杭电ACM-1.2.5 Balloon Comes!

Balloon Comes!

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 3364 Accepted Submission(s): 1103

Problem Description The contest starts now! How excited it is to see balloons floating around. You, one of the best programmers in HDU, can get a very beautiful balloon if only you have solved the very very very... easy problem. Give you an operator (+,-,*, / --denoting addition, subtraction, multiplication, division respectively) and two positive integers, your task is to output the result.  Is it very easy?  Come on, guy! PLMM will send you a beautiful Balloon right now! Good Luck!

Input Input contains multiple test cases. The first line of the input is a single integer T (0<T<1000) which is the number of test cases. T test cases follow. Each test case contains a char C (+,-,*, /) and two integers A and B(0<A,B<10000).Of course, we all know that A and B are operands and C is an operator.

Output For each case, print the operation result. The result should be rounded to 2 decimal places If and only if it is not an integer.

Sample Input 4 + 1 2 - 1 2 * 1 2 / 1 2

Sample Output 3 -1 2 0.50

 

 

代码：

#include<iostream>

#include<iomanip>

using namespace std;



int max(int num1,int num2)

{

     return num1>=num2?num1:num2;

}



int min(int num1,int num2)

{

     return num1<=num2?num1:num2;

}



int main()

{

     int n,a,b;

     char x;

     float c;

     cin>>n;

     while(n--&&n<1000)

     {

          cin>>x>>a>>b;

          if(max(a,b)<10000&&min(a,b)>0)

          {

               switch(x)

               {

                    case '+':

                         cout<<a+b<<endl;

                         break;

                    case '-':

                         cout<<a-b<<endl;

                         break;

                    case '*':

                         cout<<a*b<<endl;

                         break;

                    case '/':

                         c=(float)a/(float)b;

                         if(c==a/b)

                              cout<<a/b<<endl;

                         else

                              cout<<setiosflags(ios::fixed)<<setprecision(2)<<c<<endl;

                         break;

                    default:

                         break;

               }                   

          }

     }

}