根据2个时间,分割各个月份

为什么80%的码农都做不了架构师?>>>   hot3.png

代码效果

2018-01-29至 2018-03-07

分割为

2018-01-29   2018-01-31

2018-02-01   2018-02-28

2018-03-01   2018-03-07

DateUtil 还有用到 http://feilong-core.mydoc.io/ 工具包

 

int i = 0;

while(true){

Date sdate = new Date();

Date edate = new Date();

if (i == 0) {

sdate = insurance.date_of_start;

edate = DateUtil.getLastDateOfThisMonth(insurance.date_of_start);

}else{

Date first_month  = DateUtil.getFirstDateOfThisMonth(insurance.date_of_start);

Date next_month = DateUtil.addMonth(first_month, i);

sdate = DateUtil.getFirstDateOfThisMonth(next_month);

edate = DateUtil.getLastDateOfThisMonth(next_month);

}

if (edate.after(insurance.date_of_end)) {

edate = insurance.date_of_end;

}

System.out.println("mon:"+(i+1));

System.out.println("sdate"+Util.dateformat(sdate, "yyyy-MM-dd"));

System.out.println("edate"+Util.dateformat(edate, "yyyy-MM-dd"));

i++;

System.out.println(edate.getTime()>=insurance.date_of_end.getTime());

if (edate.getTime()>=insurance.date_of_end.getTime()) {

break;

}

if (i>100) { //保险,防止死循环

break;

}

}

转载于:https://my.oschina.net/nbuu/blog/1632263

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