ZOJ 3866 Cylinder Candy

Cylinder Candy

Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge

 

Edward the confectioner is making a new batch of chocolate covered candy. Each candy center is shaped as a cylinder with radius r mm and height h mm.

 

The candy center needs to be covered with a uniform coat of chocolate. The uniform coat of chocolate is d mm thick.

 

You are asked to calcualte the volume and the surface of the chocolate covered candy.

 

 

 

Input

 

There are multiple test cases. The first line of input contains an integer T(1≤ T≤ 1000) indicating the number of test cases. For each test case:

 

There are three integers r, h, d in one line. (1≤ r, h, d ≤ 100)

 

Output

 

For each case, print the volume and surface area of the candy in one line. The relative error should be less than 10^-8.

 

Sample Input

 

2

1 1 1

1 3 5

 

Sample Output

 

32.907950527415 51.155135338077

1141.046818749128 532.235830206285

 

---

Author: ZHOU, Yuchen
Source: The 15th Zhejiang University Programming Contest

 

解题：Q神给的代码。。我不会积分啊，妈蛋

 

 1 #include <bits/stdc++.h>

 2 using namespace std;

 3 const double PI = acos(-1.0);

 4 int main(){

 5     int T;

 6     scanf("%d",&T);

 7     while(T--){

 8         double r,h,d;

 9         scanf("%lf%lf%lf",&r,&h,&d);

10         double s = 2*d*r*PI*PI + 2*(r*r+r*h+d*h+2*d*d)*PI;

11         double v = ((6*d*(d*d+r*r)-2*d*d*d)*PI + 3*r*d*d*PI*PI)/3 + (r+d)*(r+d)*h*PI;

12         printf("%.10f %.10f\n",v,s);

13     }

14     return 0;

15 }

View Code