E-COM-NET
首页
在线工具
Layui镜像站
SUI文档
联系我们
推荐频道
Java
PHP
C++
C
C#
Python
Ruby
go语言
Scala
Servlet
Vue
MySQL
NoSQL
Redis
CSS
Oracle
SQL Server
DB2
HBase
Http
HTML5
Spring
Ajax
Jquery
JavaScript
Json
XML
NodeJs
mybatis
Hibernate
算法
设计模式
shell
数据结构
大数据
JS
消息中间件
正则表达式
Tomcat
SQL
Nginx
Shiro
Maven
Linux
Increasing
Longest
Increasing
Subsequence
很经典的题目,用简单的DP可以O(n^2)。再进一步可以O(nlgn),这时lis[i]存的是长度为i的最长递增子序列中最大值的最小值;查找更新位置的时候需要用二分查找。二分查找总是写半天,有什么技巧不?//dp.cpp:Definestheentrypointfortheconsoleapplication. // #include"stdafx.h" #include usingnamesp
u013166464
·
2014-03-23 23:00
二分查找
dp
HDU 1423 Greatest Common
Increasing
Subsequence
题目链接~~>最长公共单调递增子序列(LCIS):方法一(O(n^2)): 最长公共上升子序列(LCIS)的O(n^2)算法 预备知识:动态规划的基本思想,LCS,LIS。 问题:字符串a,字符串b,求a和b的LCIS(最长公共上升子序列)。 首先我们可以看到,这个问题具有相当多的重叠子问题。于是我们想到用DP搞。DP的首要任务是什么?定义状态。1定义状态F
u011074149
·
2014-03-04 21:00
hdu 1423 Greatest Common
Increasing
Subsequence(最长上升公共子序列)
http://acm.hdu.edu.cn/showproblem.php?pid=1423好吧,对这道题表示无语。。。给两个数字序列,求最长上升公共子序列的长度。所以可以先求最长公共子序列,用数组标记第一个序列每个i对应的到i为止最长公共子序列的长度,再求最长上升子序列。#include #include #include usingnamespacestd; intmain() { intt
u013081425
·
2014-03-01 19:00
dp
POJ 2127 Greatest Common
Increasing
Subsequence -- 动态规划
题目地址:http://poj.org/problem?id=2127DescriptionYouaregiventwosequencesofintegernumbers.Writeaprogramtodeterminetheircommonincreasingsubsequenceofmaximalpossiblelength.SequenceS1,S2,...,SNoflengthNiscal
JDPlus
·
2014-02-28 14:00
动态规划
考研机试
HDOJ 1423 Greatest Common
Increasing
Subsequence -- 动态规划
题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=1423ProblemDescriptionThisisaproblemfromZOJ2432.Tomakeiteasyer,youjustneedoutputthelengthofthesubsequence. InputEachsequenceisdescribedwithM-itslength(1
JDPlus
·
2014-02-28 13:00
动态规划
考研机试
Zero Sum(DFS)
Zero Sum Consider the sequence of digits from 1 through N (where N=9) in
increasing
order: 1 2
Simone_chou
·
2014-02-25 20:00
zero
poj 2127 Greatest Common
Increasing
Subsequence (最长公共递增子序列)
GreatestCommonIncreasingSubsequenceTimeLimit: 10000MS MemoryLimit: 65536KTotalSubmissions: 8888 Accepted: 2345CaseTimeLimit: 2000MS SpecialJudgeDescriptionYouaregiventwosequencesofintegernumbers.Write
u010228612
·
2014-02-11 14:00
Geeks面试题: Maximum Sum
Increasing
Subsequence
MaximumSumIncreasingSubsequenceGivenanarrayofnpositiveintegers.Writeaprogramtofindthesumofmaximumsumsubsequenceofthegivenarraysuchthattheintgersinthesubsequencearesortedinincreasingorder. Forexample,i
kenden23
·
2014-01-30 06:00
面试题
SUM
maximum
geeks
Increasi
zoj 3745 Salary
Increasing
题意:某老板要给员工涨薪,每次给工资在[l,r]范围的人涨c单位工资,问最后老板要付多少钱。思路:这题其实是到水题,放上来的原因是提醒自己认真看题……题里有个条件:ri #include #include #include #include #include #include #include #include #include #include #defineinf0x3f3f3f3f #def
qian99
·
2014-01-19 19:00
ZOJ
ZOJ 3745 Salary
Increasing
/*地址:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3745 * *题意:给出N个人的工资,再给工资在[l,r]区间的人加工资c,求q次操作后,老板需要给的总工资。 * *思路:用i保存工资值,a[i]保存工资为i的人数,ans=a[i]*i。 * */ #include #include #defineN2000
u012964281
·
2013-12-29 19:00
C++
c
ACM
最长上升子序列的最优算法
最长上升子序列的最优算法 1 问题背景 最长上升子序列问题(Longest
Increasing
Subsequence)在算法教学中的经典问题,在学习动态规划(Dynamic Programming
·
2013-12-21 18:00
算法
vim:
Increasing
or decreasing numbers
http://vim.wikia.com/wiki/
Increasing
_or_decreasing_numbersvim可以通过C+aC+x简单的进行数字的加减,尤其配上宏之后,可以很方便的定义一系列连续变化的变量
wangeen
·
2013-11-27 13:00
增加堆内存的大小 - 提防眼镜蛇效应
增加堆内存的大小-提防眼镜蛇效应原文:http://plumbr.eu/blog/
increasing
-heap-size-beware-of-the-cobra-effect"眼镜蛇效应"起源于当时英国统治印度殖民地的轶事
BOOM.SS
·
2013-11-20 15:00
jvm
heap
memory
BigMemory
最长递增子序列-Longest
Increasing
Subsequence
动态规划的经典题!packageDP; importjava.util.Arrays; publicclassLIS{ publicstaticvoidmain(String[]args){ int[]A={5,3,4,8,6,7}; System.out.println(lis(A)); System.out.println(lis2(A)); System.out.println(lis
hellobinfeng
·
2013-10-27 09:00
Longest
Increasing
Subsequences(最长递增子序列)的两种DP实现
一、本文内容最长递增子序列的两种动态规划算法实现,O(n^2)及O(nlogn). 二、问题描述最长递增子序列:给定一个序列,从该序列找出最长的升序/递增子序列。特点:1、子序列不要求连续;2、子序列在原序列中按严格(strictly)升序排序;3、最长递增子序列不唯一。 注:下文最长递增子序列用缩写LIS表示。 example:0,8,4,12,2,10,6,14,1,9,5,13,3,11,
·
2013-10-26 15:00
sequence
PMP模拟考试-2
Increasing
resources on the critical path activities may not always shorten the length of the project
·
2013-10-04 10:00
PMP
两次dp-poj-1239-
Increasing
Sequences
题目链接:http://poj.org/problem?id=1239题目大意:给一个数字串(不超过80位),可以在数字之间添加逗号,分成几个数,要求最后形成一个严格递增的序列,且要求最后一个数尽可能的小,如果有多个满足要求,则使第一个数尽可能大,如果还有多个,则使第二个最大,如此类推。求最后的序列。解题思路:好dp+思维。第一次从前往后dp,dp[i]表示包括第i位往前,满足题目要求能得到的最小
cc_again
·
2013-09-30 23:00
动态规划
HDU1423:Greatest Common
Increasing
Subsequence
点击打开题目链接GreatestCommonIncreasingSubsequenceTimeLimit:2000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):3075 AcceptedSubmission(s):967ProblemDescriptionThisisaprobl
l383137093
·
2013-09-28 18:00
dp
LCOS
最长非降子序列LIS(longest
increasing
subsequence)
转载来自:http://hawstein.com/posts/dp-novice-to-advanced.htmlhttp://www.felix021.com/blog/read.php?1587问题:一个序列有N个数:A[1],A[2],…,A[N],求出最长非降子序列的长度。(讲DP基本都会讲到的一个问题LIS:longestincreasingsubsequence)DP解法:正如上面我们
left_la
·
2013-09-23 21:00
[动态规划-1] 最长递增子序列-Longest
Increasing
Subsequence
问题描述:求一个一维数组arr[i]中的最长递增子序列的长度,如在序列1,-1,2,-3,4,-5,6,-7中,最长递增子序列长度为4,可以是1,2,4,6,也可以是-1,2,4,6。问题分析:我们用L(i)表示从arr[0]---arr[i]的以arr[i]结尾的最长递增子序列的长度值,那么:L(i)=1+Max(L(j)),当满足j #include /*返回最长子序列的长度*/ intli
shishengshi
·
2013-09-11 10:00
Tomcat启动不了Server Tomca v6.0 Server at localhost was unable to start
If the server requires more time, try
increasing
the timeout in the server editor.
eddysoft
·
2013-09-06 16:00
localhost
hdu 3030
Increasing
Speed Limits 树状数组
#include #include #include #include #include usingnamespacestd; #defineLL__int64 #definelowbit(x)(x&(-x)) constLLmod=1e9+7; constLLmaxn=500050; LLa[maxn],b[maxn],c[maxn],f[maxn],ans[maxn]; LLn,m,x,y,z
a601025382s
·
2013-09-01 19:00
树状数组
UVa OJ 175 - Keywords (关键字)
Time limit: 3.000 seconds限时3.000秒 Problem 问题 Many researchers are faced with an ever
increasing
·
2013-08-22 20:00
word
ZOJ 2432 Greatest Common
Increasing
Subsequence(最长公共上升子序列+路径打印)
GreatestCommonIncreasingSubsequence题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1432题目大意:给出两串数字,求他们的最长公共上升子序列(LCIS),并且打印出来。SampleInput151425-124-12124SampleOutput214分析:神奇就神奇在是LIS与LC
·
2013-08-17 07:00
sequence
1423 Greatest Common
Increasing
Subsequence (LCIS)
讲解摘自百度; 最长公共上升子序列(LCIS)的O(n^2)算法? 预备知识:动态规划的基本思想,LCS,LIS。? 问题:字符串a,字符串b,求a和b的LCIS(最长公共上升子序列)。? 首先我们可以看到,这个问题具有相当多的重叠子问题。于是我们想到用DP搞。DP的首要任务是什么?定义状态。? 1定义状态F[i][j]表示以a串的前i个字符b串的前j个字符且以b[j]为结尾构成的LCIS的长
·
2013-08-12 19:00
sequence
Greatest Common
Increasing
Subsequence(hdu1423(LCIS))
/*http://acm.hdu.edu.cn/showproblem.php?pid=1423GreatestCommonIncreasingSubsequenceTimeLimit:2000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):2724 AcceptedSubmission(
JHC23
·
2013-08-04 20:00
HDU1423:Greatest Common
Increasing
Subsequence(LICS)
ProblemDescriptionThisisaproblemfromZOJ2432.Tomakeiteasyer,youjustneedoutputthelengthofthesubsequence. InputEachsequenceisdescribedwithM-itslength(1 #include #include usingnamespacestd; intn,m,
·
2013-07-30 19:00
sequence
POJ2127:Greatest Common
Increasing
Subsequence(LICS)
DescriptionYouaregiventwosequencesofintegernumbers.Writeaprogramtodeterminetheircommonincreasingsubsequenceofmaximalpossiblelength.SequenceS1,S2,...,SNoflengthNiscalledanincreasingsubsequenceofasequen
libin56842
·
2013-07-30 10:00
HDU1423:Greatest Common
Increasing
Subsequence(LICS)
ProblemDescriptionThisisaproblemfromZOJ2432.Tomakeiteasyer,youjustneedoutputthelengthofthesubsequence. InputEachsequenceisdescribedwithM-itslength(1 #include #include usingnamespacestd; intn,m,a
libin56842
·
2013-07-29 22:00
HDU
LICS
Auto
increasing
id within oracle
1. Create table: declare num number; begin select count(*) into num from all_tables where table_name=upper('eric_emp_tbl') and owner=upper('eric'); if num=1 th
eric2500
·
2013-07-13 04:00
oracle
sequence
trigger
Server Tomcat v6.0 Server at localhost was unable to start within 45 seconds
If the server requires more time, try
increasing
the timeout in the server editor.
pengfeifei26
·
2013-06-19 17:00
java
tomcat
Increasing
Sequences-ZOJ 1499 POJ 1039
IncreasingSequencesTimeLimit: 1000MS MemoryLimit: 10000KTotalSubmissions: 2773 Accepted: 1039DescriptionGivenastringofdigits,insertcommastocreateasequenceofstrictlyincreasingnumberssoastominimizethema
zoushidexing
·
2013-06-16 20:00
codeforces 11A -
Increasing
Sequence
得到递增序列#include#include#include#include#include#include#include#include#include#include#include#include#includeusingnamespacestd;#definelllonglong#definelsrt>1#defineeps(1e-9)#defineclr_all(x,c)memset(
ymrfzr
·
2013-05-30 07:00
codeforces
单链表创建、排序(升序)
代码实现如下:#include#includetypedefstructLNode{ intdata; structLNode*next;}LNode;LNode*sort_link_list_
increasing
_order
yuan892173701
·
2013-05-15 15:00
算法
单链表
Server Tomcat v7.0 Server at localhost was unable to start within 45 seconds
If the server requires more time, try
increasing
the timeout in the server editor.网上解决办法。 1.在
snake_hand
·
2013-05-03 19:00
start with
Greatest Common
Increasing
Subsequence
GreatestCommonIncreasingSubsequenceTimeLimit:2000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):2183 AcceptedSubmission(s):662ProblemDescriptionThisisaproblemfromZO
wangwenhao00
·
2013-04-15 22:00
最长递增子序列 (Longest
Increasing
Subsequence)
问题描述:给定一个序列 An = a1 ,a2 , ...,an ,找出最长的子序列使得对所有 i B[j] then S[1][j] := 0 else S[1][j] := 1 end for i from 2 to n for j from 1 to n if A[i] > B[j] then S[i][j] := S[i-1][j]
overstack
·
2013-04-13 00:00
vim inserting
increasing
number
SubstitutewithascendingnumbersSupposeyouwanttoreplaceeachoccurrenceof"abc"with"xyz_N"whereNisanascendingnumber(xyz_1,xyz_2,xyz_3,andsoon).Oneapproachusesthefollowingcommand::leti=1|g/abc/s//\='xyz_'.
zzjjzzgggg
·
2013-04-12 21:00
vim
最长不降子序列 LIS(Longest
Increasing
Subsequence) 动态规划与深度搜索
看清楚题意,再做题。我发现我总是给自己出题,把题目的意思看成另一个,哎,结果又来一套说法.这是我做poj1836 Alignment,繁衍出的.注意:以下跟poj1836题意不一。最长不降子序列例题:下面给出三组数,第一行一个队列是人数,然后队伍各自的身高,问从中抽出多少个人可以让剩下的人员从左至右是低到高。input:51111171.71.51.31.31.51.61.771735948out
fofu33
·
2013-04-05 11:00
动态规划
ACM
Eclipse启动异常
If the server requires more time, try
increasing
the timeout in the server editor.
wxb880114
·
2013-03-25 13:00
eclipse
最长上升子序列 Longest
Increasing
Subsequence 输出其中一个序列 O(n^2) O(nlogn)
最长上升子序列概念维基百科->LongestIncreasingSubsequence算法一:动态规划数据定义:a[]:输入序列d[]:保存最长升序子序列的子问题。 d[i]表示以a[i]结尾的最长子序列的长度。 d[]初始化为1。因为子序列最短也是1。n:a和d的长度状态转移方程:d[0]=1 当i=0 d[i]=1+max{d[j],a[i]>a[j]&&0top则将a
YorkCai
·
2013-03-08 19:00
n2
最长上升子序列
longest
S
nlogn
Increasing
输出其中一个序列
hdu 1423 Greatest Common
Increasing
Subsequence(DP 最长公共上升子序列)
GreatestCommonIncreasingSubsequenceTimeLimit:2000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):2081 AcceptedSubmission(s):626ProblemDescriptionThisisaproblemfromZO
nealgavin
·
2013-02-03 14:00
freebsd 9.0 配置samba 出现max_open_files:
increasing
sysctl_max (11095) to minimum Windows limit (16384)解决方法
freebsd9.0配置samba出现max_open_files:increasingsysctl_max(11095)tominimumWindowslimit(16384)解决方法第一种解决方法:sysctlkern.maxfiles=16384sysctlkern.maxfilesperproc=16384第二种解决方法:把下面的2行写入到 /boot/loader.confkern.ma
alantop's blog
·
2013-01-24 12:00
Resolution to the record count
increasing
of the file exported from DB when ‘0A’ is included in it
Resolution totherecordcountincreasingofthefileexportedfromDBwhen‘0A’isincludedinit DBQueryAnalyzer3.02isupforpresentedafterChineseSpringFestival.Ihavebeendoingsoftwaretestonitforaboutamonth.
magenfeng
·
2013-01-18 13:00
tomcat启动问题
If the server requires more time, try
increasing
the timeout in the server editor.
hibeary
·
2013-01-04 11:00
tomcat
POJ 2127 Greatest Common
Increasing
Subsequence (动态规划)
http://poj.org/problem?id=2127 这道题目就是求两个序列的最长公共上升子序列,序列的长度不超过500,那么我们使用O(N^3)复杂度的算法也能过。 我们假设数组A和B分别为这两个序列,我们定义状态dp[i][j]表示以A[i]和B[j]结尾的并且LCIS的最后一个元素小于A[i]的值,也就是说dp[i][j]并不一定是串A[1--i]和串B[1--j]的LC
geniusluzh
·
2012-12-23 16:00
UIView的层次结构--code
//blog.csdn.net/theonezh/article/details/8216584 // Recursively travel down the view tree,
increasing
反求诸己
·
2012-12-18 15:00
UIView
Hdu 1423 Greatest Common
Increasing
Subsequence
最长公共上升子序列,关于O(n^2)的算法,这篇文章讲的不错。http://ishare.iask.sina.com.cn/f/14329392.html?from=like#include #include #include #include #include #include usingnamespacestd; constintMAXN=1005; inta[MAXN],b[MAXN];
Wall_F
·
2012-12-09 22:00
11.15------关于buffer cache 的一段文档的翻译
Increasing
Memory Allocated to the Buffer Cache 增大分配给buffer cache的内存 As a general rule, investigate
wsql
·
2012-11-15 23:00
buffer
Find longest
increasing
sequence (LIS)
#include #include typedefunsignedintuint; voidFindLIS(constuintarr[],uintlength) { uint*lis=newuint[length]; uint*pre=newuint[length]; lis[0]=0; intmax_length=0; for(inti=1;istk; intelem_idx=lis[m
leo524891010
·
2012-11-10 13:00
上一页
13
14
15
16
17
18
19
20
下一页
按字母分类:
A
B
C
D
E
F
G
H
I
J
K
L
M
N
O
P
Q
R
S
T
U
V
W
X
Y
Z
其他