最长公共子序列及动态规划问题

答案写的最简便以理解的

https://blog.csdn.net/Bob__yuan/article/details/99690889

除了返回个数，要返回字符串的方法

int i = len1, j = len2;
vector> dp = lcs;
while (i != 0 && j != 0) {
if (dp[i][j] == dp[i - 1][j]) i--;
else if (dp[i][j] == dp[i][j - 1]) j--;
else {
str.push_back(text1[i - 1]);
i--;
j--;
}
}

dp分析的

https://www.cnblogs.com/wkfvawl/p/9362287.html

https://blog.csdn.net/trochiluses/article/details/37966729