先求出凸包,显然至少需要有一条边在凸包上(我只会感性理解不会证明QAQ),那么旋转卡壳一下就好了。
AC代码如下:
#include<iostream> #include<cstdio> #include<cstdlib> #include<cmath> #include<algorithm> #define eps 1e-12 #define N 50005 using namespace std; struct point{ double x,y; }a[N],q[N],t[4]; int n; point operator +(point u,point v){ u.x+=v.x; u.y+=v.y; return u; } point operator -(point u,point v){ u.x-=v.x; u.y-=v.y; return u; } point operator *(point u,double v){ u.x*=v; u.y*=v; return u; } double crs(point u,point v){ return u.x*v.y-u.y*v.x; } double dot(point u,point v){ return u.x*v.x+u.y*v.y; } double dist(point u,point v){ return sqrt(dot(v-u,v-u)); } bool cmp(point u,point v){ double t=crs(u-a[1],v-a[1]); return (t>eps || t>-eps && t<eps && dist(a[1],u)<dist(a[1],v)); } int main(){ scanf("%d",&n); int i,k; for (i=1; i<=n; i++) scanf("%lf%lf",&a[i].x,&a[i].y); k=1; for (i=2; i<=n; i++) if (a[i].y<a[k].y || fabs(a[i].y-a[k].y)<eps && a[i].x<a[k].x) k=i; swap(a[1],a[k]); sort(a+2,a+n+1,cmp); int tp=1; q[1]=a[1]; for (i=2; i<=n; i++){ while (tp>1 && crs(q[tp]-q[tp-1],a[i]-q[tp-1])<eps) tp--; q[++tp]=a[i]; } q[tp+1]=q[1]; int l=1,r=1; k=1; double ans=1e100; for (i=1; i<=tp; i++){ double len=dist(q[i],q[i+1]); while (crs(q[i+1]-q[i],q[k]-q[i])<crs(q[i+1]-q[i],q[k+1]-q[i])+eps) k=k%tp+1; while (dot(q[i+1]-q[i],q[r]-q[i])<dot(q[i+1]-q[i],q[r+1]-q[i])+eps) r=r%tp+1; if (i==1) l=r; while (dot(q[i+1]-q[i],q[l]-q[i])+eps>dot(q[i+1]-q[i],q[l+1]-q[i])) l=l%tp+1; double ls=dot(q[i+1]-q[i],q[l]-q[i])/len,rs=dot(q[i+1]-q[i],q[r]-q[i])/len; double ht=crs(q[i+1]-q[i],q[k]-q[i])/len,tmp=ht*(rs-ls); if (tmp<0) tmp=-tmp; if (tmp<ans){ ans=tmp; t[0]=q[i]+(q[i+1]-q[i])*(rs/len); t[1]=t[0]+(q[r]-t[0])*(ht/dist(q[r],t[0])); t[2]=t[1]+(q[k]-t[1])*((rs-ls)/dist(q[k],t[1])); t[3]=t[0]+t[2]-t[1]; } } printf("%.5f\n",ans); k=0; for (i=1; i<4; i++) if (t[i].y<t[k].y || fabs(t[i].y-t[k].y)<eps && a[i].x<a[k].x) k=i; for (i=0; i<4; i++,k=(k+1)%4) printf("%.5f %.5f\n",t[k].x,t[k].y); return 0; }
by lych
2016.4.14