Ladder

Word Ladder II

1publicclassSolution{ 2publicList>findLadders(StringbeginWord,StringendWord,SetwordList){ 3List>res
一切不期而至·2016-02-18 09:00

Word Ladder

1publicclassSolution{ 2publicintladderLength(StringbeginWord,StringendWord,SetwordList){ 3if(!
一切不期而至·2016-02-16 09:00

Word Ladder

Giventwowords(beginWordandendWord),andadictionary'swordlist,findthelengthofshortesttransformationsequencefrombeginWordtoendWord,suchthat:OnlyonelettercanbechangedatatimeEachintermediatewordmustexistin
KickCode·2016-02-11 02:00

Word Ladder II python

题目Giventwowords(beginWordandendWord),andadictionary’swordlist,findallshortesttransformationsequence(s)frombeginWordtoendWord,suchthat:OnlyonelettercanbechangedatatimeEachintermediatewordmustexistinthe
风澈云间·2016-01-24 23:52

leetcode -- Word Ladder I & II -- II没有理解

WordLadderhttps://leetcode.com/problems/word-ladder/这里思路就是BFS,DFS太慢。
xyqzki·2015-12-17 21:00

leetcode笔记：Word Ladder

一.题目描述Giventwowords(startandend),andadictionary,findthelengthofshortesttransformationsequencefromstarttoend,suchthat:•Onlyonelettercanbechangedatatime•EachintermediatewordmustexistinthedictionaryForex
liyuefeilong·2015-12-10 23:00

Abstraction of Lean In

Thereisfarmoretolifethanclimbingacareerladder,includingraisingchildren,seekingpersonalfulfillment,contributingtosociety
kid551·2015-12-08 22:44

算法经典问题（一）

阶最后剩4阶，如果你每次跨6阶，最后剩余5阶，只有当你每次跨7阶，才正好到头，这个楼梯到底有多少阶，分析，因为每次跨7阶，才正好到头，说明楼梯的阶数是7的倍数int main(){             ladder
eatnothing·2015-12-07 19:00

Word Ladder II

自己写的一个算法，用node来代替存储每个可行点的历史串。但是LC还是过不了，因为超时：//Toavoidmemoryissues,usenewnodeforit privateclassWLNode{ publicStringstr; publicWLNodeparent; publicWLNode(Stringstr,WLNodeparent){ this.str=str; this.par
Simon253·2015-12-06 17:00

sicily 1063. Who's the Boss

MemoryLimit:32MBDescriptionSeveralsurveysindicatethatthetalleryouare,thehigheryoucanclimbthecorporateladder.AtTALLEnterprisesInc.this"defactostandard"hasbee
huangjq36SYSU·2015-11-16 14:00

10029 - Edit Step Ladders

描述：字符串有点大，直接用动规的话25000^2肯定会超时，所以需要动规+二分/哈希，我的代码是采用二分，这样的话，不超过2s就可以过了 #include <cstdio> #include <cstdlib> #include <cstring> char str[25010][18]; int v[25010]; int n,sum; void
·2015-11-13 17:58

Verilog与C++的类比

例如可以写一个FullAdder module，表示全加器这种器件。
·2015-11-13 16:14

Java Word Ladder(字梯)

问题： Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate wo
·2015-11-13 14:21

Leetcode | Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a timeEach intermediate word mus
·2015-11-13 13:45

LeetCode | Word Ladder II

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a timeEach intermediate word must exist
·2015-11-13 13:25

My Solution: Word Ladder

public class Solution { public int ladderLength(String start, String end, Set<String
·2015-11-13 12:40

leetcode Word Ladder II

和上题 Word Ladder I题目差不多，不过这里是要记录所有最段路径的可能。
·2015-11-13 12:33

leetcode Word Ladder

给定两个字符串start和end，和一个字符串字典dict，判断从start到end 要经过几次变化，每次变化只能取字典里的词，且相邻的变化只有一个字符不同。例如： For example, Given:start = "hit"end = "cog"dict = ["hot"
·2015-11-13 12:32

LeetCode: Word Ladder II

看了别人的答案，这题的关键在于数据结构的选择，一开始选择的multimap肯定MLE 1 class Solution { 2 public: 3 void getPath(vector<vector<string> > &ansSet, vector<string> &ans, int now, vector<vec
·2015-11-13 12:58

LeetCode: Word Ladder

1 class Solution { 2 public: 3 int ladderLength(string start, string end, unordered_set<string
·2015-11-13 12:43

UVa 10566 - Crossed Ladders

设宽度为w，二分w。 1 #include <cstdio> 2 #include <cmath> 3 #include <algorithm> 4 5 #define eps 1e-6 6 7 using namespace std; 8 9 int main() 10 { 11 double x,
·2015-11-13 07:20

[LeetCode]Word Ladder II

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Ea
·2015-11-13 05:50

[LeetCode]Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-11-13 05:49

uva 10026 Problem C: Edit Step Ladders

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=970  通过对每一个字符串，每一个位置进行枚举三个操作，然后二分查找操作后的字符串是否存在，dp记录。 1 #include <cstdio>
·2015-11-13 01:22

[LeetCode#127]Word Ladder

---恢复内容开始--- The problem: Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one l
·2015-11-13 01:50

LeetCode: Word Ladder解题报告

Word Ladder解题报告 Given two words (start and end), and a dictionary, find the length of shortest
·2015-11-13 00:03

LeetCode: Word Ladder II 解题报告

Word Ladder II Given two words (start and end), and a dictionary, find all shortest transformation
·2015-11-13 00:37

LeetCode_Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a time Each intermediate word
·2015-11-12 23:23

Word Ladder

  1 题目 1 Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: 2 3 Only one letter can be changed at a ti
·2015-11-12 22:26

【leetcode】Word Ladder II

  Word Ladder II Given two words (start and end), and a dictionary, find all shortest
·2015-11-12 21:13

【leetcode】Word Ladder

Word Ladder  Total Accepted: 24823 Total Submissions: 135014 My Submissions Given
·2015-11-12 18:36

UVa 10029 Edit Step Ladders（hash状态压缩DP）

题意： 给定多个字符串，是按照字典顺序排列的。一个字符串如果能够可以通过改变一个字母，删除一个字母，增加一个字母变成后面的某一个字符串， 那么称这两个字符串之间存在一个阶梯，问最多有多少个阶梯。 思路： http://www.cnblogs.com/staginner/archive/2011/11/30/2269222.html 这一题的难点在于题目数据量很大，O(n^2)的算法铁定会
·2015-11-12 17:20

<2012 12 25> 嵌入式工程师眼中的PLC

对于PLC的编程语言，工业界有一些标准，主要有梯形图（LAD－LAdder Diagram）、顺序功能图（SFC－Seauential Fuction Chart）、语
·2015-11-12 15:27

leetcode—word ladder II

1.题目描述 Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that:   Only one letter can be changed at a time
·2015-11-12 13:09

Word Ladder II

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Ea
·2015-11-12 11:16

Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-11-12 11:15

Word Ladder 改

  1 public class Solution { 2 public int ladderLength(String start, String end, HashSet
·2015-11-12 09:44

Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-11-12 09:43

leetcode—word ladder II

1.题目描述 Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that:   Only one letter can be changed at a time
·2015-11-12 09:43

LeetCode Word Ladder II

原题链接在这里：https://leetcode.com/problems/word-ladder-ii/它山之石，在生成neighbours时需采用循环，否则会有concurrentModificationException
Dylan_Java_NYC·2015-11-12 04:00

Word Ladder II

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Ea
·2015-11-11 15:42

leetcode-Word Ladder II

Word Ladder II   Total Accepted: 6164  Total Submissions: 58601 My Submissions
·2015-11-11 14:28

[leetcode]Word Ladder II

因为搜索所有答案，所有我有了个DFS的方案。但后来一看，超时又错误，因为看错题，求的是所有最短路径的解。 public class Solution { private ArrayList<ArrayList<String>> ans = new ArrayList<ArrayList<String>>(); private HashSe
·2015-11-11 14:37

Word Ladder II

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Ea
·2015-11-11 13:27

Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-11-11 13:26

Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-11-11 13:59

Word Ladder

Given two words (start and end), and a dictionary, find the length of shortest transformation sequence from start to end, such that: Only one letter can be changed at a ti
·2015-11-11 11:41

Word Ladder II Graph

Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Ea
·2015-11-11 04:56

Word Ladder

Given two words (start and end), and a dictionary, find all transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each interm
·2015-11-11 04:55

[leetcode]Word Ladder

最终解法参考了：http://discuss.leetcode.com/questions/1108/word-ladder 和 http://blog.sina.com.cn/s/
·2015-11-11 03:56
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