poj-2488

POJ-2488 A Knight's Journey（深搜DFS）

POJ-2488AKnight’sJourney##AKnight’sJourneyTimeLimit:1000MSMemoryLimit:65536KTotalSubmissions:43097Accepted:14620DescriptionBackgroundTheknightisgettingboredofseeingthesameblackandwhitesquaresagainanda
Undefined variable·2020-07-30 09:24

POJ-2488 A Knight's Journey

BackgroundTheknightisgettingboredofseeingthesameblackandwhitesquaresagainandagainandhasdecidedtomakeajourneyaroundtheworld.Wheneveraknightmoves,itistwosquaresinonedirectionandonesquareperpendiculartot
AKone123456·2020-07-30 09:30

POJ-2488 A Knight's Journey 解题报告

DescriptionBackgroundTheknightisgettingboredofseeingthesameblackandwhitesquaresagainandagainandhasdecidedtomakeajourneyaroundtheworld.Wheneveraknightmoves,itistwosquaresinonedirectionandonesquareperpe
angle555945·2020-07-04 11:09

poj-2488

AKnight'sJourneyTimeLimit:1000MSMemoryLimit:65536KTotalSubmissions:49498Accepted:16787DescriptionBackgroundTheknightisgettingboredofseeingthesameblackandwhitesquaresagainandagainandhasdecidedtomakeajo
fenger_c·2018-04-20 19:25

POJ-2488 国际象棋马的走法 （深度优先搜索和回溯）

#include#defineMAX27voiddfs(inti,intj);intdx[8]={-1,1,-2,2,-2,2,-1,1};intdy[8]={-2,-2,-1,-1,1,1,2,2};intmarked[MAX][MAX];//标记intpathx[MAX];intpathy[MAX];intflag,step;intp,q;intmain(void){intn;inti=0;i
zhayujie·2017-07-03 22:00

（水）POJ-2488字典序dfs

题目大意：给一个p,q分别代表图的行与列数（列在输出时用A，B......表示），规定一个走的规则，求出走遍所有格子且不重复的方法，若有多种答案则输出字典序最小的，无输出impossible。这里的字典序以列优先，即A2#includeusingnamespacestd;intp,q,kase,T;intd[8][2]={{-1,-2},{1,-2},{-2,-1},{2,-1},{-2,1},{
AC_hell·2016-04-06 15:33

（水）POJ-2488字典序dfs

题目大意：给一个p,q分别代表图的行与列数（列在输出时用A，B......表示），规定一个走的规则，求出走遍所有格子且不重复的方法，若有多种答案则输出字典序最小的，无输出impossible。这里的字典序以列优先，即A2 #include usingnamespacestd; intp,q,kase,T; intd[8][2]={{-1,-2},{1,-2},{-2,-1},{2,-1},{-2,
AC_hell·2016-04-06 15:00

POJ-2488 A Knight's Journey dfs搜索

简单的dfs搜索，题目要求是骑士可以从任意一点出发走完整个棋盘的路径。字典序输出要注意八个方向的排列顺序。 代码如下： #include <cstring> #include <cstdlib> #include <cstdio> using namespace std; int N, M, dir[8][2] = {-2, -1, -2, 1
·2015-10-30 14:20

poj-2488 A Knight's Journey

#include #include #include #include intmap[50][50]; intp,q; intmove[8][2]={-1,-2,1,-2,-2,-1,2,-1,-2,1,2,1,-1,2,1,2}; intpn[50]; charqn[50]; intflag; voiddfs(intnum,charch,intstep){ inti; if(step==p*q
Strokess·2015-10-04 18:00

poj-2488

//376K16MSG++ #include #include #defineMAX28 intboard[MAX][MAX]; intp; intq; structPoint{ intx; inty; }; typedefstructPointPoint; PointvisitOrder[MAX]; intvisitedSquareNum; intflag[MAX][MAX]; int
fyfcauc·2014-07-19 22:00

POJ-2488 A Knight's Journey(需注意搜索顺序的深搜)

AKnight'sJourneyTimeLimit: 1000MS MemoryLimit: 65536KTotalSubmissions: 26950 Accepted: 9195DescriptionBackground Theknightisgettingboredofseeingthesameblackandwhitesquaresagainandagainandhasdecidedtom
u012628310·2013-12-05 12:00

POJ-2488 A Knight's Journey 解题报告

DescriptionBackground Theknightisgettingboredofseeingthesameblackandwhitesquaresagainandagainandhasdecidedtomakeajourney aroundtheworld.Wheneveraknightmoves,itistwosquaresinonedirectionandonesquareper
angle555945·2012-02-16 01:00
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