Permutations

【leetcode】 Permutation Sequence (middle)

unique permutations.
·2015-10-27 15:42

【leetcode】Permutations (middle)

Given a collection of numbers, return all possible permutations.
·2015-10-27 15:41

[LeetCode] Permutation Sequence

unique permutations.
·2015-10-27 15:03

[LeetCode] Permutations II

Given a collection of numbers that might contain duplicates, return all possible unique permutations.
·2015-10-27 15:03

[LeetCode] Permutations

Given a collection of numbers, return all possible permutations.
·2015-10-27 15:02

Codeforces 463D

Gargari and Permutations time limit per test 2 seconds memory limit per test 256 megabytes
·2015-10-27 15:15

[LeetCode] Permutation Sequence

unique permutations.
·2015-10-27 14:59

Permutations 模拟

Permutations time limit per test 1 second memory limit per test 256 megabytes input standard
·2015-10-27 13:15

Young's Picture Permutations

Description Mr. Young wishes to take a picture of his class. The students will stand in rows with each row no longer than the row behind it and the left ends of the rows aligned. For instance, 12 stu
·2015-10-27 12:07

LeetCode:Permutation Sequence

unique permutations.
·2015-10-27 11:37

[leedcode 47] Permutations II

Given a collection of numbers that might contain duplicates, return all possible unique permutations.
·2015-10-23 09:03

[leedcode 46] Permutations

Given a collection of numbers, return all possible permutations.
·2015-10-23 09:02

codeforces Gargari and Permutations(DAG+BFS)

1 /* 2 题意：求出多个全排列的lcs！ 3 思路：因为是全排列，所以每一行的每一个数字都不会重复，所以如果有每一个全排列的数字 i 都在数字 j的前面，那么i， j建立一条有向边！ 4 最后用bfs遍历整个图，求出源点到每一个点的距离，其中最大的距离就是最长的公共子序列的长度！ 5 */ 6 #include<iostream>
·2015-10-23 08:11

Permutations【python】

class Solution: # @param num, a list of integer # @return a list of lists of integers def permute(self, num): length=len(num) if length==1: return [num]
·2015-10-23 08:10

CodeForces 187A Permutations

反向思维，先求数组中不用处理的元素个数，再用n减去这个数，得到结果。   1 #include <iostream> 2 #include <cstring> 3 4 #define maxn 200000+10 5 6 using namespace std; 7 8 int n; 9 int a[maxn],b[m
·2015-10-23 08:15

TOJ 4003 Next Permutation

描述 It is an interesting exercise to write a program to print out all permutations of 1, 2, …, n.
·2015-10-23 08:42

leetcode-46、47 Permutations/II 数字的排列组合

一、Permutations问题描述：Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations
woliuyunyicai·2015-10-22 08:00

Leetcode:Permutations 排列

戳我去解题 Given a collection of numbers, return all possible permutations.
·2015-10-21 13:08

Codeforces Round #136 (Div. 1)C. Little Elephant and Shifts multiset

256 MB 题目连接 http://codeforces.com/problemset/problem/220/C Description The Little Elephant has two permutations
·2015-10-21 12:50

[leedcode 60] Permutation Sequence

unique permutations.
·2015-10-21 12:34

Useful R functions

Random Samples and Permutations sample(x, size, replace = FALSE, prob = NULL) sample.int(n, size
·2015-10-21 12:37

Programming pages of Jasper Neumann

http://programming.sirrida.de/ Discussion topics Bit permutations Download source files
·2015-10-21 10:28

leetcode Permutations

题目链接思路：递归回溯。典型应用publicclassSolution{ intn; List>result; Listtemp; booleanisUsed[]; int[]nums; publicList>permute(int[]nums){ n=nums.length; isUsed=newboolean[n]; temp=newLinkedList(); result=newLinke
bleuesprit·2015-10-14 19:00

【LeetCode从零单刷】Permutations

题目：Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].解答：回溯法（剪枝法）。技巧以及注意事项已经在《【LeetCode从零单刷
yOung_One·2015-10-13 09:00

Permutations II

Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1]. Runtime:28ms1classSolution{
amazingzoe·2015-10-13 04:00

Permutations

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1]. Analyse:  (1)Swapthe1stelementwithallth
amazingzoe·2015-10-13 02:00

LeetCode Permutations II

原题链接在这里：https://leetcode.com/problems/permutations-ii/题目：Givenacollectionofnumbersthatmightcontainduplicates
Dylan_Java_NYC·2015-09-27 12:00

LeetCode Permutations

原题链接在这里：https://leetcode.com/problems/permutations/题目：Givenacollectionof distinct numbers,returnallpossiblepermutations.Forexample
Dylan_Java_NYC·2015-09-27 11:00

LeetCode -- Permutations

 题目描述：Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].就是对给定的数组生成全排列。思路：本题主要是Backtracking的一个基本应
csharp25·2015-09-25 11:00

Gargari and Permutations(dp)

题目链接：codeforces463D题目大意：给出k个排列，问这k个排列的最长公共子序列的长度。题目分析：第一次做这种排列的dp，感觉学到了一种新的定义状态的方法。首先我们要记录pos[i][j]代表第i行数j出现的位置。cnt[i]记录当前扫过的范围内数i出现的次数。dp[i]表示以数i结尾的最长公共子序列的长度。我们首先遍历的是序列的长度，然后每次扫描每一行上的数，更新cnt[i],然后如果
qq_24451605·2015-09-21 19:00

[CareerCup] 9.5 Permutations 全排列

LeetCode上的原题，请参加我之前的博客Permutations全排列和PermutationsII全排列之二。 
Grandyang·2015-09-20 09:00

leetcode_Permutations II

描述：Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].思路：就该题来说，它是Permutation的进化版
dfb198998·2015-09-09 18:00

Leetcode: Permutations II

QuestionGivenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations:[1,1,2],[1,2,1],and[2,1,1].ShowTagsShowSimilarProbl
ayst123·2015-09-09 07:00

Leetcode: Permutations

QuestionGivenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].ShowTagsShowSimilarProblemsSolution1Ge
ayst123·2015-09-09 06:00

LeetCode题解：Permutations

Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].题意：求出给定数字的所有组合可能解决思路：先加入第一个元素，然后把第二个元素插入两个位置中，
u012403246·2015-09-06 21:00

LeetCode（47）Permutations II

题目Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations:[1,1,2],[1,2,1],and[2,1,1].分析用上一题的代码，完全可以AC，那是因为我们的库函数nex
fly_yr·2015-08-31 20:00

LeetCode（46）Permutations

题目Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].分析求给定向量数组所有元素的全排列问题。我们知道n个元素有n!种全排列，而STL底层文件
fly_yr·2015-08-31 20:00

POJ 2470 Ambiguous permutations（水~）

Description新旧位置和数字的互换比如，原来的数字和位置（位置用[]框起来）是：23451[1][2][3][4][5]–>51234[1][2][3][4][5]Input多组输入，每组用例第一行为数列长度n，第二行n个数表示数列1~n调整后的数列，以n=0结束输入Output对于每组用例，如果调整后的数列符合互换规则则输出ambiguous，否则输出notambiguousSample
V5ZSQ·2015-08-28 09:00

[LeedCode OJ]#46 Permutations

联系信箱：[email protected]】题目链接：https://leetcode.com/problems/permutations/题意：给定一个数组，要求返回其所有全排列的情况思路
libin1105·2015-08-26 16:00

Leetcode - Permutations II

Paste_Image.pngMycode:importjava.util.ArrayList;importjava.util.Arrays;importjava.util.List;publicclassSolution{publicList>permuteUnique(int[]nums){if(nums==null||nums.length==0)returnnull;ArrayList>r
Richardo92·2015-08-22 04:21

HDU 5338(ZZX and Permutations-用线段树贪心)

ZZXandPermutationsTimeLimit:6000/3000MS(Java/Others)    MemoryLimit:131072/131072K(Java/Others)TotalSubmission(s):888    AcceptedSubmission(s):278ProblemDescriptionZZXlikespermutations.ZZXknowsthatape
nike0good·2015-08-20 20:00

Permutations

Youaregiven n k-digitintegers.Youhavetorearrangethedigitsintheintegerssothatthedifferencebetweenthelargestandthesmallestnumberwasminimum.Digitsshouldberearrangedbythesameruleinallintegers.InputThefirs
Kirito_Acmer·2015-08-13 09:00

python 全排列

itertools模块现成的全排列：foriinitertools.permutations('abcd',4):print''.join(i)相关全排列算法：defperm(l):if(len(l)&
Andrew9tech·2015-08-09 11:55

LeetCode 46 - Permutations

Given a collection of numbers, return all possible permutations.
yuanhsh·2015-08-06 03:00

LeetCode 46 - Permutations

阅读更多Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].publicList>permute(int[]num){List>result=n
yuanhsh·2015-08-04 00:00

HDOJ 5338 ZZX and Permutations 线段树+树状数组

[题意]:给一个排列加上表示循环的括号,问如何让1到n的对应的字典序最大.从1开始贪心每个数字可以往三个地方走,右边第一个,跳转到左边的某一个,和自己构成循环对于走到右边第一个的情况,只要判断右边的那个有没有被占据就可以了,如果可以和右边的互换,那么需要在线段树中将右边的数置为0跳转到左边的某一个,一个数如果跳转到左边的某一个则说明左边的那个是括号开头这个数是括号结尾,用一个线段树查询区间里的最大
u012797220·2015-08-03 22:00

Leetcode - Permutation II

原题链接： https://leetcode.com/problems/permutations-ii/ [分析] 同Permutation一题的区别在于输入数组可能包含重复元素，在面试时即使面试官没有明确指出也该想到
likesky3·2015-08-01 10:00

多校第四场 1012 hdu 5338 ZZX and Permutations(线段树+树状数组+贪心)

题目链接：hdu5338题目大意：首先我们有一个序列：1，2，…….,n。我们要读入一个操作序列，这个序列是1~n的一个排列，我们可以通过加括号形成一个循环节，循环节不能嵌套和交叉循环节内部是后面的换到前面，最前面的换到最后面问如何将操作序列划分循环，能够将原序列通过转换获得字典序最大的序列题目分析：首先我们既然要得到要字典序最大，那么我们可以贪心地从高到低地枚举每一个位，每一位尽量取大的，因为如
qq_24451605·2015-07-31 18:00

【线段树】 HDOJ 5338 ZZX and Permutations

每次贪心的找后一位或前面最大的。。。。#include usingnamespacestd; typedeflonglongLL; #definelsonos,ss; set::iteratorit; intmaxv[maxn>1; build(lson); build(rson); pushup(o); } voidupdate(into,intL,intR,intq) { if(L==R)
blankcqk·2015-07-31 14:00

HDU 5338 ZZX AND PERMUTATIONS 线段树

链接多校题解胡搞。。。题意太难懂了。。ZZXandPermutationsTimeLimit:6000/3000MS(Java/Others)    MemoryLimit:131072/131072K(Java/Others)TotalSubmission(s):310    AcceptedSubmission(s):83ProblemDescriptionZZXlikespermutatio
qq574857122·2015-07-31 00:00
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