Counting

Counting Bits

Givenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1’sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,1,2,1,2].Followup:Itisve
xinyuehuixin·2016-05-08 11:00

Counting Bits 数字的二进制中1的个数

Givenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:For num=5 youshouldreturn [0,1,1,2,1,2].Followu
u010005161·2016-05-07 21:00

山东省第四届ACM大学生程序设计竞赛-Boring Counting（划分树-二分查找）

BoringCountingTimeLimit:3000ms  Memorylimit:65536K  有疑问？点这里^_^题目描述  InthisproblemyouaregivenanumbersequencePconsistingofNintegerandPi istheith elementinthesequence.Nowyoutaskistoansweralistofqueries,f
MIKASA3·2016-05-07 20:00

UVA 11401:Triangle Counting

TriangleCounting  Youaregiven n rodsoflength1,2…,n.Youhavetopickany3ofthem&buildatriangle.Howmanydistincttrianglescanyoumake?Notethat,twotriangleswillbeconsidereddifferentiftheyhaveatleast1pairofarmsw
qq_28954601·2016-05-06 19:00

【SDUT OJ 2610】 Boring Counting（主席树）

【SDUTOJ2610】BoringCounting（主席树）BoringCountingTimeLimit:3000msMemorylimit:65536K有疑问？点这里^_^题目描述InthisproblemyouaregivenanumbersequencePconsistingofNintegerandPiistheithelementinthesequence.Nowyoutaskist
A_LeiQ·2016-05-04 20:55

【SDUT OJ 2610】 Boring Counting（主席树）

【SDUTOJ2610】BoringCounting（主席树）BoringCountingTimeLimit:3000ms  Memorylimit:65536K  有疑问？点这里^_^题目描述  InthisproblemyouaregivenanumbersequencePconsistingofNintegerandPi istheith elementinthesequence.Nowyo
ChallengerRumble·2016-05-04 20:00

Boring Counting——【SDUT2610】主席树

BoringCountingTimeLimit:3000msMemorylimit:65536K题目描述InthisproblemyouaregivenanumbersequencePconsistingofNintegerandPiistheithelementinthesequence.Nowyoutaskistoansweralistofqueries,foreachquery,please
huayunhualuo·2016-05-04 18:00

报错：Xcode 7.3 cannot create __weak reference in file using manual reference counting

在使用__weak的时候报错 Xcode7.3cannotcreate__weakreferenceinfileusingmanualreferencecounting解决方法一：设置项目中的buildsetting->AppleLLVM7.1-Language-ObjectiveC->WeakReferencesinManualRetainReleaseYES解决方法二：用__unsafe_un
lllkey·2016-05-04 15:00

ZOJ 3944 People Counting（思维/技巧/模拟）

题目：http://www.icpc.moe/onlinejudge/showProblem.do?problemCode=3944代码：#include #include usingnamespacestd; charmaps[105][105]; charbase[105][105]={{'.','O','.'},{'/','|','\\'},{'(','.',')'}}; inth,w
qq_32473657·2016-05-04 13:00

POJ-2386Lake Counting，搜索题。。

LakeCountingTimeLimit: 1000MS MemoryLimit: 65536K     DescriptionDuetorecentrains,waterhaspooledinvariousplacesinFarmerJohn'sfield,whichisrepresentedbyarectangleofNxM(1 #include #include #include #inc
NYIST_TC_LYQ·2016-05-04 13:00

leetcode Counting Bits

点击打开链接在是2的幂的时候个数为1。在这之后，每次都会从头开始在增加现在这个数的大小。相当于从1再走一遍。#include #include usingnamespacestd; intmain() { intnum=8; vectorres=vector(num+1,0); intpow2=1,before=1; for(inti=1;i<=num;i++){ if(i==pow2){
bleuesprit·2016-05-03 21:00

LeetCode:Counting Bits

CountingBits   TotalAccepted: 18290 TotalSubmissions: 32984 Difficulty: MediumGivenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1's intheirbinaryrepresentatio
itismelzp·2016-04-29 17:00

Bloom Filter 算法简介 (增加 Counting Bloom Filter 内容)

前言   本博客内曾已经整理过十道海量数据处理面试题与十个方法大总结。接下来，本博客内会重点分析那些海量数据处理的方法，并重写十道海量数据处理的面试题。如果有任何问题，欢迎不吝指正。谢谢。一、什么是BloomFilter   BloomFilter是一种空间效率很高的随机数据结构，它的原理是，当一个元素被加入集合时，通过K个Hash函数将这个元素映射成一个位阵列（Bitarray）中的K个点，把它
bigtree_3721·2016-04-27 21:00

ACM刷题之ZOJ———— People Counting

PeopleCountingTimeLimit:2Seconds    MemoryLimit:65536KBInaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphotoforthem.Every
xiaofeng187·2016-04-27 15:00

ZOJ 3944 People Counting（模拟+暴力）

PeopleCountingTimeLimit:2SecondsMemoryLimit:65536KBInaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphotoforthem.Everyonew
__铭·2016-04-27 11:51

ZOJ 3944 People Counting（模拟+暴力）

PeopleCountingTimeLimit:2SecondsMemoryLimit:65536KBInaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphotoforthem.Everyonew
Code_KK·2016-04-27 11:00

Xcode 7.3 cannot create __weak reference in file using manual reference counting解决方法

测试机更新到ios9.3后xcode不得不更新了。下载了xcode7.3后，运行项目后报错，只好查了查，最终找到了结果更新7.3后编译可能会出现这个错。官方的回答在这里：https://forums.developer.apple.com/thread/38934还有一个结果如下：1doesn’tapplytoMRR,becauseyoujustdon’tretainthevariableanyw
Lu_Ca·2016-04-27 10:00

【ZOJ3944 The 13th Zhejiang Provincial Collegiate Programming ContestI】【简单模拟】People Counting 照片人数统计 人

PeopleCountingTimeLimit:2Seconds    MemoryLimit:65536KBInaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphotoforthem.Every
snowy_smile·2016-04-26 18:00

ZOJ Problem Set - 3944（interesting people counting））

【链接】：clickhere~~【题意】：PeopleCountingTimeLimit:2SecondsMemoryLimit:65536KBInaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeap
u013050857·2016-04-26 14:00

HDU 5439 Aggregated Counting

AggregatedCountingTimeLimit:1500/1000MS(Java/Others)    MemoryLimit:131072/131072K(Java/Others)TotalSubmission(s):672    AcceptedSubmission(s):305ProblemDescriptionAggregatedCountingMeetup(ACM)isaregu
u013097262·2016-04-25 10:00

zoj-3944-People Counting

InaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphotoforthem.Everyonewasinthephotoandnoonewascompletelyblocked.Eachperson
Ypopstar·2016-04-24 21:00

acm/icpc 浙江省赛 People Counting

水题，但是比赛的时候没写出来，思路是对的，但是竞赛的那种环境下，静不下下来，改了很多次都改不对，诶，心态还是太差，要努力的还有很多啊。思路就是打一张相同大小的表，初始全部为0，当碰到头时，往下判断，如果是这个人身体的一部分，那就变为1，且cnt++，一次判断，感觉题目好水啊，当时身边的队伍都挂了紫色气球，就我们队没有，好可惜。#include #include usingnamespacestd;
qq_33901573·2016-04-24 20:00

ZOJ 3944-People Counting【模拟】（2016浙江省大学生程序设计竞赛）

PeopleCountingTimeLimit:2Seconds    MemoryLimit:65536KBInaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphotoforthem.Every
qq_29600137·2016-04-24 17:00

ZOJ-3944 People Counting From 第13届浙江省赛

ZOJ-3944PeopleCountingFr第13届浙江省赛TimeLimit:2SecondsMemoryLimit:65536KBInaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphot
no_alternantive·2016-04-24 09:00

zoj 3944 People Counting

InaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphotoforthem.Everyonewasinthephotoandnoonewascompletelyblocked.Eachperson
ACM__dongsheng·2016-04-23 23:12

zoj 3944 People Counting

InaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphotoforthem.Everyonewasinthephotoandnoonewascompletelyblocked.Eachperson
ACM__dongsheng·2016-04-23 23:00

ZOJ 3944 People Counting

PeopleCountingTimeLimit: 2Seconds     MemoryLimit: 65536KBInaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphotoforthem.Ev
jtjy568805874·2016-04-23 23:00

浙江省省赛2016同步赛I题_People Counting

I题链接点击打开链接题目意思是让你找出人的个数，每个人的形状告诉你了！并且在照片中，每个形状可以部分参与，，那么怎么正确的找出所有的人，，我的做法是从左向右，从上到下，，进行扫描，碰到人身体的某个部分的时候，将这个人身上的合法区域全变为'.'，并且ans++，就相当于统计了一个人，，扫描过后，，所有的人也就全部统计出来了！！#include #include #include #include #
yizhen_acmer·2016-04-23 23:00

poj1971 Parallelogram Counting

题意：给n个点，问能组成四边形平行四边形的个数（有可能有三点共线）思路：组成平行四边形的判定条件之中有一个是，对角线互相平分，即中点相同，所以直接n^2算出所有中点然后排序求就好了#include usingnamespacestd; constintmaxn=1005; structNode { intx,y; }mid[maxn*maxn],nodes[maxn]; boolcmp(Node
qq_21057881·2016-04-23 22:00

13届浙江省省赛 I题 People Counting

InaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphotoforthem.Everyonewasinthephotoandnoonewascompletelyblocked.Eachperson
qq_33638791·2016-04-23 21:00

浙江16年省赛 I题 People Counting

PeopleCountingTimeLimit: 2Seconds     MemoryLimit: 65536KBInaBG(dinnergathering)forZJUICPCteam,thecoacheswantedtocountthenumberofpeoplepresentattheBG.Theydidthatbyhavingthewaitresstakeaphotoforthem.Ev
zp___waj·2016-04-23 19:00

HDU 4358-I - Boring counting-dfs序+离线+树状数组/线段树

http://acm.hdu.edu.cn/showproblem.php?pid=4358题意：给你一颗树，n个节点，每个有其权值。给一个k。q次询问，每次询问以x为根节点的子树里，有多少种权值恰好出现次数为k。我们先求个dfs序，把树型结构转为线性数组。那么题目变成q次查询，每次查询区间L【x】，R【x】之间有多少个权值，出现的次数恰好为k而本题可以用离线的做法，先把所有查询的区间按右端点排序
viphong·2016-04-23 10:00

leetcode——338——Counting Bits

Givenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,1,2,1,2].Followup:Itisve
happyxuma1991·2016-04-21 19:00

sdut 2610:Boring Counting（第四届山东省省赛原题，划分树 + 二分）

BoringCountingTimeLimit:3000ms  Memorylimit:65536K  有疑问？点这里^_^题目描述  InthisproblemyouaregivenanumbersequencePconsistingofNintegerandPi istheith elementinthesequence.Nowyoutaskistoansweralistofqueries,f
aozil_yang·2016-04-21 00:00

Leetcode_338_Counting Bits

Givenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1’sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,1,2,1,2].Followup:Itisve
a7055117a·2016-04-20 18:00

LeetCode 第 338 题 (Counting Bits)

LeetCode第338题(CountingBits)Givenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1’sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0
liyuanbhu·2016-04-19 09:00

LLVM 与 Clang 介绍

6628543晚上听国软徐纪元学弟给我说起了他刚装上的MacLion操作系统，也说到了最近Apple推出的新版本的Xcode4.2在iOS4、iOS5程序开发中，加入了 automatic reference counting
songchunmin_·2016-04-18 17:00

Counting Sheep，B. Revenge of the Pancakes，C. Coin Jam，D. Fractiles（构造））

CountingSheepProblemBleatrixTrotterthesheephasdevisedastrategythathelpsherfallasleepfaster.First,shepicksanumber N.Thenshestartsnaming N,2× N,3× N,andsoon.Whenevershenamesanumber,shethinksaboutallofth
piaocoder·2016-04-18 15:00

Counting Bits

Givenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:For num=5 youshouldreturn [0,1,1,2,1,2].Followu
u012848330·2016-04-17 16:00

POJ Lake Counting

DescriptionDuetorecentrains,waterhaspooledinvariousplacesinFarmerJohn'sfield,whichisrepresentedbyarectangleofNxM(1 usingnamespacestd; charg[110][110]; intm,n; voiddfs(intx,inty){ g[x][y]='.'; for(inti
ShiWaiGaoRen12345·2016-04-17 14:00

Manual Reference Counting(简写MRC)

调回手动内存管理要有下面的操作引用计数器的基本操作 1.方法的基本使用 1>retain ：计数器+1，会返回对象本身 2>release ：计数器-1，没有返回值 3>retainCount ：获取当前的计数器 4>dealloc * 当一个对象要被回收的时候，就会调用 * 一定要调用[superdealloc]，这句调用要放在最后面  2.概念 1> 僵尸对象 ：所占用内存已经被回收的对象，僵
zcl那都不是事·2016-04-16 11:00

SGU 117 Counting（快速幂）

Description给出三个整数n,m,k，以及n个数a[i]，问这n个数中有多少个数满足a[i]^m%k=0Input第一行三个整数n,m,k，第二行n个整数a[i](1 #include usingnamespacestd; #definemaxn11111 intmod_pow(inta,intb,intp) { a%=p; intans=1; while(b) { if(b&1)ans=
V5ZSQ·2016-04-14 19:00

Counting Bits

分析打算用动态规划，所以先找x和x-1的规律：011011100101110111100010011010101001010010110100101001101111000f(x)表示x二进制表示中1的个数，m表示从右往左第一个0的位置（从0开始计数）。找数字x-1从右往左第一个0的位置m；f(x)=f（x-1）-m+1；我们认为7这样的数字的二进制表示中没有0，如果x-1的二进制表示中没有找到0
u010902721·2016-04-14 19:00

Counting Bits

比较容易想到的就是一个个数拿出来判断有几个1，判断时可以采用n&(n-1)来简化过程，不过时间复杂度明显就是O(n*sizeof(integer)).。此外可以采用动态规划来做，对于一个大于1的整数，其二进制至少有2位，假设是n位，可以把它分成前（n-1）位和最后1位分别统计。classSolution{ public: vectorcountBits(intnum){ vectorcnt(num
xl2432·2016-04-14 18:00

Proof of Cover's Function Counting Theorem

QuestionDescription:Supposewehave pointsin .Wehave partitionsofthese points intotwoclasses. Thequestionis:howmanythesepartitionsyieldlinearlyseparableclasses,i.e.wheretwoclassescanbeperfectlyseparated
vernice·2016-04-14 03:00

hdu 5439 Aggregated Counting（长春网络赛——找规律+二分）

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=5439AggregatedCountingTimeLimit:1500/1000MS(Java/Others)    MemoryLimit:131072/131072K(Java/Others)TotalSubmission(s):665    AcceptedSubmission(s):302Pro
qiqi_skystar·2016-04-13 21:00

lightoj 1148 - Mad Counting 简单数学

统计人数，询问了n个人每个人都回答了除了自己外支持同一球队的其他人数是多少，问最小有多少人。统计每个数字出现多少次，有a[i]+1个人回答的一样可以刚好组成一个团体...如果有剩余的话也是一个新的团体。#include usingnamespacestd; #definelllonglong #defineullunsignedlonglong #definemod1000007 #definei
azx736420641·2016-04-13 15:00

Counting Bits 解题报告

题目链接: https://leetcode.com/problems/counting-bits/Givenanonnegativeintegernumber num.Foreverynumbers 
qq508618087·2016-04-13 08:00

山东省第四届ACM大学生程序设计竞赛 Boring Counting 划分树

BoringCountingTimeLimit:3000ms  Memorylimit:65536K  有疑问？点这里^_^题目描述  InthisproblemyouaregivenanumbersequencePconsistingofNintegerandPi istheith elementinthesequence.Nowyoutaskistoansweralistofqueries,f
zp___waj·2016-04-12 19:00

leetcode(1)--338.Counting Bits

LeetCode338.CountingBitsGivenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:For num=5 youshouldreturn [0
momo462·2016-04-11 17:10
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