http://acm.whu.edu.cn/land/problem/detail?problem_id=1564
思路：先把串复制一遍，在末尾补个标记，后缀数组跑一下，扫一遍就ok了（过滤后缀在后半部分的）。
1 #pragma comment(linker, "/STACK:10240000,10240000") 2 3 #include 4 #include 5 #include 6 #include 7 #include 8 #include 9 #include 10 #include 11 #include 12 #include 13 #include 14 #include 15 #include <set> 16 #include 17 #include 18 #include 19 #include 20 #include 21 22 using namespace std; 23 24 #define mem0(a) memset(a, 0, sizeof(a)) 25 #define mem_1(a) memset(a, -1, sizeof(a)) 26 #define lson l, m, rt << 1 27 #define rson m + 1, r, rt << 1 | 1 28 #define define_m int m = (l + r) >> 1 29 #define rep_up0(a, b) for (int a = 0; a < (b); a++) 30 #define rep_up1(a, b) for (int a = 1; a <= (b); a++) 31 #define rep_down0(a, b) for (int a = b - 1; a >= 0; a--) 32 #define rep_down1(a, b) for (int a = b; a > 0; a--) 33 #define all(a) (a).begin(), (a).end() 34 #define lowbit(x) ((x) & (-(x))) 35 #define constructInt4(name, a, b, c, d) name(int a = 0, int b = 0, int c = 0, int d = 0): a(a), b(b), c(c), d(d) {} 36 #define constructInt3(name, a, b, c) name(int a = 0, int b = 0, int c = 0): a(a), b(b), c(c) {} 37 #define constructInt2(name, a, b) name(int a = 0, int b = 0): a(a), b(b) {} 38 #define pchr(a) putchar(a) 39 #define pstr(a) printf("%s", a) 40 #define sstr(a) scanf("%s", a) 41 #define sint(a) scanf("%d", &a) 42 #define sint2(a, b) scanf("%d%d", &a, &b) 43 #define sint3(a, b, c) scanf("%d%d%d", &a, &b, &c) 44 #define pint(a) printf("%d\n", a) 45 #define test_print1(a) cout << "var1 = " << a << endl 46 #define test_print2(a, b) cout << "var1 = " << a << ", var2 = " << b << endl 47 #define test_print3(a, b, c) cout << "var1 = " << a << ", var2 = " << b << ", var3 = " << c << endl 48 49 typedef double db; 50 typedef long long LL; 51 typedef pair<int, int> pii; 52 typedef multiset<int> msi; 53 typedef set<int> si; 54 typedef vector<int> vi; 55 typedef map<int, int> mii; 56 57 const int dx[8] = {0, 0, -1, 1, 1, 1, -1, -1}; 58 const int dy[8] = {-1, 1, 0, 0, 1, -1, 1, -1 }; 59 const int maxn = 1e6 + 7; 60 const int md = 1e9 + 7; 61 const int inf = 1e9 + 7; 62 const LL inf_L = 1e18 + 7; 63 const double pi = acos(-1.0); 64 const double eps = 1e-6; 65 66 template<class T>T gcd(T a, T b){return b==0?a:gcd(b,a%b);} 67 template<class T>bool max_update(T &a,const T &b){if(b>a){a = b; return true;}return false;} 68 template<class T>bool min_update(T &a,const T &b){if(breturn true;}return false;} 69 template<class T>T condition(bool f, T a, T b){return f?a:b;} 70 template<class T>void copy_arr(T a[], T b[], int n){rep_up0(i,n)a[i]=b[i];} 71 int make_id(int x, int y, int n) { return x * n + y; } 72 73 74 /// 构造后缀数组的之前，需要在原串末尾加个空字符(比其它字符都小即可)， 75 ///把这个空字符看成原串的一部分（这样在比较的时候到这个位置一定可以分个大小）, 76 ///所以n应该为原序列长度+1，后缀n-1是"空串"，sa[0]总是n-1。 77 struct SuffixArray { 78 int n; 79 int arr[6][maxn]; 80 int *sa, *x, *y, *c, *rnk, *height; 81 SuffixArray() { sa = arr[0]; x = arr[1]; y = arr[2]; c = arr[3]; rnk = arr[4]; height = arr[5]; } 82 void resize(int nn) { n = nn; mem0(arr[0]); } 83 void build_sa(int s[], int m) { // m is biger than the max value of char 84 rep_up0(i, m) c[i] = 0; 85 rep_up0(i, n) c[x[i] = s[i]]++; 86 rep_up1(i, m - 1) c[i] += c[i - 1]; 87 rep_down0(i, n) sa[--c[x[i]]] = i; 88 for (int k = 1; k <= n; k <<= 1) { 89 int p = 0; 90 for (int i = n - k; i < n; i++) y[p++] = i; 91 rep_up0(i, n) if (sa[i] >= k) y[p++] = sa[i] - k; 92 rep_up0(i, m) c[i] = 0; 93 rep_up0(i, n) c[x[y[i]]]++; 94 rep_up0(i, m) c[i] += c[i - 1]; 95 rep_down0(i, n) sa[--c[x[y[i]]]] = y[i]; 96 swap(x, y); 97 p = 1; x[sa[0]] = 0; 98 for (int i = 1; i < n; i++) { 99 x[sa[i]] = y[sa[i - 1]] == y[sa[i]] && y[sa[i - 1] + k] == y[sa[i] + k]? p - 1 : p++; 100 } 101 if (p >= n) break; 102 m = p; 103 } 104 } 105 void build_height(int s[]) { 106 int k = 0; 107 rep_up0(i, n) rnk[sa[i]] = i; 108 rep_up0(i, n) { 109 if (k) k--; 110 int j = sa[rnk[i] - 1]; 111 while (s[i + k] == s[j + k]) k++; 112 height[rnk[i]] = k; 113 } 114 } 115 }; 116 117 SuffixArray sa; 118 char s[maxn]; 119 int ss[maxn]; 120 121 int main() { 122 //freopen("in.txt", "r", stdin); 123 int n, k; 124 while (cin >> n >> k) { 125 scanf("%s", s); 126 rep_up0(i, n) ss[i + n] = ss[i] = s[i]; 127 ss[2 * n] = 0; 128 int len = n * 2 + 1; 129 sa.resize(len); 130 sa.build_sa(ss, 128); 131 int cnt = 0; 132 for (int i = 1; i < len; i++) { 133 if (sa.sa[i] < n) { 134 cnt++; 135 if (cnt == k) { 136 int x = sa.sa[i]; 137 if (x == 0) x = n; 138 cout << x << endl; 139 break; 140 } 141 } 142 } 143 } 144 return 0; 145 }
转载于:https://www.cnblogs.com/jklongint/p/4446215.html
