LeetCode#648 Replace Words (week14)

week14

题目

In English, we have a concept called root, which can be followed by some other words to form another longer word - let’s call this word successor. For example, the root an, followed by other, which can form another word another.

Now, given a dictionary consisting of many roots and a sentence. You need to replace all the successor in the sentence with the root forming it. If a successor has many roots can form it, replace it with the root with the shortest length.

You need to output the sentence after the replacement.
LeetCode#648 Replace Words (week14)_第1张图片
Note:
The input will only have lower-case letters.
1 <= dict words number <= 1000
1 <= sentence words number <= 1000
1 <= root length <= 100
1 <= sentence words length <= 1000

原题地址:https://leetcode.com/problems/replace-words/description/

解析

题目给出一个数组dict作为存放字典中的字符串,给定一个字符串sentence,要求将sentence以空格分解为子字符串,如果某个子字符串a以dict中的某个字符串b为开头,称b为a的root,用b代替sentence中对应的a,最后将sentence中的子字符串重新连接为一个字符串
大致思路是先将sentence按空格分割为子字符串并存放在数组中,对于每个子字符串,查找dict中是否有字符串是其root,有则以之代替,最后用数组中的字符串及空格重新拼接成新的字符串

代码

class Solution {
public:
    string replaceWords(vector<string>& dict, string sentence) {
        vector<string> words;
        spilt(sentence, words);
        replace(dict, words);

        string rel = "";
        for (int i = 0; i < words.size(); ++i) {
            rel += words[i];
            rel += " ";
        }
        return rel.substr(0,rel.size() - 1);
    }
    /*将字符串按空格分解*/
    void spilt(string sentence, vector<string>& words) {
        int len = sentence.size();
        int begin = 0, end = 0;
        int last_blank = -1;
        while (end < len) {
            /*每找到一个空格生成一个子串*/
            if (sentence[end] != ' ') {
                ++end;
            }
            else {
                last_blank = end;
                string ss = sentence.substr(begin, end - begin);
                words.push_back(ss);
                begin = end + 1;
                end = begin;
            }
        }
        /*最后一个子串后面没有空格,单独处理*/
        if (last_blank != -1) {
            string s = sentence.substr(last_blank + 1, len - last_blank);
            words.push_back(s);
        }

    }
    /*对于words中的每个字符串,在dict中查找root并替代*/
    void replace(vector<string>& dict, vector<string>& words) {
        int len = words.size();
        for (int i = 0; i < len; ++i) {
            for (int j = 0; j < dict.size(); ++j) {
                if (isRoot(dict[j], words[i])) {
                    words[i] = dict[j];
                    break;
                }
            }
        }
    }
    /*比较得到字符串str是否以sub开头*/
    bool isRoot(string sub, string str) {
        int k = 0, j = 0;
        while (str[k] == sub[j] && k < str.size() - 1) {
            if (j == sub.size() - 1) {
                return true;
            }
            ++k;
            ++j;
        }
        return false;
    }
};

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