python算法
1、求三位数组合
四个数字能组成多少个互不相同且无重复数字的三位数？
lst = [3,6,2,7]
a = []
for i in lst:
for j in lst:
for k in lst:
if i != j and i != k and j != k:
a.append('{first} {secend} {third}' . format(first = i ,secend = j,third = k))
print('共有{count}个符合条件的数字'.format(count(len(a))))
2.生成矩阵
已知两个矩阵
lst_1 = [1,2,3,4]
lst_2 = ['a' , 'b' , 'c' ,'d']
a = []
for i in lst_1:
b = []
for j in lst_2:
value = str(i) + j
b.append(value)
a.append(b)
print(a)
3、列表偏移
已知列表lst = [1,2,3,4,5]
要求列表向右偏移两位后变成 lst = [4,5,1,2,3]
lst = [1, 2, 3, 4, 5]
count = int(input('输入偏移位数:'))
count %= len(lst)
print(count)
for i in range(count):
tmp = lst[-1]
for j in range(len(lst) - 1, 0, -1):
lst[j] = lst[j - 1]
lst[0] = tmp
print(lst)
pandas 基础
1、请利用多种方式转化为DataFrame，
1.
data = {'python': ['Pandas','numpy','flask','django',np.nan,'ElasticSearch','Pandas','pymysql'],
'score': ['1.0','2.0',np.nan,'4.0','5.0','6.0','7.0','10.0']}
df = pd.DataFrame(data)
df
2.
python = pd.Series(['Pandas','numpy','flask','django',np.nan,'ElasticSearch','Pandas','pymysql'],name= 'python')
python = python.to_frame()
score = pd.Series([1,2,np.nan,4,5,6,7,10],name = 'score')
score = score.to_frame()
data = pd.merge( python ,score , left_index= True, right_index=True)
data
2、提取含有字符串‘pandas’的行
df[df['python']== 'Pandas']
3、输出df的所有列名
df.columns
4、修改第二列列名为‘popularity’
df.rename(columns = {'score' : 'popularity'},inplace = True)
df
5、统计python列中每种模块包出现的次数
df['python'].value_counts()
6、将空值用上下值的平均值填充
df['popularity'] = df['popularity'].fillna(df['popularity'].interpolate())
df