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Constructing
杭电ACM1102——
Constructing
Roads
这题,简单的最小生成树的应用,只是输入的方式比较特殊。还会告诉你哪一些村庄是已经有路的。输入的第一个数n,是村庄的数目,然后下面n*n个数代表的是:第i行第j个就是村庄i和j之间的距离。理解了这个,就很容易写出代码了。使用并查集避免形成环。下面是AC的代码:#include#include#includeusingnamespacestd;classdata//两个村庄直接的数据,也就是距离{pu
XD灬
·
2020-08-13 16:50
杭电
acm
杭电
kruskal
Hdu 1102
Constructing
Roads【最小生成树】
ConstructingRoadsTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):17176AcceptedSubmission(s):6524ProblemDescriptionThereareNvillages,whicharenumberedfrom1toN,a
hope1262946533
·
2020-08-13 15:58
生成树&&树形图
POJ 2421
Constructing
Roads 最小生成树 kruscal+并查集
ConstructingRoadsTimeLimit:2000MSMemoryLimit:65536KTotalSubmissions:18604Accepted:7683DescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnect
kdwycz
·
2020-08-13 15:07
【OJ】graph—图论
poj 2421
Constructing
Roads 并查集+最小生成树
DescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthe
joafelnglfds
·
2020-08-13 14:29
图论
HDOJ-1102
Constructing
Roads(最小生成树)两种做法
题目最小生成树Kruskal算法/*HDU1102ConstructingRoads题意:有n个乡村,修路,然后保证每两条路之间连接。如果A和B连接,那么A和B直接连接或者中间还有一个乡村,间接连接。已经有一些路了,你的任务是找出来一路径连接所有乡村。输入:i到j的长度,注意去重边最小生成树,,,*/#include#include#includeusingnamespacestd;constin
huatian5
·
2020-08-13 14:24
图论
数据结构
MST
Kruskal算法
Prim
Constructing
Roads
ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthereexistsavi
韩小妹
·
2020-08-13 14:23
图论
poj 2421
Constructing
Roads
ConstructingRoadsTimeLimit:2000MSMemoryLimit:65536KTotalSubmissions:22865Accepted:9784DescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnect
我要吃熊猫
·
2020-08-13 13:42
最小生成树
poj 2421
Constructing
Roads(最小生成树)
ConstructingRoadsTimeLimit:2000MSMemoryLimit:65536KTotalSubmissions:22124Accepted:9431DescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnect
acm_cxq
·
2020-08-13 12:36
最小生成树
杭电Hdu 1102
Constructing
Roads
这道题也是一道经典最小生成树的题目,用的prim算法。贵在会方法,并且能准确读懂题,我就读了好久,我犹豫的地方比方说:城镇B,C之间相连有一条路,如果城镇A可以通向C,那它也能通向B。开始我把它理解成了,A必须连着B,之间有条路;也必须连着C,之间有条路,其实不是这样。A通向B或C任何一个城镇就相当于也通向了另一个城镇。这才是最小生成树的意思吗,下面就好弄了。还有一个地方,就是正在建设的路,那不属
FsnailWang
·
2020-08-13 12:21
最小生成树
D -
Constructing
Roads POJ - 2421
D-ConstructingRoadsPOJ-2421ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbe
风中一颗松
·
2020-08-13 11:08
最小生成树
POJ2421
Constructing
Roads(最小生成树)
题意:村庄之间连通,要求输出最小权值和,注意有些村庄已经连通要点:Prim算法稍微变一下,因为是求权值和,已经连通的之间权值改为0即可,反正为0后面算的时候肯定是最小值,会加入集合的,然后权值又是0不影响。15347342Seasonal2421Accepted208K32MSC++826B2016-04-0314:36:19#include#include#includeintmap[105][
weixin_34208185
·
2020-08-13 11:48
杭电 hdu 1102
Constructing
Roads (最小生成树)
杭电hdu1102ConstructingRoads(最小生成树)ConstructingRoadsTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):16548AcceptedSubmission(s):6297ProblemDescriptionThereareNvi
thestarfish
·
2020-08-13 10:20
并查集
最小生成树
HDU 1102
Constructing
Roads
思想:简单最小生成树,kruskal。结构体数组的范围一定要注意不要开小了,因为这个问题时间超限n次,还找不出来o(╯□╰)o,还有就是注意一些细节问题。#include#include#include#include#include#includeusingnamespacestd;intper[105];voidinit(){for(inti=0;i<105;i++){per[i]=i;}}s
qq_38235087
·
2020-08-13 10:55
acm
图论
D -
Constructing
Roads
ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthereexistsavi
囧九
·
2020-08-13 10:08
并查集和最小生成树
hdu 1102
Constructing
Roads
ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthereexistsavi
zuhiul
·
2020-08-13 10:11
hdu
最小生成树
HDOJ 1102
Constructing
Roads(最小生成树)
ConstructingRoadsTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):6455AcceptedSubmission(s):2377ProblemDescriptionThereareNvillages,whicharenumberedfrom1toN,an
御史大夫
·
2020-08-13 10:07
HOJ 1102
Constructing
Roads(最小生成树)
数据量不大,直接暴力过。我用了Prime,过程写在注释中。#include#include#include#pragmawarning(disable:4996)usingnamespacestd;constintNN=100+5,INF=99999999;inta[NN][NN],f[NN];intfind(intx){//找到根节点if(x==f[x])returnx;f[x]=find(f[
qq_44724908
·
2020-08-13 10:09
hdu1102
Constructing
Roads
ConstructingRoadsTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):12166AcceptedSubmission(s):4621ProblemDescriptionThereareNvillages,whicharenumberedfrom1toN,a
u010793761
·
2020-08-11 13:35
ACM--题目
Exploring Branch Predictors for
Constructing
Transient Execution Trojans
ExploringBranchPredictorsforConstructingTransientExecutionTrojans(木马)1.摘要:针对于幽灵攻击,工业界迅速采取了一系列软件和硬件上的缓解措施,其中微码补丁最为流行和受信任(microcodepatch)问题:现有的防护策略仍旧存在被攻击的漏洞论文工作:提出了暂态木马(transienttrojans),即一种软件模块会在暂态执行模
shuiliusheng
·
2020-08-10 07:53
computer
architecture
【论文阅读】Utilizing BERT for Aspect-Based Sentiment Analysis via
Constructing
Auxiliary Sentence
UtilizingBERTforAspect-BasedSentimentAnalysisviaConstructingAuxiliarySentence这篇论文主要是通过用aspect构造辅助句子,将ABSA问题转成sentence-pair分类任务,模型就是用了bert,然后再sentihood和semeval2014task4上都取得了很好的结果简介这篇文章的问题领域是TABSA:aspec
BeforeEasy
·
2020-08-09 18:23
论文
NLP
hdu
Constructing
Roads(最小生成树,kuskal算法)
ConstructingRoadsTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):14569AcceptedSubmission(s):5530ProblemDescriptionThereareNvillages,whicharenumberedfrom1toN,a
itcoder-9527
·
2020-08-09 06:15
HDOJ1102
Constructing
Roads【最小生成树】-----武科大ACM暑期集训队选拔赛1题
这道题目没有做出来,代码写好之后一直没有AC,本以为做了这么多最小生成树的题目,这道题一定没问题的,结果很遗憾,没有注意细节问题:首先,如何处理已经建好的路?已经建好的路说明这两个点是连通的,只要把他们间距设为0就好了。其次,注意循环的控制,我把第一个for中的i=1写成i=0了。Problem:1102(ConstructingRoads)JudgeStatus:AcceptedRunId:59
weixin_33915554
·
2020-08-04 05:16
POJ--2421--
Constructing
Roads【最小生成树】
链接:http://poj.org/problem?id=2421题意:n个村庄,告诉你任两个村庄间距离,要建一些路使得任两个村庄都可以互相到达,需要使花费最小,其中有q条路已经建了,求最小花费。把已经建的路的权值改为0,再prim就行了。kruskal做的话,把建好的路用并查集合并,再kruskal就行了prim算法#include#include#include#include#include
altair21
·
2020-08-03 10:25
最小生成树MST
POJ代码
Poj-2421
Constructing
Roads
[题目链接]题意:N个村庄要实现村村通,Q个村已经相通了,求剩下的村庄要实现村村通的最小花费。思路:相通的村庄距离置为0,跑一边最小生成树就好啦。Prim算法VSKruskal算法(感觉后者既好写,效率又高)Prim算法:#include#include#include#includeusingnamespacestd;constintinf=0x3f3f3f3f;constintMax_v=11
zzti_xiaowei
·
2020-08-03 09:53
Acm--图论
最小生成树
poj2421
Constructing
Roads
描述:有n个村庄,编号为1,2,3,,,n应该建造道路使他们互相可达对输入数据3099069299001796921790112意思有3个村庄,099069299001796921790意思是1号到1,2,3的距离分别为0990692112意思是有一条道路已经接通,就是1号与2号间的道路解法:kruskal算法,建造最小生成树即可#include#include#includeusingnames
zhangwei1120112119
·
2020-08-03 09:26
最小生成树
poj2421
Constructing
Roads-最小生成树prim
ConstructingRoadsTimeLimit:2000MSMemoryLimit:65536KTotalSubmissions:16680Accepted:6806DescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnect
蒝味
·
2020-08-03 09:50
030-图论
POJ 2421
Constructing
Roads
注意:prime算法求最小生成树算法要非常熟练时间限制:2000ms内存限制:65536kB描述ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifan
youyang1991
·
2020-08-03 09:02
ACM刷题之HDU————
Constructing
Roads
ConstructingRoadsTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):22339AcceptedSubmission(s):8591ProblemDescriptionThereareNvillages,whicharenumberedfrom1toN,a
小时的枫
·
2020-08-03 08:22
ACM题目
最小生成树
数据结构
H -
Constructing
Roads
点击打开链接ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthereexi
星星的泪痕
·
2020-08-03 08:28
最小生成树
Constructing
Roads
TimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):17231AcceptedSubmission(s):6547ProblemDescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuilds
wind囡囝
·
2020-08-03 08:14
acm程序
Kruskal
查并集
hdu
oj
POJ - 2421
Constructing
Roads (最小生成树)
ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthereexistsavi
是奥利奥阿
·
2020-08-03 08:23
水题之路
Constructing
Roads
ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthereexistsavi
weixin_33834137
·
2020-08-03 06:04
POJ-2421-
Constructing
Roads
链接:https://vjudge.net/problem/POJ-2421#author=tsacm123题意:有N个村庄,从1到N,你应该修建一些道路,这样每两个村庄就可以连接起来。我们说两个村庄A和B相连,当且仅当A和B之间有一条路,或者存在一个村庄C使得A和C之间有一条路,并且C和B相连。我们知道一些村庄之间已经有一些道路了,你的工作是修建一些道路,这样所有的村庄都连接起来,所有道路的长度
weixin_33695082
·
2020-08-03 06:03
POJ - 2421
Constructing
Roads (最小生成树)
ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthereexistsavi
weixin_30872499
·
2020-08-03 06:14
POJ 2421
Constructing
Roads 最小生成树
来源:http://poj.org/problem?id=2421题意:还是给你n个点,然后求最小生成树。特殊之处在于有一些点之间已经连上了边。思路:对于已经有边的点,特殊标记一下,加边的时候把这些边的权值赋值为0即可。这样就可以既保证这些边一定存在,又保证了所求的结果正确。代码:#include#include#include#include#includeusingnamespacestd;#
weixin_30329623
·
2020-08-03 06:29
HDU - 1102 -
Constructing
Roads (最小生成树--prim算法!!)
ConstructingRoadsTimeLimit:2000/1000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):14890AcceptedSubmission(s):5674ProblemDescriptionThereareNvillages,whicharenumberedfrom1toN,a
zzuspy
·
2020-08-03 05:53
~~~~~~~~~~图论
生成树
~~~~~~~~~~数据结构
HDU
POJ 2421
Constructing
Roads(简单最小生成树)
POJ2421ConstructingRoads(简单最小生成树)http://poj.org/problem?id=2421题意:有N个点的无向图,给了你该图的距离矩阵.且其中一些点已经连接起来了,现在要你求让该无向图连通,你需要添加边的总长度最少是多少?分析:将已经连通的边看成是长度为0的边,然后用Kruskal算法处理即可.完全图,一定存在最小生成树.AC代码:#include#includ
focus_best
·
2020-08-03 05:08
ACM--题解汇总
★★
图论--最小生成树
practice
again
poj 2421
Constructing
Roads
题目链接:http://poj.org/problem?id=2421题目思路:这道题很简单,就是把给出的已有的道路之间的值换为零就可以了AC代码:#include#defineinf0xfffffffintmap[105][105],n;voiddisjka(){intcur=1,next,i,j,m=n;intvis[105]={0},dis[105];for(i=1;i<=n;i++)dis
黑山老猴妖
·
2020-08-03 05:55
poj 2421
Constructing
Roads(最小生成树 kruskal算法)
ConstructingRoadshttp://poj.org/problem?id=2421TimeLimit:2000MSMemoryLimit:65536KTotalSubmissions:19457Accepted:8103DescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuch
defense881
·
2020-08-03 05:24
poj
ACM_图论
图
ACM之解题报告
POJ-2421
Constructing
Roads
ConstructingRoadsTimeLimit:2000MSMemoryLimit:65536KDescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBare
J_Sure
·
2020-08-03 05:20
Prim
ACM-POJ
I -
Constructing
Roads
DescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthe
不满de奶瓶
·
2020-08-03 05:47
并查集
最小生成树
D -
Constructing
Roads
ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthereexistsavi
曾經的過去
·
2020-08-03 04:13
POJ 2421
Constructing
Roads(最小生成树,边已经存在的处理方法)
ConstructingRoadsTimeLimit:2000MSMemoryLimit:65536KTotalSubmissions:22483Accepted:9606DescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnect
Shyazhut
·
2020-08-03 04:14
POJ
最小
最大
次小生成树
POJ - 2421
Constructing
Roads(最小生成树简单应用)
题意:一些点已经连通,还有一些未连通,求所有的点连通,需要的代价。题解:最小生成树模板题,先根据邻接矩阵把边都存起来,然后把已经相邻的边权为0,再存起来。跑一遍kk,这些边权为0的肯定把刚才邻接表存进去的给覆盖(用不到他们)了!#include#include#include#include#include#include#include#include#include#include#inclu
Soar-
·
2020-08-03 04:41
图论-------最小生成树
POJ - 2421
Constructing
Roads (最小生成树 prim)
ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthereexistsavi
蝉鸣的夏季
·
2020-08-03 04:57
ACM-图论
Constructing
Roads(第12次h题)
ConstructingRoads问题链接http://poj.org/problem?id=2421DescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBare
qq_43993717
·
2020-08-03 04:03
POJ - 2421
Constructing
Roads【prim】
ConstructingRoadsTimeLimit:2000MSMemoryLimit:65536KTotalSubmissions:28912Accepted:12823DescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnec
黑糖22
·
2020-08-03 04:02
Constructing
Roads(Kruskal)
ProblemDescriptionThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAand
cjmHK
·
2020-08-03 03:57
Constructing
Roads POJ - 2421 prim
ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthereexistsavi
luer9
·
2020-08-03 03:44
prim
Constructing
Roads
ThereareNvillages,whicharenumberedfrom1toN,andyoushouldbuildsomeroadssuchthateverytwovillagescanconnecttoeachother.WesaytwovillageAandBareconnected,ifandonlyifthereisaroadbetweenAandB,orthereexistsavi
HPU王小二
·
2020-08-03 03:01
最小生成树
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