ＨＤＵ １３１２ Red and Black
Red and Black
Time Limit: 2000/1000 MS
Memory Limit: 65536/32768 K (Java/Others)
Problem
There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only on black tiles.
Write a program to count the number of black tiles which he can reach by repeating the moves described above.
Input
The input consists of multiple data sets. A data set starts with a line containing two positive integers W and H; W and H are the numbers of tiles in the x- and y- directions, respectively. W and H are not more than 20.
There are H more lines in the data set, each of which includes W characters. Each character represents the color of a tile as follows.
'.' - a black tile
'#' - a red tile
'@' - a man on a black tile(appears exactly once in a data set)
Output
For each data set, your program should output a line which contains the number of tiles he can reach from the initial tile (including itself).
Sample Input
6 9
....#.
.....#
......
......
......
......
......
#@...#
.#..#.
11 9
.#.........
.#.#######.
.#.#.....#.
.#.#.###.#.
.#.#..@#.#.
.#.#####.#.
.#.......#.
.#########.
...........
11 6
..#..#..#..
..#..#..#..
..#..#..###
..#..#..#@.
..#..#..#..
..#..#..#..
7 7
..#.#..
..#.#..
###.###
...@...
###.###
..#.#..
..#.#..
0 0Sample Output
45
59
6
13
本题据学长说是板子题（简单到不能再简单的那种），好吧。。。。我不会 ）X--X（ ，，按着板子套了好久，总算弄懂了。。
翻译就不粘了，以后还是要看懂英文的，毕竟很多题都是英文的，，，，，所以就说一下大意吧！！！！
题的大意：@是你的起始位置， 点是你可以走的，#号是墙不能走，问你你能到走的位置的数目（其中包括你的起始位置@）
解题思路：DFS深搜
ＡＣ代码：
#include
#include
#include //memset对数组进行赋初值memset(数组名,所赋的值,数组的长度sizeof(数组名)) strcmp
#include //string
#include //vec
#include //que
#include //sta
#include //set se;
#include
以下这个代码是用ｓｃａｎｆ（＂％ｃ＂，＆ｓｔｒ［ｉ］［ｊ］）；来接收的：
int main()
{
int stax, stay;
while(scanf("%d %d", &w, &h) != EOF && (w || h))
{
getchar();//第一次吸收掉输入w,h之后的那个回车键；
// for(int i=0; i
本题所学到的：
- 如果用％ｃ来接收需要用ｇｅｔｃｈａｒ（）来吸收换行符；
- ｍｅｍｓｅｔ（ｖｉｓ， ａ， ｓｉｚｅｏｆ（ｖｉｓ）） （其中ｖｉｓ表示数组名，ａ表示要赋的值，ｓｉｚｅｏｆ（ｖｉｓ）表示要赋值的长度）
- 告诉你个秘密这个ｍｅｍｓｅｔ的头文件是＃ｉｎｃｌｕｄｅ ＜ｓｔｒｉｎｇ．ｈ＞
- 它也可以给非ｉｎｔ型的数组赋值