[BZOJ3265]志愿者招募加强版（单纯形）

题目描述

传送门

题解

和志愿者招募一样啊
单纯形裸题

代码

#include
#include
#include
#include
#include
using namespace std;
#define N 1005
#define M 10005

const double eps=1e-9;
const double inf=1e18;
int n,m,k,l,r;
double a[M][N],b[M],c[N],ans;

void pivot(int l,int e)
{
    b[l]/=a[l][e];
    for (int i=1;i<=n;++i)
        if (i!=e) a[l][i]/=a[l][e];
    a[l][e]=1.0/a[l][e];
    for (int i=1;i<=m;++i)
        if (i!=l&&fabs(a[i][e])>eps)
        {
            b[i]-=b[l]*a[i][e];
            for (int j=1;j<=n;++j)
                if (j!=e)
                    a[i][j]-=a[l][j]*a[i][e];
            a[i][e]=-a[l][e]*a[i][e];
        }
    ans+=b[l]*c[e];
    for (int i=1;i<=n;++i)
        if (i!=e)
            c[i]-=c[e]*a[l][i];
    c[e]=-c[e]*a[l][e];
}
void simplex()
{
    while (1)
    {
        int e;
        for (e=1;e<=n;++e)
            if (c[e]>eps) break;
        if (e==n+1) break;
        double Min=inf,t;int l;
        for (int i=1;i<=m;++i)
            if (a[i][e]>eps&&(t=b[i]/a[i][e])int main()
{
    scanf("%d%d",&n,&m);
    for (int i=1;i<=n;++i) scanf("%lf",&c[i]);
    for (int i=1;i<=m;++i)
    {
        scanf("%d",&k);
        while (k--)
        {
            scanf("%d%d",&l,&r);
            for (int j=l;j<=r;++j) ++a[i][j];
        }
        scanf("%lf",&b[i]);
    }
    simplex();
    printf("%.0lf\n",ans);
}