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Counting
leetcode(1)--338.
Counting
Bits
LeetCode338.CountingBitsGivenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,
momo462
·
2016-04-11 17:10
bits
移位
leetcode
leetcode
Counting
Leaves (30)
Afamilyhierarchyisusuallypresentedbyapedigreetree.Yourjobistocountthosefamilymemberswhohavenochild.InputEachinputfilecontainsonetestcase.Eachcasestartswithalinecontaining0&m5.map插入元素最简单的方法m[1]=0;CODE#
baidu_32157201
·
2016-04-11 09:00
pat
map应用
树的遍历
树的存储
[LeetCode]
Counting
Bits
Givenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:For num=5 youshouldreturn [0,1,1,2,1,2].Followu
zxdfc
·
2016-04-10 15:00
【GoogleCodeJam2016A】【暴力】
Counting
Sheep x的倍数从小向大增加直到出现0~9所有数的最小倍增终点
CountingSheepThiscontestisopenforpractice.Youcantryeveryproblemasmanytimesasyoulike,thoughwewon'tkeeptrackofwhichproblemsyousolve.Readthe Quick-StartGuide togetstarted.Smallinput7pointsSolveA-smallLar
snowy_smile
·
2016-04-10 12:00
暴力
Codejam
题库-google
Counting
Sheep
ProblemhereProblemBleatrixTrotterthesheephasdevisedastrategythathelpsherfallasleepfaster.First,shepicksanumberN.ThenshestartsnamingN,2×N,3×N,andsoon.Whenevershenamesanumber,shethinksaboutallofthedigit
LeongHouHeng
·
2016-04-10 11:00
算法
Codejam
uva 1225 Digit
Counting
#include #include #include usingnamespacestd; intchange(charch) { returnch-'0'; } intmain() { intt; cin>>t; while(t--) { intn; cin>>n; charch[10005]; inta[10]; memset(a,0,sizeof(a)); for(inti=1;i<=n;i
qq_33901573
·
2016-04-09 21:00
【POJ 2386】【Lake
Counting
】【DFS】
#include"iostream" usingnamespacestd; #defineMAX_map105 intnumx,numy; charmap[MAX_map][MAX_map]; intflag[MAX_map][MAX_map]; intdir[8][2]={{0,1},{1,1},{1,0},{0,-1},{-1,-1},{-1,0},{1,-1},{-1,1}}; voiddf
x123654p
·
2016-04-09 00:00
poj
DFS
计数排序
COUNTING
——SORT(A,B,k) let
ying847782627
·
2016-04-08 10:00
C语言
计数排序
算法+实现
《leetCode》:
Counting
Bits
题目Givenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1’sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,1,2,1,2].Followup:Itis
u010412719
·
2016-04-07 16:00
LeetCode
bit
count
leetcode笔记:
Counting
Bits
一.题目描述Givenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1’sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,1,2,1,2].Followup:
liyuefeilong
·
2016-04-07 15:00
LeetCode
位运算
C++
算法
bits
hdu4358Boring
counting
链接:http://acm.hdu.edu.cn/showproblem.php?pid=4358题意:给定一棵n个节点的树和k,每个点有点权,再给q个询问,每次询问:在以v为根的子树中有多少个数恰好出现了k次。分析:遇到子树问题,首先考虑到的就是dfs序,然后发现还有一个条件k。我的处理方式是:先离散化,然后构出dfs序,然后处理出in[],out[],lose[]数组,如果当前i中的数是某个出
Fsss_7
·
2016-04-06 20:00
Counting
Bits
想到了两种解法:(1)参照的是10进制数转换为2进制数的计算过程,代码如下:classSolution{ public: vectorcountBits(intnum){ vectorcounts; for(inti=0;icountBits(intnum){ vectorcounts; for(inti=0;i>1; } counts.push_back(count); } returncoun
qq_20581563
·
2016-04-06 19:00
LeetCode
Counting
Bits还有更好的解法吗
Givenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:For num=5 youshouldreturn [0,1,1,2,1,2].Followu
booirror
·
2016-04-06 18:00
LeetCode
106.
Counting
Bits
Givenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:For num=5 youshouldreturn [0,1,1,2,1,2].给定一个整数n
u010339647
·
2016-04-05 10:00
【LeetCode】
Counting
Bits(338)
1.DescriptionGivenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,1,2,1,2].2.
leesf
·
2016-04-03 08:00
PostgreSQL利用pg_rman进行备份
https://github.com/ossc-db/pg_rman.gitInitialized empty Git repository in /opt/pg_rman/.git/remote:
Counting
Foundation
·
2016-03-31 17:00
[置顶] Xcode 7.3 cannot create __weak reference in file using manual refrence
counting
SetBuildSettings->AppleLLVM7.1-Language-ObjectiveC->WeakReferencesinManualRetainReleasetoYES.去buildsettings输入weak,搜索出来AppleLLVM7.1-Language-ObjectiveC->Weak,然后把NO改为YES即可。原文链接http://stackoverflow.com/q
darongzi1314
·
2016-03-31 10:00
7.3
POJ 2386 Lake
Counting
LakeCountingTimeLimit: 1000MS MemoryLimit: 65536KTotalSubmissions: 26957 Accepted: 13541DescriptionDuetorecentrains,waterhaspooledinvariousplacesinFarmerJohn'sfield,whichisrepresentedbyarectangleofNxM
a2459956664
·
2016-03-30 12:00
leetcode--
Counting
Bits
Givenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1’sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,1,2,1,2].Followup:Itisve
a1b2c3d4123456
·
2016-03-30 11:00
LeetCode
Counting
Bits
Givenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:For num=5 youshouldreturn [0,1,1,2,1,2].首先,直接移动
a342500329a
·
2016-03-30 00:00
POJ 2396 Lake
Counting
(简单dfs)
LakeCountingTimeLimit: 1000MS MemoryLimit: 65536KTotalSubmissions: 26942 Accepted: 13532DescriptionDuetorecentrains,waterhaspooledinvariousplacesinFarmerJohn'sfield,whichisrepresentedbyarectangleofNxM
huatian5
·
2016-03-29 15:00
poj
DFS
POJ 2386 Lake
Counting
AC.很普通的DFS#include #include #include usingnamespacestd; charmap[105][105]; voiddfs(intline,intcol) { if(map[line][col]=='.'||map[line][col]==0)return; map[line][col]='.'; dfs(line-1,col-1); dfs(line
Kiritow
·
2016-03-28 20:00
poj
挑战程序设计竞赛
PAT (Advanced Level) Practise 1115
Counting
Nodes in a BST (30)
1115.CountingNodesinaBST(30)时间限制400ms内存限制65536kB代码长度限制16000B判题程序Standard作者CHEN,YueABinarySearchTree(BST)isrecursivelydefinedasabinarytreewhichhasthefollowingproperties:Theleftsubtreeofanodecontainsonl
jtjy568805874
·
2016-03-26 21:00
pat
LeetCode之338—-
Counting
Bits
最近上算法课上的有点心塞,所以感觉应该刷刷题来见见世面了,所以选择了LeetCode来做一点题目。LeetCode之338:Givenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1’sintheirbinaryrepresentationandreturnthemasa
Jung_zhang
·
2016-03-26 15:00
LeetCode
算法
Counting
Bits
TotalAccepted: 7119 TotalSubmissions: 12947 Difficulty: MediumGivenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheirbinaryrepresentationandreturnthemasa
EbowTang
·
2016-03-26 12:00
LeetCode
算法
技术
面试
回溯法
Counting
Bits
TotalAccepted: 7119 TotalSubmissions: 12947 Difficulty: MediumGivenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheirbinaryrepresentationandreturnthemasa
EbowTang
·
2016-03-26 12:00
LeetCode
算法
技术
面试
回溯法
Leetcode 338
Counting
Bits
338.CountingBitsMySubmissionsQuestionTotalAccepted: 7206 TotalSubmissions: 13074 Difficulty: MediumGivenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sinthei
u013575812
·
2016-03-25 23:00
Cannot create __weak reference in file using manual reference
counting
Xcode更新到7.3后会出现NSObject+MJProperty.h报Cannotcreate__weakreferenceinfileusingmanualreferencecounting错误信息。解决的办法:在BuildSettings--------->AplleLLVM7.1-Language-Objectibe-C------------->WeakReferenceInManua
sinat_29789455
·
2016-03-25 10:00
【UVA11401】Triangle
Counting
——计算方法
题意:从1,2,3⋯,n中选出三个不同的整数,使它们能够组成三角形,问有多少种方法分析:设最长的边为x,另外的两条边为y,z,所以y+z>x,所以z的范围为x>z>x−y当y=1时,x>z>x−1显然无解当y=2时,x>z>x−2z=x−1num=1当y=3时,x>z>x−3z=x−1,x−2num=2⋮当y=x−1时,x>z>1z=2,3,4⋯,x−1num=x−2所以当最长的边为x时,num=
huayunhualuo
·
2016-03-24 20:00
Counting
Bits (2 solutions)
CountingBitsGivenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:For num=5 youshouldreturn [0,1,1,2,
陆草纯
·
2016-03-24 19:00
第六天-ARC
. // #import #import "CZPerson.h" /* ARC automatic Reference
Counting
自动引用计数 A
ZZILY
·
2016-03-24 09:00
Counting
Bits
Givenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,1,2,1,2].Followup:Itisve
qdqade
·
2016-03-23 16:54
function
possibly
complexity
leetcode
Counting
Bits
Givenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:For num=5 youshouldreturn [0,1,1,2,1,2].Followu
u014568921
·
2016-03-21 21:00
LeetCode
leetcode 338 :
Counting
Bits :找规律&位运算
338.CountingBitsMySubmissionsQuestionTotalAccepted: 3211 TotalSubmissions: 5600 Difficulty: MediumGivenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheir
smileyk
·
2016-03-20 23:00
Counting
Bits
Givenanonnegativeintegernumber num.Foreverynumbers i intherange 0≤i≤num calculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:For num=5 youshouldreturn [0,1,1,2,1,2].Followu
brucehb
·
2016-03-19 23:00
[LeetCode]
Counting
Bits 计数位
Givenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1'sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,1,2,1,2].Followup:Itisv
Grandyang
·
2016-03-19 07:00
Counting
Bits [Difficulty: Medium]
题目:Givenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1’sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,1,2,1,2].Followup:Iti
Lnho2015
·
2016-03-18 18:00
LeetCode
算法
数组
二进制表示
Counting
Bits [Difficulty: Medium]
题目:Givenanonnegativeintegernumbernum.Foreverynumbersiintherange0≤i≤numcalculatethenumberof1’sintheirbinaryrepresentationandreturnthemasanarray.Example:Fornum=5youshouldreturn[0,1,1,2,1,2].Followup:Iti
Lnho2015
·
2016-03-18 18:00
LeetCode
算法
数组
二进制表示
object_setInstanceVariable is unavailable: not available in automatic reference
counting
mode
object_setInstanceVariableisunavailable:notavailableinautomaticreferencecountingmode翻译过来意思是object_setInstanceVariable不能再ARC的模式下使用解决方法:1.要么把XCODE项目改成MRC 2.要么换一个方法,本人测试,可以换objc_setAssociatedObject方法来替代
u013538542
·
2016-03-18 14:00
ios
xcode
HDU-1264
Counting
Squares(矩形面积并模板)
CountingSquaresTimeLimit:2000/1000MS(Java/Others) MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):1644 AcceptedSubmission(s):817ProblemDescriptionYourinputisaseriesofrectangles,oneperlin
acm_cxq
·
2016-03-17 22:00
ACM
HDU
UVA 11401Triangle
Counting
题意:求在1~n这n个数字中选出3个不同的数字能组成三角形的方案数。分析:《算法竞赛入门经典训练指南》数学基础例题2。代码:#include #include #include #include #include #include #include #include #include #include #include #include #pragmacomment(linker,"/STACK:
Fsss_7
·
2016-03-16 00:00
UVa 1225 - Digit
Counting
数字连一起,数数多少个1#include 2#include 3#include 4usingnamespacestd; 5intn,t,tmp; 6intmain() 7{ 8cin>>t; 9while(t--) 10{ 11cin>>n; 12intans[10]={0}; 13for(inti=1;i<=n;i++) 14{ 15tmp=i; 16while(
nicetomeetu
·
2016-03-14 15:00
UVa1225Digit
Counting
(计算1-n的整数0-9各出现了多少次,神级代码...)
UVA-1225DigitCountingTimeLimit:3000MS MemoryLimit:Unknown 64bitIOFormat:%lld&%lluSubmitStatusDescriptionTrungisboredwithhismathematicshomeworks.Hetakesapieceofchalkandstartswritingasequenceofconsecuti
hurmishine
·
2016-03-13 21:00
Counting
digit
Uva1225
git postBuffer
Imetthiserror.IhavetriedalotoftimesandIneversucceed.git clone https://github.com/cocos2d/cocos2d-x.git Cloning into 'cocos2d-x'... remote:
Counting
h2appy
·
2016-03-13 09:07
error
git
buffer
git postBuffer
Imetthiserror.IhavetriedalotoftimesandIneversucceed.git clone https://github.com/cocos2d/cocos2d-x.gitCloning into 'cocos2d-x'...remote:
Counting
h2appy
·
2016-03-13 09:07
error
buffer
git
杂文
【Usaco2015 dec 】
Counting
Haybales
题意农夫约翰打算重修他的农场。他有N块土地,连续排列成一行,标号为1…N。在每块土地上有任意数量的草堆。他可以发出三种指令:1)对一个连续区间的土地,每块土地增加相同数量的草堆。2)对一个连续区间的土地,输出其中最少的草堆数量。3)对一个连续区间的土地,输出草堆数量总数。第一行两个正整数,N(1≤N≤200,000)和Q(1≤Q≤100,000)。下一行是N个非负整数,最大100,000,表示每块
qq_32739495
·
2016-03-12 12:00
线段树
Usaco-2015
HDU 2952
Counting
Sheep
Description一个网格图,上下左右算一块问总共有几块Alogrithm搜索DFSCode#include #include #include usingnamespacestd; constintmaxh=100; constintmaxw=100; constintdx[4]={0,0,1,-1}; constintdy[4]={1,-1,0,0}; structP { intx,y;
YYecust
·
2016-03-09 20:00
UVa1225 Digit
Counting
本题不难,数组循环,简单打表自己太水,开始忽略了(n-1)和n的关系,n的各个数字出现情况只需要在n-1情况下考虑n就好了https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=3666#include #include #include #definemaxn1
sinat_19628145
·
2016-03-09 08:00
【bzoj1914】[Usaco2010 OPen]Triangle
Counting
数三角形 计算几何
补集转化总数-不能过原点的三角形我们发现先按照极角排序,然后枚举每个点,这个点与原点连线的一侧任选两个点与这个点围成的三角形都不能过原点那么怎么计算呢?其实按顺序枚举每个点,每个点只计算一遍,则正好不重不漏的计算了每一种情况我们发现只要顺序枚举就可以了,按极角序枚举时,每次向后移一个点,会在原来的点的个数上-1假如枚举到点i,记一个右端点r,在当前节点与原点所在的直线右侧的点的集合一定是[i+1,
u012288458
·
2016-03-08 21:00
POJ 3046 Ant
Counting
POJ3046题目大意如下:指定蚂蚁家族有T个,每个家族的蚂蚁数量最多为100只,最少当然为1了,总共有A只蚂蚁,每只蚂蚁唯一的区别就是它所对应的家族编号,相同编号的蚂蚁看成没有差别。现在将这些蚂蚁分成不同的集合,指定每次分割是的集合大小(每次分割出来的集合大小都是统一的)。现在指定集合大小的范围,求出对于不同集合大小的分割方法的总和。这是一个递推问题当然也是DP,所以重要的不是自己去模拟分类,而
kornberg_fresnel
·
2016-03-07 00:00
dp
ACM
poj
ICPC
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