Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
, return true.
Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
Note:
You may assume both s and t have the same length.
public class Solution { public boolean isIsomorphic(String s, String t) { if(s == null && t == null) return true; if(s == null || t == null) return false; Map<Character, Character> map1 = new HashMap<>(); Map<Character, Character> map2 = new HashMap<>(); for(int i = 0; i < s.length(); i++){ char sChar = s.charAt(i); char tChar = t.charAt(i); if(!map1.containsKey(sChar)){ map1.put(sChar, tChar); }else{ if(tChar != map1.get(sChar)){ return false; } } if(!map2.containsKey(tChar)){ map2.put(tChar, sChar); }else{ if(sChar != map2.get(tChar)){ return false; } } } return true; } }
注意: 要求双向对应, 比如 ‘ab’ 对应 ‘aa’应该返回false, 所以用了两个hashmap