Trapping

Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,
·2015-11-11 15:15

[Leetcode][Python]42: Trapping Rain Water

# -*- coding: utf8 -*-'''__author__ = '[email protected]'42: Trapping Rain Waterhttps://oj.leetcode.com
·2015-11-11 12:56

Trapping Rain Water

Question: Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given&nbs
·2015-11-11 10:09

Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,
·2015-11-11 10:55

[leetcode][042] Trapping Rain Water (Java)

题目在这里: https://leetcode.com/problems/trapping-rain-water/ [标签] Array; Stack; Two Pointers 这个题我感觉很难
·2015-11-11 05:37

leetcode Trapping Rain Water

  Trapping Rain Water   Total Accepted: 2335  Total Submissions: 8464 My
·2015-11-11 04:18

Leetcode: Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1]
·2015-11-11 01:34

[leetcode]Trapping Rain Water

一开始我也像参考链接http://www.cnblogs.com/lichen782/p/Leetcode_Trapping_Rain_Water.html里面一样想了许久想到“俄罗斯方块”想法。
·2015-11-10 21:01

LeetCode Trapping Rain Water

class Solution { public: int trap(int A[], int n) { if (n < 1) return 0; vector<int> peaks; vector<int> peaks_tmp; int last_idx = 0;
·2015-11-09 14:55

Leetcode#42 Trapping Rain Water

原题地址   不妨手动模拟一下，观察是否有规律可寻。 假设从位置0开始，我们有一个矩形条 向右扩展，我们遇到了第二个矩形条，假设这个矩形条比第一个矮： 我们继续向右扩展，直到遇到比第一个矩形条高（或者相等）的矩形条： 那么显然，蓝色的部分就是装水的部分，把这部分累加到最终的结果中 然后，以新发现的这个矩形条为左边界，继续向右扩展... 通过模拟我们发现
·2015-11-09 12:04

Trapping Rain Water

Trapping Rain Water Given n non-negative integers representing an elevation map where the
·2015-11-08 11:13

Trapping Rain Water

https://leetcode.com/problems/trapping-rain-water/ Given n non-negative integers representing
·2015-11-07 10:11

leetcode[42]Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,
·2015-11-05 08:14

Trapping Rain Water

Trapping Rain Water 问题： Given n non-negative integers representing an elevation map where
·2015-11-03 21:05

【leetcode】Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,
·2015-11-02 14:17

LeetCode - Trapping Rain Water

Trapping Rain Water 2014.2.10 03:25 Given n non-negative integers representing an elevation
·2015-11-02 11:11

[Leetcode] Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,
·2015-11-02 09:22

【leetcode】Trapping Rain Water(hard)

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,
·2015-11-02 09:43

[LeetCode] Trapping Rain Water 栈

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,
·2015-11-01 14:56

Twitter算法面试题详解（Java实现）——Trapping Rain Water

【算法题：求出高低不同的砖中能存多少水】 「Trapping Rain Water」 Given n non-negative integers representing an
·2015-11-01 13:51

leetcode Trapping Rain Water

无脑写代码代码（TLE）： 1 #include<iostream> 2 #include<vector> 3 4 using namespace std; 5 6 int findLeft(int i, vector<int> height) 7 { 8 int t = i-1; 9 while
·2015-11-01 11:32

[LeetCode] 接雨水，题 Trapping Rain Water

这题放上来是因为自己第一回见到这种题，觉得它好玩儿 =) Trapping Rain Water Given n non-negative integers representing
·2015-11-01 08:28

Trapping Rain Water

还有candy那道题，好像都是这种双扫系列的 ref http://fisherlei.blogspot.com/2013/01/leetcode-trapping-rain-water.html
·2015-10-31 17:47

第一次刷leetcode小结

LeetCode 上不会的 Reverse Integer Gray Code Generate Parentheses Pascal's Triangle II 正方向读和反方向读保持不变的区别 Trapping
·2015-10-31 14:58

[LeetCode] Trapping Rain Water

Trapping Rain Water Given n non-negative integers representing an elevation map where
·2015-10-31 12:36

Trapping Rain Water [LeetCode]

Problem Description: http://oj.leetcode.com/problems/trapping-rain-water/ Basic idea: Get the index
·2015-10-31 09:20

[leedcode 42] Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,
·2015-10-31 08:40

Leetcode: Trapping Rain Water

题目 Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,
·2015-10-30 17:50

Leetcode:Trapping Rain Water

戳我去解题 Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,
·2015-10-30 16:27

Trapping Rain Water leetcode java

题目： Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,
·2015-10-30 10:11

[LeetCode] Trapping Rain Water 收集雨水

  Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [
·2015-10-28 08:11

leetcode -- Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,
·2015-10-28 08:20

[leetcode]Trapping Rain Water @ Python

原题地址：https://oj.leetcode.com/problems/trapping-rain-water/ 题意： Given n non-negative
·2015-10-28 08:10

LeetCode:Container With Most Water,Trapping Rain Water

Container With Most Water 题目链接 Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is
·2015-10-26 15:43

Trapping Rain Water

使用栈结构解决。 #include <iostream> #include <stack> using namespace std; class Solution { public: int trap(int A[], int n) { if (n<3){ return 0; }
·2015-10-23 08:18

Trapping Messages Sent to an Application

http://www.delphicorner.f9.co.uk/articles/apps7.htm Trapping Messages Sent to an Application I wrote
·2015-10-21 10:46

LeetCode Trapping Rain Water

原题链接在这里：https://leetcode.com/problems/trapping-rain-water/参考这篇帖子：http://www.cnblogs.com/springfor/p/3877101
Dylan_Java_NYC·2015-10-15 02:00

leetcode-42 Trapping Rain Water

问题描述：Given n non-negativeintegersrepresentinganelevationmapwherethewidthofeachbaris1,computehowmuchwateritisabletotrapafterraining.Forexample, Given [0,1,0,2,1,0,1,3,2,1,2,1],return 6.Theaboveelevatio
woliuyunyicai·2015-10-09 20:00

LeetCode 42 [Trapping Rain Water]

原题给出n个非负整数，代表一张X轴上每个区域宽度为1的海拔图,计算这个海拔图最多能接住多少（面积）雨水。海拔分别为[0,1,0,2,1,0,1,3,2,1,2,1],返回6.解题思路一块直柱能接的水取决于左右两边较短的高度，所以第一个比较直观的方法是从左到有遍历一遍记录该点左边的最大值，从右到左遍历一遍记录该点的右边的最大值，此方法为O(n)时间,O(n)空间，第二种方法可以利用单调递减栈来实现，
Jason_Yuan·2015-10-07 10:14

leetcode笔记：Trapping Rain Water

一.题目描述Givennnon-negativeintegersrepresentinganelevationmapwherethewidthofeachbaris1,computehowmuchwateritisabletotrapafterraining.Forexample,Given[0,1,0,2,1,0,1,3,2,1,2,1],return6.Theaboveelevationmap
Herbert_Zero·2015-10-02 23:08

leetcode笔记：Trapping Rain Water

一.题目描述Givennnon-negativeintegersrepresentinganelevationmapwherethewidthofeachbaris1,computehowmuchwateritisabletotrapafterraining.Forexample,Given[0,1,0,2,1,0,1,3,2,1,2,1],return6.Theaboveelevationmap
liyuefeilong·2015-10-02 23:00

LeetCode（42）Trapping Rain Water

题目Givennnon-negativeintegersrepresentinganelevationmapwherethewidthofeachbaris1,computehowmuchwateritisabletotrapafterraining.Forexample,Given[0,1,0,2,1,0,1,3,2,1,2,1],return6.Theaboveelevationmapisre
fly_yr·2015-09-29 13:00

*LeetCode-Trapping Rain Water

感觉很难想到两个指针从两边两边也都keep一个max每次只挪动一个根据当前那个低就挪动那个为了两个指针相遇的时候不会有冲突而且相遇的时候也是低的一边决定水位然后被挪动的一边判断当前高度和这边max的值假如更高了就updatemax，否则就填一部分填的是当前高度这个unit的上面和相应这边max之间的水publicclassSolution{ publicinttrap(int[]height){
bsbcarter·2015-09-22 06:00

Trapping Rain Water

Given n non-negativeintegersrepresentinganelevationmapwherethewidthofeachbaris1,computehowmuchwateritisabletotrapafterraining.Forexample, Given [0,1,0,2,1,0,1,3,2,1,2,1],return 6.Theaboveelevationmapi
qdqade·2015-09-15 09:49

Trapping Rain Water

Given n non-negativeintegersrepresentinganelevationmapwherethewidthofeachbaris1,computehowmuchwateritisabletotrapafterraining.Forexample, Given [0,1,0,2,1,0,1,3,2,1,2,1],return 6.Theaboveelevationmapi
qdqade·2015-09-15 09:49

Trapping Rain Water

Givennnon-negativeintegersrepresentinganelevationmapwherethewidthofeachbaris1,computehowmuchwateritisabletotrapafterraining.Forexample,Given[0,1,0,2,1,0,1,3,2,1,2,1],return6.Theaboveelevationmapisrepr
qdqade·2015-09-15 09:49

[置顶] Trapping Rain Water

题目大意在二维的平面上，有许多堵高低不同的墙，这些墙有一个神奇的性质，那就是装水，如果有三堵墙，从左到右排列，高度分别为2、1、2，那么，这三堵墙就可以装下1个单位的水，现在给你每堵墙的高度，请求出最多能装多少水。思路最开始的想法是暴力找第二高的墙，然后把每堵墙和它做差就可以找了，但是这样是不对的。后来想把不断找第二、三、四……高的墙然后做差，主要思路是找到两个不能储水的墙，这两堵墙中间的格子是可
Biopunk·2015-08-01 03:00

Leetcode - Trapping Rain Water

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1],
likesky3·2015-07-22 22:00

LeetCode42:Trapping Rain Water

Given n non-negativeintegersrepresentinganelevationmapwherethewidthofeachbaris1,computehowmuchwateritisabletotrapafterraining.Forexample, Given [0,1,0,2,1,0,1,3,2,1,2,1],return 6.Theaboveelevationmapi
u012501459·2015-07-20 16:00

[LeetCode] Trapping Rain Water

Note: The following idea is in fact from the last answer in this link, which leads to a clean code. I just reorganize it and add some explanations. I hope it is Ok. The following are four soluti
·2015-07-14 23:00
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