http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=3146
There is a bag-like data structure, supporting two operations:
1 x
Throw an element x into the bag.
2
Take out an element from the bag.
Given a sequence of operations with return values, you're going to guess the data structure. It is a stack (Last-In, First-Out), a queue (First-In, First-Out), a priority-queue (Always take out larger elements first) or something else that you can hardly imagine!
There are several test cases. Each test case begins with a line containing a single integer n (1<=n<=1000). Each of the next n lines is either a type-1 command, or an integer 2 followed by an integer x. That means after executing a type-2 command, we get an element x without error. The value of x is always a positive integer not larger than 100. The input is terminated by end-of-file (EOF). The size of input file does not exceed 1MB.
For each test case, output one of the following:
stack
It's definitely a stack.
queue
It's definitely a queue.
priority queue
It's definitely a priority queue.
impossible
It can't be a stack, a queue or a priority queue.
not sure
It can be more than one of the three data structures mentioned above.
6 1 1 1 2 1 3 2 1 2 2 2 3 6 1 1 1 2 1 3 2 3 2 2 2 1 2 1 1 2 2 4 1 2 1 1 2 1 2 2 7 1 2 1 5 1 1 1 3 2 5 1 4 2 4
queue not sure impossible stack priority queue
#include <stdio.h> #include <string.h> #include <iostream> #include <algorithm> #include <queue> #include <stack> using namespace std; queue<int>q; stack<int>s; priority_queue<int>p; int n,x,y; int main() { while(~scanf("%d",&n)) { while(!q.empty()) q.pop(); while(!s.empty()) s.pop(); while(!p.empty()) p.pop(); int flagq=1,flagp=1,flags=1; int a; for(int i=0; i<n; i++) { scanf("%d%d",&x,&y); if(x==1) { q.push(y); p.push(y); s.push(y); } else { if(flagq==1) { if(q.empty()) { flagq=0; } else { a=q.front(); q.pop(); if(a!=y) flagq=0; } } if(flagp==1) { if(p.empty()) { flagp=0; } else { a=p.top(); p.pop(); if(a!=y) flagp=0; } } if(flags==1) { if(s.empty()) { flags=0; } else { a=s.top(); s.pop(); if(a!=y) flags=0; } } } } if(flagq&&!flagp&&!flags) { printf("queue\n"); continue; } if(!flagq&&flagp&&!flags) { printf("priority queue\n"); continue; } if(!flagq&&!flagp&&flags) { printf("stack\n"); continue; } if(!flagq&&!flagp&&!flags) { printf("impossible\n"); continue; } printf("not sure\n"); } return 0; }