#leetcode#Isomorphic Strings


Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg""add", return true.

Given "foo""bar", return false.

Given "paper""title", return true.

Note:
You may assume both s and t have the same length.


public class Solution {
    public boolean isIsomorphic(String s, String t) {
        if(s == null && t == null)
            return true;
        if(s ==  null || t == null)
            return false;
        
        Map<Character, Character> map1 = new HashMap<>();
        Map<Character, Character> map2 = new HashMap<>();
        
        for(int i = 0; i < s.length(); i++){
            char sChar = s.charAt(i);
            char tChar = t.charAt(i);
            
            if(!map1.containsKey(sChar)){
                map1.put(sChar, tChar);
            }else{
                if(tChar != map1.get(sChar)){
                    return false;
                }
            }
            
            if(!map2.containsKey(tChar)){
                map2.put(tChar, sChar);
            }else{
                if(sChar != map2.get(tChar)){
                    return false;
                }
            }
        }
        return true;
    }
}


注意: 要求双向对应, 比如 ‘ab’ 对应 ‘aa’应该返回false, 所以用了两个hashmap

你可能感兴趣的:(LeetCode)