URAL 2037 Richness of binary words (回文子串,找规律)

Richness of binary words

题目链接:

http://acm.hust.edu.cn/vjudge/contest/126823#problem/B

Description


For each integer i from 1 to n, you must print a string s i of length n consisting of letters ‘a’ and ‘b’ only. The string s i must contain exactly i distinct palindrome substrings. Two substrings are considered distinct if they are different as strings.

Input


The input contains one integer n (1 ≤ n ≤ 2000).

Output


You must print n lines. If for some i, the answer exists, print it in the form “ i : s i” where s i is one of possible strings. Otherwise, print “ i : NO”.

Sample Input

input output
4
1 : NO
2 : NO
3 : NO
4 : aaaa


题意:


要求输出n个长度为n的字符串(只能放a或b):
要求Si中不同回文子串的个数恰为i.


题解:


本质就是找出一种构造方式使得回文子串个数不会再增加.
参考2015-ICPC合肥现场赛H题:
http://blog.csdn.net/snowy_smile/article/details/49870109
http://blog.csdn.net/keshuai19940722/article/details/49839359


代码:

#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#define LL long long
#define eps 1e-8
#define maxn 210000
#define mod 100000007
#define inf 0x3f3f3f3f
#define IN freopen("in.txt","r",stdin);
using namespace std;

int n;

int main(int argc, char const *argv[])
{
    //IN;

    while(scanf("%d", &n) != EOF)
    {
        if(n == 1) {
            printf("1 : a\n");
            continue;
        }
        if(n == 2) {
            printf("1 : NO\n");
            printf("2 : ab\n");
            continue;
        }

        if(n < 8) {
            for(int i=1; i

转载于:https://www.cnblogs.com/Sunshine-tcf/p/5746764.html

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