【DP】 ZOJ 3802 Easy 2048 Again

这道题简直不能忍。。。如果不用滚动数组初始化memset会超时。。改for就行了。。出题人写的是滚动数组。。这样卡初始化简直不能忍。。。

#include <iostream>  
#include <queue>  
#include <stack>  
#include <map>  
#include <set>  
#include <bitset>  
#include <cstdio>  
#include <algorithm>  
#include <cstring>  
#include <climits>  
#include <cstdlib>
#include <cmath>
#include <time.h>
#define maxn 505
#define maxm 40005
#define eps 1e-10
#define mod 1000000007
#define INF 999999999
#define lowbit(x) (x&(-x))
#define mp mark_pair
#define ls o<<1
#define rs o<<1 | 1
#define lson o<<1, L, mid  
#define rson o<<1 | 1, mid+1, R  
typedef long long LL;
//typedef int LL;
using namespace std;
LL powmod(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base%mod;base=base*base%mod;b/=2;}return res;}
void scanf(int &__x){__x=0;char __ch=getchar();while(__ch==' '||__ch=='\n')__ch=getchar();while(__ch>='0'&&__ch<='9')__x=__x*10+__ch-'0',__ch = getchar();}
LL gcd(LL _a, LL _b){if(!_b) return _a;else return gcd(_b, _a%_b);}
// head

int num[maxn];
int dp[maxn][10000];
int n;
void read(void)
{
	scanf("%d", &n);
	for(int i = 1; i <= n; i++) scanf("%d", &num[i]);
}
void work(void)
{
	for(int i = 0; i <= n; i++)
		for(int j = 0; j < (1<<13); j++)
			dp[i][j] = -1;
	dp[0][0] = 0;
	for(int i = 0; i < n; i++)
		for(int j = 0; j < (1<<13); j++) {
			if(dp[i][j] == -1) continue;
			dp[i+1][j] = max(dp[i+1][j], dp[i][j]);
			int tmp = num[i+1]-1;
			if(tmp & j) dp[i+1][num[i+1]] = max(dp[i+1][num[i+1]], dp[i][j] + num[i+1]);
			else if(num[i+1] & j) {
				int res = 0, t = num[i+1];
				while(t & j) t <<= 1, res += t;
				dp[i+1][num[i+1] + j] = max(dp[i+1][num[i+1] + j], dp[i][j] + num[i+1] + res);
			}
			else dp[i+1][num[i+1] + j] = max(dp[i+1][num[i+1] + j], dp[i][j] + num[i+1]);
		}
	int ans = 0;
	for(int i = 0; i < (1<<13); i++) ans = max(ans, dp[n][i]);
	printf("%d\n", ans);
}
int main(void)
{
	int _;
	while(scanf("%d", &_)!=EOF) {
		while(_--) {
			read();
			work();
		}
	}
	return 0;
}


你可能感兴趣的:(ZOJ)