1016 部分A+B（15 分）

#include
#include
#include
using namespace std;
string a, b;
int da, db;
typedef long long LL;
LL getnum(string s, int d)
{
    int ans = 0;
    for (int i = 0; i < s.length(); i++)
    {
        if (d == s[i] - '0')ans = ans * 10 + s[i] - '0';
    }
    return ans;
}
int main()
{
    cin >> a >> da >> b >> db;
    LL aa = getnum(a, da);
    LL bb = getnum(b, db);
    printf("%lld", aa + bb);
    return 0;
}