6.有n个整数，使其前面各数顺序向后移m个位置，最后m个数变成最前面的m个数...

a=[1,2,3,4,5,6,7]

m=4

last_m_numbers=a[-m:]

print last_m_numbers

front_numbers=a[:-m]

print front_numbers

print last_m_numbers+front_numbers

转载于:https://www.cnblogs.com/luo25236240/p/9255384.html