leetcode Top100(14)轮转数组

给定一个整数数组 nums,将数组中的元素向右轮转 k 个位置,其中 k 是非负数。

示例 1:

输入: nums = [1,2,3,4,5,6,7], k = 3
输出: [5,6,7,1,2,3,4]
解释:
向右轮转 1 步: [7,1,2,3,4,5,6]
向右轮转 2 步: [6,7,1,2,3,4,5]
向右轮转 3 步: [5,6,7,1,2,3,4]
package TOP11_20;


import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.stream.Collectors;

/**
 * 示例 1:
 * 

* 输入: nums = [1,2,3,4,5,6,7], k = 3 * 输出: [5,6,7,1,2,3,4] * 解释: * 向右轮转 1 步: [7,1,2,3,4,5,6] * 向右轮转 2 步: [6,7,1,2,3,4,5] * 向右轮转 3 步: [5,6,7,1,2,3,4] */ public class Top14 { public static int[] rotate(int[] nums, int k) { int length = nums.length; if (length == 0 || k == 0) { return nums; } int t = 0; if (k < length) { t = k; } if (k >= length) { t = k % length; } if (t == 0) { return nums; } int[] b = new int[t]; int[] c = new int[length - t]; for (int i = 0; i < t; i++) { b[t - i - 1] = nums[length - 1 - i]; } for (int i = 0; i < length - t; i++) { c[i] = nums[i]; } List result = new ArrayList<>(); result.addAll(Arrays.stream(b).boxed().collect(Collectors.toList())); result.addAll(Arrays.stream(c).boxed().collect(Collectors.toList())); int[] ress = result.stream().mapToInt(Integer::valueOf).toArray(); for (int i = 0; i < length; i++) { nums[i] = ress[i]; } return ress; } //用新的数组 private static void rotate2(int[] nums, int k) { int length = nums.length; k = k % nums.length; int[] newArray = new int[length]; if (length == 0 || k == 0) { return; } for (int i = 0; i < length; i++) { newArray[(i + k) % length] = nums[i]; } System.arraycopy(newArray, 0, nums, 0, length); } //翻转 这个想法有点牛 public static void rotate3(int[] nums, int k) { k %= nums.length; reverse(nums, 0, nums.length - 1); reverse(nums, 0, k - 1); reverse(nums, k, nums.length - 1); } public static void reverse(int[] nums, int start, int end) { while (start < end) { int temp = nums[start]; nums[start] = nums[end]; nums[end] = temp; start += 1; end -= 1; } } public static void main(String[] args) { int[] nums = {1, 2, 3, 4, 5, 6, 7}; int[] res = rotate(nums, 3); System.out.println(res); } }

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