Ladder

Word Ladder——LeetCode

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-11-11 01:19

Leetcode: Word Ladder II

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each intermediate word must e
·2015-11-11 01:44

[itint5]单词变换

http://www.itint5.com/oj/#42 基本上就是word ladder。直接来BFS，记录前驱。
·2015-11-10 21:23

[LeetCode 127] Word Ladder

https://leetcode.com/problems/word-ladder/ http://www.lintcode.com/zh-cn/problem/word-ladder/
·2015-11-09 14:45

[LeetCode] word ladder II

http://www.lintcode.com/zh-cn/problem/word-ladder-ii/# 给出两个单词（start和end）和一个字典，找出所有从start到end的最短转换序列
·2015-11-09 14:45

Leetcode#127 Word Ladder

原题地址   BFS Word Ladder II的简化版（参见这篇文章） 由于只需要计算步数，所以简单许多。
·2015-11-09 12:03

Leetcode#126 Word Ladder II

原题地址   既然是求最短路径，可以考虑动归或广搜。这道题对字典直接进行动归是不现实的，因为字典里的单词非常多。只能选择广搜了。 思路也非常直观，从start或end开始，不断加入所有可到达的单词，直到最终到达另一端。本质上广度优先遍历图。 需要注意的是，拓展下一个单词时不能对字典进行枚举，因为字典里的单词太多。幸好单词本身都不长，所以直接枚举单词所有可能的变形，看看在dict中
·2015-11-09 12:48

Leetcode: Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate word
·2015-11-08 17:52

Desperate housewives S01 EP01-EP02

to rest 下葬 chore  家务活杂事 超4 errand 差事 Lynette Scavo 利奈特 斯卡沃 move up the corporate ladder
·2015-11-08 15:28

leetcode第一刷_Word Ladder II

这道题非常难。 之前的题目我提到过一次用两个vector来做层序遍历的，就是由于这道题。要想最后恢复出单词变换的路径，就须要事先保存，依据dp中路径恢复的启示，保存的应该是一个单词的前一个变换节点。可能有非常多个单词都能变换到当前单词，因此应该是一个set。用一个二维的vector保存当前能够变换到的单词和变换出这些单词单词。每一维的vector存放的都是一个set。设存放当前可訪问单词的vec
·2015-11-08 13:02

图论(三)------广度优先搜索与单源无权最短路径

比如，一个word ladder problem，一次只变换一个字母，找出从fool到sage的最短路径。
·2015-11-08 13:40

Word Ladder

Word Ladder Given two words (start and end), and a dictionary, find the length of shortest
·2015-11-08 11:54

leetcode 解题报告 Word Ladder II

见https://oj.leetcode.com/problems/word-ladder-ii/ 这一题我反复修改了两天半。尝试过各种思路，总是报TLE。
·2015-11-07 10:20

poj 2507Crossed ladders <计算几何>

链接：http://poj.org/problem?id=2507 题意：哪个直角三角形，一直角边重合， 斜边分别为 X, Y， 两斜边交点高为 C ， 求重合的直角边长度~ 思路： 设两个三角形不重合的两条直角边长为 a ， b，根据 三角形相似， 则有 1/a + 1/b =1/c, 二分枚举答案得之~ 1 #include <cstdio> 2 #includ
·2015-11-05 09:15

Word Ladder

Word Ladder 问题: Given two words (start and end), and a dictionary, find the length of shortest
·2015-11-03 21:14

POJ 1059 Chutes and Ladders

1. 一下午就做了这么一道题，蛋疼的模拟题。刚开始没有考虑当超过100的时候怎么处理，一直WA，上网看解题报告才知道。。。 2. memset()函数的用法。只能初始化为0或者-1。当初始值为其他数时，是在每一位上是这个数（这句话没明白），记住只能把数组初始化为0或者-1就行了； 3. 此题属于模拟题，不得不说，模拟题的if语句就是多啊； #include <iostream
·2015-11-02 18:53

《消费提示：看懂天梯 不被忽悠　显卡/CPU性能排名》

From: http://www.smzdm.com/consumer-tip-read-ladder-not-been-fooled-graphics-cpu-performance-ranking.html
·2015-11-02 14:55

Word Ladder II

Word Ladder II 问题： Given two words (start and end), and a dictionary, find all shortest transformation
·2015-11-02 14:56

【leetcode】Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-11-02 10:15

LeetCode Word Ladder 找单词变换梯

  题意：给出两个单词，以及一个set集合，当中是很多的单词。unordered_set是无序的集合，也就是说找的序列也是无序的了，是C++11的标准，可能得升级你的编译器版本了。要求找出一个从start到end这两个单词的变换序列。从start开始，每次可以变一个字母，且所变之后的单词必须在set中，最后要求变成end，问经过了多少个中间变换？注意要加多2次（start和end也要算
·2015-11-01 10:45

POJ 1059 Chutes and Ladders

POJ_1059     由于题目说了最后掷骰子的次数不会超过1000，所以直接模拟掷骰子的过程即可。 #include<stdio.h>#include<string.h>#define MAXN 1010#define MAXD 110#define MAXP 10int P, die[MAXN], g[MAXD], turn[MAX
·2015-10-31 19:56

LeetCode Word Ladder

Given two words (beginWord and endWord), and a dictionary, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be
·2015-10-31 18:06

LeetCode Word Ladder II

    Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be change
·2015-10-31 18:05

天题系列：Word Ladder II

乍一看还真以为和1 一样，呵呵 当然不是啦 Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can b
·2015-10-31 12:35

Word Ladder---BFS

还是参考爱做饭同学 http://www.cnblogs.com/springfor/p/3893499.html Given two words (beginWord and endWord), and a dictionary, find the length of shortest transformation sequence from beginWord
·2015-10-31 12:34

Word Ladder

这题的基本思路很轻易看懂，就是转换成图的中的最短路径问题。我一直出现TLE的错误，原因就在转换过程太复杂。 可以遍历整个表，建立邻接表或者邻接矩阵。问题是这个过程就会是一个o(n^2)的过程。恰恰这道题又一个测试用例的词特别多，于是这个转换过程就行不通了。 办法很简单，就是枚举每个词变化一个字母后可能出现的单词（复杂度：length X 26， length是单词的长度），然后看它在不在词典中
·2015-10-31 12:08

Word Ladder II

https://leetcode.com/problems/word-ladder-ii/ Given two words (start and end), and a dictionary
·2015-10-31 11:41

Word Ladder

https://leetcode.com/problems/word-ladder/ Given two words (start and end), and a dictionary
·2015-10-31 11:41

LeetCode - Word Ladder II

Word Ladder II 2014.2.13 01:23 Given two words (start and end), and a dictionary, find all
·2015-10-31 11:30

LeetCode - Word Ladder

Word Ladder 2014.2.27 02:14 Given two words (start and end), and a dictionary, find the length
·2015-10-31 11:30

leetcode[126]Word Ladder II

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Ea
·2015-10-31 10:01

leetcode[127]Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-10-31 10:01

LeetCode127：Word Ladder II

题目： Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each intermediate word m
·2015-10-31 10:03

LeetCode126：Word Ladder

题目： Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermedi
·2015-10-31 10:03

【leetcode】Word Ladder II（hard）★ 图 回头看

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Ea
·2015-10-31 09:25

《Cracking the Coding Interview》——第18章：难题——题目10

解法：Leetcode中有Word Ladder，这题基本思路一致。 代码： 1 // 18.10 Given a list of words, all of same length.
·2015-10-31 09:19

【leetcode刷题笔记】Word Ladder II

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Ea
·2015-10-31 09:54

UVA 10029 Edit Step Ladders

UVA_10029     这个题目一开始想转化成最长上升子序列的模型，但发现这样不好做，后来看了别人的题解发现可以转化成找有向无环图的最长路去做。     这样面临的一个问题就是如果显性地建图的话是没办法存下每条边的，于是我们不妨在每次尝试连线的时候再判断这条边是否存在。     为了方便判断两个字符串之间是否有一条有向边，我们不
·2015-10-31 09:11

利用css中的border生成三角，兼容包括IE6的主流浏览器

1、生成四个不同颜色方向的梯形 #ladder{ width:20px; height:20px; border:10px solid; border-color:#ff3300 #0000ff
·2015-10-31 08:47

【leetcode】Word Ladder (hard) ★

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-10-30 14:26

Verilog与C++的类比 (IC Design) (Verilog) (C/C++)

例如可以写一个FullAdder module，表示全加器这种器件。
·2015-10-28 09:30

My favorate FireFox addons

Gladder 根据设置自动使用代理打开网页。自从用了它，咱 WikiPedia也能上了，BlogSpot也能逛了，Gmail也不当了，总之就是一个字：爽！
·2015-10-28 08:00

[LeetCode] Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-10-27 15:17

Leetcode: Word Ladder II

Question Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a
·2015-10-27 14:14

leetcode -- Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-10-27 12:10

Complete The Pattern #6 - Odd Ladder

Complete The Pattern #6 - Odd Ladder Task: You have to write a function pattern which creates
·2015-10-21 12:30

[leetcode]Word Ladder

class Solution { public: int ladderLength(string start, string end, unordered_set<string>
·2015-10-21 11:45

Leetcode:Word Ladder 单词接龙

Word Ladder Given two words (start and end), and a dictionary, find the length of shortest transformation
·2015-10-21 11:36

VHDL实现加法器

//全加法器libraryieee;useieee.std_logic_1164.all;entityalladderisport(A,B,Cin:instd_logic;S,Cout:outstd_logic
lym152898·2015-10-07 00:55

*LeetCode-Word Ladder

不等就判断这个新造的词是否在词典里假如在就removefromdict并且addtoqueue每次这个que里存在的是同一个level的都循环完了再len＋＋publicclassSolution{ publicintladderLength
bsbcarter·2015-10-06 03:00
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