2019独角兽企业重金招聘Python工程师标准>>> 
SELECT (
select count(*) from BORROW_LIST
where DELETE_FLAG=0 and BORROW_ID=c.BORROW_ID
group by LOAN_USER_ID
) as cyrs_COUNT，sum(...) ....
from BORROW c
这样查出来的数量是多个结果，无法对应其他字段 ，并且数据 并不是总人数
LOAN_USER_ID USER_NAME ..................
1 啊啊啊
23 啵啵啵
23 纯纯粹粹
35 点点滴滴
但是如果写成下面这样 的话 是无法取到c.BORROW_ID 的
SELECT (select count(*) from (
select count(*) from BORROW_LIST
where DELETE_FLAG=0 and BORROW_ID=c.BORROW_ID
group by LOAN_USER_ID ) d
) as cyrs_COUNT，sum(...) ....
from BORROW c
那么只有这样了~~~~~换个方法
SELECT (
select count(distinct(LOAN_USER_ID)) from BORROW_LIST
where DELETE_FLAG=0 and BORROW_ID=c.BORROW_ID
) as cyrs_COUNT，sum(...) ....
from BORROW c
这样就不用再套一层子查询了