java如何解析xml文件_java如何解析/读取xml文件

本文实例为大家分享了java解析/读取xml文件的方法，供大家参考，具体内容如下

XML文件

John

B

12

Mary

A

11

Simon

A

18

Java 代码:

package net.viralpatel.java.xmlparser;

import java.io.File;

import javax.xml.parsers.DocumentBuilder;

import javax.xml.parsers.DocumentBuilderFactory;

import org.w3c.dom.Document;

import org.w3c.dom.Element;

import org.w3c.dom.Node;

import org.w3c.dom.NodeList;

public class XMLParser {

public void getAllUserNames(String fileName) {

try {

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();

DocumentBuilder db = dbf.newDocumentBuilder();

File file = new File(fileName);

if (file.exists()) {

Document doc = db.parse(file);

Element docEle = doc.getDocumentElement();

// Print root element of the document

System.out.println("Root element of the document: "

+ docEle.getNodeName());

NodeList studentList = docEle.getElementsByTagName("student");

// Print total student elements in document

System.out

.println("Total students: " + studentList.getLength());

if (studentList != null && studentList.getLength() > 0) {

for (int i = 0; i < studentList.getLength(); i++) {

Node node = studentList.item(i);

if (node.getNodeType() == Node.ELEMENT_NODE) {

System.out

.println("=====================");

Element e = (Element) node;

NodeList nodeList = e.getElementsByTagName("name");

System.out.println("Name: "

+ nodeList.item(0).getChildNodes().item(0)

.getNodeValue());

nodeList = e.getElementsByTagName("grade");

System.out.println("Grade: "

+ nodeList.item(0).getChildNodes().item(0)

.getNodeValue());

nodeList = e.getElementsByTagName("age");

System.out.println("Age: "

+ nodeList.item(0).getChildNodes().item(0)

.getNodeValue());

}

}

} else {

System.exit(1);

}

}

} catch (Exception e) {

System.out.println(e);

}

}

public static void main(String[] args) {

XMLParser parser = new XMLParser();

parser.getAllUserNames("c:\\test.xml");

}

}

以上就是本文的全部内容，希望对大家的学习有所帮助。