going

每日英语：New Reason To Get The Kids To Bed On Time

Going to bed at the same time every night could give your child's brain a boost, a recent study found.Researchers
·2015-10-21 11:24

每日英语：Can Going In and Out of Air Conditioning Cause Colds?

For most people, summer involves numerous daily shifts between scorching outdoor heat and frosty air-conditioned interiors. But does exposing the body to extreme temperature swings make people sick? P
·2015-10-21 11:19

Flash/Flex学习笔记(28)：动态文本的滚动控制

flash.events.Event; import flash.events.MouseEvent; var flag:int = 0; txtMsg.text = "这是一首很好听的歌：Going
·2015-10-21 11:30

美剧字幕-美国怪谭-第一季第一集

美剧字幕-美国怪谭-第一季第一集 努力学习英语 you are going to die in there.
·2015-10-21 11:15

POJ 3345 Bribing FIPA(树形DP)

Description There is going to be a voting at FIPA (Fédération Internationale de Programmation
·2015-10-21 11:48

1z0-052 q209_4

You need to insert data to the child table first because it is going to be a long transaction and data
·2015-10-21 11:09

SDE面试技巧之四：算法面试

You’re not going to lose points asking for clarifications or talking through the obvious upfront.
·2015-10-21 11:55

Poverty in USA and China

Today I am going to tal
·2015-10-21 11:08

iis设置脚本

For my first entry, I am going to discuss a freq
·2015-10-21 11:55

Unrealircd走入困境

以下摘自unrealircd官方站点: Syzop going inactive Because my wrist condition 
·2015-10-21 10:00

NSInvocation Basics

In this article I'm going to cover the basics and usages of NSInvocation.
·2015-10-21 10:40

STM32F2xx DMA Controllers

/08/18/stm32f2xx-dma-controllers/ If you’re moving a bunch of data around, the DMA controllers are going
·2015-10-21 10:56

Spoken English（017）

You are going out of your way for us ,I believe It’s just the matter of the schedule,that is if it
·2015-10-21 10:13

同步训练2-项目整体管理

During the middle of the project, things have been going well.
·2015-10-21 10:56

看美片必备英语常识

1．What the *** is going on?（到底他母亲的怎么回事？） 　　 　　　　通常此话出于黑人之口，且口气最宜为疑惑，不解，愤怒等等。 　　 　　　　
·2015-10-21 10:52

Stop going 40 mph in first gear

This article is recommends three sources for better ways to work. It’s not about testing in particular, just working. Working in technology can be chaotic. You will often get a lot of training in th
·2015-10-21 10:23

15 个编程热点，和15 个渐冷的趋势

www.infoworld.com/article/2609017/application-development/application-development-15-hot-programming-trends-and-15-going-cold.html
自由之信·2015-10-15 19:00

【进阶——最小费用最大流】hdu 1533 Going Home （费用流）Pacific Northwest 2004

题意：给一个n*m的矩阵，其中由k个人和k个房子，给每个人匹配一个不同的房子，要求所有人走过的曼哈顿距离之和最短。 输入：多组输入数据。每组输入数据第一行是两个整型n, m，表示矩阵的长和宽。接下来输入矩阵。 输出：输出最短距离。 题解：标准的最小费用最大流算法，或者用KM算法。由于这里是要学习费用流，所以使用前者。最小费用最大流，顾名思义，就是在一个网络中，不止存在流量，每单位流量还存在一个费用
mypride·2015-10-13 21:00

poj Going from u to v or from v to u? 强联通缩点+拓扑排序（或搜索）

方法一#include #include #include #include #include #include #include #include #include #include #include #include #include //#include usingnamespacestd; typedeflonglongll; constintN=1024; structEdge { in
xinag578·2015-09-11 09:00

HDU_1533_Going Home(最小费用流模板)

GoingHomeTimeLimit:10000/5000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):3492    AcceptedSubmission(s):1795ProblemDescriptionOnagridmaptherearenlittlemenandnhouses.Ineac
jhgkjhg_ugtdk77·2015-09-11 00:00

Java compiler与installed Java project face不匹配解决方法

So if you are using java 1.6 for building your project, you are going to face this issue every time you
残风vs逝梦·2015-08-30 07:00

HDU 1533--Going Home【最小费用最大流 && 模板】

GoingHomeTimeLimit:10000/5000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):3452    AcceptedSubmission(s):1771ProblemDescriptionOnagridmaptherearenlittlemenandnhouses.Ineac
hpuhjh·2015-08-28 00:00

hdoj 1533 Going Home 【最小费用最大流】【KM入门题】

GoingHomeTimeLimit:10000/5000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):3443AcceptedSubmission(s):1763ProblemDescriptionOnagridmaptherearenlittlemenandnhouses.Ineachunittim
笑着走完自己的路·2015-08-24 14:12

hdoj 1533 Going Home 【最小费用最大流】【KM入门题】

GoingHomeTimeLimit:10000/5000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):3443    AcceptedSubmission(s):1763ProblemDescriptionOnagridmaptherearenlittlemenandnhouses.Ineac
chenzhenyu123456·2015-08-24 14:00

POJ 2195 Going Home(二分图最大权值匹配) KM

DescriptionOnagridmaptherearenlittlemenandnhouses.Ineachunittime,everylittlemancanmoveoneunitstep,eitherhorizontally,orvertically,toanadjacentpoint.Foreachlittleman,youneedtopaya$1travelfeeforeveryste
zhou_yujia·2015-08-23 22:00

poj 2195 Going Home (费用流/KM)

给出n个人，n个房子的坐标，每个人移动1格需要花费$1，求n个人分别进入n个房子所需最小花费。法一：最佳完美匹配(KM算法)O(n^3)建图：求出各个房子和人的曼哈顿距离作为边权值，求最优匹配就好了。法二：费用流建图：1、将人编号为1-cntM，房子编号为cntM+1到cntM+cntH2、每个人到每个房子连一条边，容量为1，边权为二者曼哈顿距离。3、添加源点0，到每个人连一条边，容量为1，边权为
u014679804·2015-08-21 20:00

HDU-1533 Going Home（二分图匹配）

最近开始做最小费用流的题目，该题是二分图完美匹配下的最小权匹配，所谓完美匹配就是说从源点流入的总流量等于从汇点流出的总流量，在这种状态下的最小费用。 那么显然是要套用最小费用流模板，另外二分图匹配的第一步就是要划分集合，划分两个集合，集合A与源点相连，集合B与汇点相连，至于容量和权值就要依据题目而定。比如该题，因为每个小人恰好能对应一个房子，所以每个小人与汇点的容量为1，房子与汇点的容量为1，这样
weizhuwyzc000·2015-08-21 10:00

hdu1533Going Home KM算法

//给一个n*m的图， //m表示人，h表示房子 //问所有人走回家的最小步数 //每个人只能进一间房 //很明显的最大带权匹配 //每个人到每每间房的距离即为权值 //由于是求最小，只要改为负权就行 #include #include #include #include #include usingnamespacestd; constintmaxn=110; constintinf=0x3f3
cq_pf·2015-08-17 14:00

POJ 2195 && HDU 1533 Going Home（最小费用最大流-mcmf）

Description在一个N*M的地图上有若干个人和与其数量相同的房子，每个房子只能容纳一人，每个人移动一格需花费$1，问让所有人都住进房子的最小花费Input多组用例，每组用例第一行为两个整数N和M表示地图行列数，之后为以N*M矩阵，’.’表示空地,’H’表示房子,‘m’表示人，以00结束输入Output对于每组用例，输出使所有人都住进房子的最小花费SampleInputSampleOutpu
V5ZSQ·2015-08-11 15:00

poj 2195 Going Home【最小费用最大流】

题目链接：http://poj.org/problem?id=2195题意：给你一些人的位置，和屋子的位置，求使得所有人回到屋子的最小花费是多少。每个屋子只能装一人。人每横着或竖着走一步，花费为1。解法：最小费用流。bin神板子建图是原点到人，人到屋子，屋子到汇点。流量均为1，人与屋子费用为距离。其他费用为0；代码：/*POJ2195GoingHome邻接矩阵形式最小费用最大流*/ #inclu
u014427196·2015-08-07 20:00

HDU 1533 Going Home 最小费用最大流

DescriptionOnagridmaptherearenlittlemenandnhouses.Ineachunittime,everylittlemancanmoveoneunitstep,eitherhorizontally,orvertically,toanadjacentpoint.Foreachlittleman,youneedtopaya$1travelfeeforeveryste
qq_26564523·2015-08-07 15:00

poj 2762 Going from u to v or from v to u? 【判断图是否为弱连通】 【tarjan求SCC + 缩点 + 拓扑排序】

Goingfromutovorfromvtou?TimeLimit: 2000MS MemoryLimit: 65536KTotalSubmissions: 15720 Accepted: 4155DescriptionInordertomaketheirsonsbrave,JiajiaandWindtakethemtoabigcave.Thecavehasnrooms,andone-waycor
chenzhenyu123456·2015-08-02 09:00

UFT 12 – Top 5 New Features you are going to Love

NewUnifiedFunctionalTestingFeaturesAfewdaysago,rightbeforeChristmas,HPfinallymadeUFT11.5availablefordownload.Here’saquicklookatthetopfivefeaturesIthinkyou’regoingtolove:5)NewAdd-InsforFlexandQtapplica
xuyubotest·2015-07-30 00:00

Hibernate: Implicit & Explicit Polymorphism

As I was going through the various inheritance strategies in Hibernate, I came across the ‘class’ element
·2015-07-26 00:00

HDU 1533.Going Home(费用流模板)

#include #include #include #include #include #include #include #include #include #include #include #include #include usingnamespacestd; #defineINF0x3f3f3f3f #defineinf-0x3f3f3f3f #definelsonkedges; ve
acm_fighting·2015-07-25 18:00

lib32asound2 : Depends: libc6-i386 (>= 2.7) but it is not going to be installed

sudo apt-get install -f sudo dpkg --configure -a sudo apt-get clean sudo apt-get update sudo apt-get upgrade Environment: Ubuntu 12.04 LTS 64bit Problem: Unable to install teamviewer; e
·2015-07-11 09:00

poj 2762 Going from u to v or from v to u?(SCC缩点+拓扑排序)

判断图是否是单连通图。强连通缩点后得到DAG图，然后拓扑排序，删点之后若形成1个以上入度为0的点，说明有超过1条链，不是单连通图。#include #include #include #include #include #include #include usingnamespacestd; #definemaxn1005 vectorG[maxn]; intpre[maxn],low[maxn]
u014679804·2015-06-27 12:00

when going for the shoe

"Loveyouall,"shesaidAnotherwavearrivedafterthesecondIraqwar,withIraqirefugeesformingthemajorityofAuthenticSebastianJanikowskiJerseynewcomers5millionofstocktocoveraninterestpaymentofabout$13"That'satru
lluggg872·2015-06-25 14:00

is going to be和will be的区别

 is going to be和will be的区别问题: Don't worry.He___________all right soon.
roddy·2015-06-15 10:00

[费用流] POJ 2195 Going Home

题目链接：http://poj.org/problem?id=2195题意：地图上有相同数量的人和房屋，让所有人回到不同的房屋里，总的路程最小，路程定义为哈密顿距离。昨天开始看了一下费用流，思想和最大流差不多，只是找增广路的时候找最小花费的路径来增广。用最好理解的EK算法来看，EK中的BFS过程就是在找增广路，如果把这个过程变成找一条最花费小的增广路就可以了。关于增广路的理解，由EK的BFS看来，
kg20006·2015-06-07 16:00

NYOJ 991 Registration system（map简单应用）

OK 描述 A new e-mail service "Berlandesk" is going to be opened in Berland in the near future. 
helloiamclh·2015-06-03 07:00

(GoogLeNet)Going deeper with convolutions笔记

转自 http://www.gageet.com/2014/09203.phpGoingdeeperwithconvolutions笔记ContentsAbstractIntroductionRelated WorkMotivation and High Level ConsiderationsArchitectural DetailsGoogLeNetTraining MethodologyIL
csyhhb·2015-05-25 11:00

SharePoint list lookup column indexing and CAML query relation

But as the lists are going to have large number of items the performance is decreas
yake022·2015-05-18 14:00

Tasker to proximity screen off

off, you may know how convenient it is to automate our lives via built-in proximity sensor.Now I am going
·2015-05-18 01:00

Topshelf Configuration z

Topshelf Configuration While the Quickstart gives you enough to get going, there are many more features
·2015-04-24 22:00

Registration system

Registrationsystem时间限制：1000 ms | 内存限制：65535 KB难度：2描述A new e-mail service "Berlandesk" is going to be
bao_libra·2015-04-21 14:00

Making Physics Based Side-Scroller Part 4: Screen Sizes and Resolutions

overlap2d.com/making-physics-based-side-scroller-part-4-screen-sizes-and-resolutions/   Today we are going
gcc2ge·2015-04-09 21:00

Making Physics Based Side-Scroller Part 3: Adding UI and Moving Platforms

Today we are going to do the 3d part of the tutorial on side-scro
gcc2ge·2015-04-09 21:00

【最小费用最大流】【HDU1533】【Going Home】

题意 给你一个类似这样的图...H.......H.......H....mmmHmmmm...H.......H.......H....问所有H移动到所有m上花费最少的步数以所有H到所有m连一条边，边的权重为2者距离，这样其实就是一个二分图带权匹配也可以用KM算法来做网络流做法类似二分图最大流做法，左右来个超级源，超级汇，然后求一边费用流即可/* 1.WA关于二分图匹配的数据范围要注意是否要乘以
zy691357966·2015-04-05 19:00

POJ2195 Going Home【二分图最佳匹配】

题目链接：http://poj.org/problem?id=2195题目大意：在一个N*M的矩阵中，有M个人和M个房子，每个人要安排一个房子，每个房子只能安排一个人。而每个人移动一步需要一美元。那么问题来了：求为每个人安排房子移动所需要的金钱最小值是多少。思路：做一个二分图，一边为人，另一边为房子，如果把人和房子之间的距离作为边权的话，问题就变成了求带权二分图最小权和的最佳匹配。这里我们为了方便
u011676797·2015-04-02 20:00
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