解析多json组成的字符串

{"result":0,"num":1,"contents":[{"friendID":8,"familyID":4,"friendName":"8978","isActive":1,"createTime":"2014/03/04 17:23:42"}]}
{"result":23,"num":1,"contents":[{"type":4,"content":null,"sendTime":"2014/03/04 19:26:26","senderId":1,"nickName":"11"}]}

//String str = "{\"result\":0,\"num\":1,\"contents\":[{\"friendID\":8,\"familyID\":4,\"friendName\":\"8978\",\"isActive\":1,\"createTime\":\"2014/03/04 17:23:42\"}]}{\"result\":23,\"num\":1,\"contents\":[{\"type\":4,\"content\":null,\"sendTime\":\"2014/03/04 19:26:26\",\"senderId\":1,\"nickName\":\"11\"}]}" ;
						//Log.e("old",str);
						if(null == str){
							return ;
						}
						boolean isContain = str.contains("}{") ; // 是否包含了很多json
						if(isContain){// 包含了很多json，需要拆分，分开解析
							String[] jsons = str.split("[}][{]") ;
							if(null == jsons)
								return ;
							for(int i=0 ;i iter = json.keys();
										String key = null ;
										String value = null ;
										while(iter.hasNext()){
											key = iter.next() ;
											value = json.getString(key) ;
											LogUtil.e("findFamilyFriends", key + " = " + value) ;
										} 
									}
								} catch (JSONException e) {
									e.printStackTrace();
								}
								
							}
						}else{
							JSONObject jsonObject =  null;
							try {
								jsonObject = new JSONObject(str);
								String result = jsonObject.optString("result") ;
								int num = jsonObject.optInt("num") ;
								LogUtil.e("findFamilyFriends", "result = " + result+" ,num = " + num) ;
								JSONArray jsonArray = jsonObject.getJSONArray("contents");
								if((null == jsonArray) && (jsonArray.length() < 0)){
									LogUtil.e("findFamilyFriends", "no contents!") ;
									return ;
								}
								
								for(int i=0 ;i iter = json.keys();
									String key = null ;
									String value = null ;
									while(iter.hasNext()){
										key = iter.next() ;
										value = json.getString(key) ;
										LogUtil.e("findFamilyFriends", key + " = " + value) ;
									} 
								}
							} catch (JSONException e) {
								e.printStackTrace();
							}
						}
					}