Atlantis(线段树)

http://acm.hdu.edu.cn/showproblem.php?pid=1542

参考了某某大牛的代码。确实代码飘逸,给上注释,怕自己忘了;

Atlantis

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10210    Accepted Submission(s): 4352


Problem Description
There are several ancient Greek texts that contain descriptions of the fabled island Atlantis. Some of these texts even include maps of parts of the island. But unfortunately, these maps describe different regions of Atlantis. Your friend Bill has to know the total area for which maps exist. You (unwisely) volunteered to write a program that calculates this quantity.
 


 

Input
The input file consists of several test cases. Each test case starts with a line containing a single integer n (1<=n<=100) of available maps. The n following lines describe one map each. Each of these lines contains four numbers x1;y1;x2;y2 (0<=x1
The input file is terminated by a line containing a single 0. Don’t process it.
 


 

Output
For each test case, your program should output one section. The first line of each section must be “Test case #k”, where k is the number of the test case (starting with 1). The second one must be “Total explored area: a”, where a is the total explored area (i.e. the area of the union of all rectangles in this test case), printed exact to two digits to the right of the decimal point.

Output a blank line after each test case.
 


 

Sample Input
 
   
2 10 10 20 20 15 15 25 25.5 0
 


 

Sample Output
 
   
Test case #1 Total explored area: 180.00
 


 

Source
Mid-Central European Regional Contest 2000
 
/**从下到上枚举每一条边,对x建树,维护总的边在x轴的贡献**/
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
using namespace std;
const int SIZE=2e2+10;
const int maxn=500000;
const int Mod=1e8;
struct Line{
    double h,l,r;
    int f;
    bool operator<(const Line &other)const{
        return h>1;
        if(X[m]==key)return m;
        if(X[m]>1;
    if(L<=m)update(L,R,c,lson);
    if(R>m)update(L,R,c,rson);
    pushup(l,r,rt);
}
int main()
{
    int n;
    double x1,x2,y1,y2;
    int cas=1;
    while(scanf("%d",&n)&&n){
        for(int i=0;i
卡了好久

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