杭电oj 1004

先看题目

Let the Balloon Rise

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 94800    Accepted Submission(s): 36201

Problem Description

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

This year, they decide to leave this lovely job to you.

 

Input

Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.

A test case with N = 0 terminates the input and this test case is not to be processed.

 

Output

For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.

 

Sample Input

5 green red blue red red 3 pink orange pink 0

 

Sample Output

red pink

我的思路就是记录下每种颜色气球的数量，然后遍历找到最大的。很笨的办法

#include 
#include 
using namespace std;
typedef struct
{
	string col;
	int number;
}result;
int main()
{
	result res[100];
	int number;
	string maxColor;
	int maxNumber;
	string color;
	int count;
	bool flag;
	int i,j;
	cin>>number;
	while(number!=0)
	{
		flag=false;
		count=0;
		for(i=0;i>color;
			for(j=0;jmaxNumber)
			{
				maxNumber=res[i].number;
				maxColor=res[i].col;
			}
		}
		cout<>number;
		 
	}
	return 0;
}

ac了