#88 B

Input A B M

C = 1e9

The equation of p2 winning is (Na * C + Nb) % M == 0, that's (Na * (C % M) + Nb % M) % M == 0

Further, p1 controls M1 = (Na * (C % M)) % M, p2 controls M2 = Nb % M

If B >= M - 1,  P1 has no chances to win, because P2 can always pick a number makes (M2 + M1) % M == 0

If A == B == 0, the same result.

So, when B < M-1, then 1 <= M1 <= M-B-1 will make p1 wins.

#include <stdio.h>

int main() {
    int A, B, M, i, m, C = 1e9, d;
    scanf("%d %d %d", &A, &B, &M);

    int min = ( A < M ? A : M-1 );
    if( B >= M-1 || ( A == 0 && B == 0 ) ) {
        printf("2\n");
        return 0;
    }
    C = C % M;  // C = 1e9 % M
    m = 0;
    d = M-B;
    for( i=1;i<=min;i++ ) {
        m += C; // m is i * 1e9 % M
        if( m > M ) m -= M;
        if( m == 0 ) break; // because m starts from 0, if 0 again, means no chance.
        if( 1 <= m && m < d ) {
            printf("1 %.9d\n", i); 
            return 0;
        }
    }

    printf("2\n");

    return 0;
}