用spfa来处理多源点时连超级源点都不用建立了。 代码如下： #include <iostream> #include <cstring> #include <cstdlib>
·2015-10-21 11:55

hdu1049--Climbing Worm

由于输入数据规模不大，用简单模拟即可 代码如下：   #include<stdio.h> int main() {     int d,u,n,x,time;     while(scanf("%d %d %d",&n,&u,&d),n)   &
·2015-10-20 08:10
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