going

Google App Engine(2)Java Start and Project

The Project Directory The structure of the project is going to be
sillycat·2013-01-07 05:00

Custom video/camera overlay view on the iPhone

p=443 Today I am going to show how we can add a custom overlay view to the standard iPhone video capt
zl4393753·2013-01-03 23:00

ActionScript翻译的Asteroids

flash edition // just translate the python code into AS3.0, I  // will optimize it later // First I am going
seandor·2012-12-21 11:00

Prefer--Going To Translate The Book Of Andriod Application Testing Guide

   写在前面的话——   最近测试Andriod应用程序，主要在功能方面，均为手工黑盒测试，感觉没有什么深度，想系统地学习一下关于Andriod的测试，于是在网上翻来覆去找资料，但关于Andriod的测试，自动化的都是一些基本的描述，并不够深入也不成系统，昨天看到网上一本pdf格式的书籍《AndriodApplicationTestingGuide》,大概看了一下目录，感觉还比较系统全面，但没有
BenShare·2012-12-15 14:52

勇猛精进系列文档之《建议背诵的英语口语》

Get going!     赶快动身吧！ 用在开始行动时。 3. We've got to hit the road.
overloving·2012-12-12 15:00

mysql/jdbc function in out param

So i need to run a jdbc call that is going against a sql server database.
·2012-12-10 14:00

hdu 1533 Going Home【KM算法求最大权匹配】

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1533我的链接：http://acm.hust.edu.cn:8080/judge/contest/view.action?cid=17728#problem/BGoingHomeTimeLimit:10000/5000MS(Java/Others)    MemoryLimit:65536/32768
Cfreezhan·2012-12-04 18:00

自定义进度条

UIProgressView and Custom Track and Progress Images (iOS 5 properties) Here's what's going on:
zl4393753·2012-11-29 00:00

Weblogic server 运行状态是: ADMIN

Here we are going to see a Scenario which is very common but troublesome.
Mint_Grass·2012-11-13 11:00

Persisting Cookies In An iOS Application?

    I am going to use NSHTTPCookieStorage in an iOS App to manage cookies that are retrieved
cppmule·2012-10-19 10:00

c++ - virtual inheritance example 1

In this post we are not going to discuss the theory but instead we are going to show you an example
joe.bq.wang·2012-10-14 15:00

httpclient 在获取返回值时，使用getResponseBodyAsString触发警告的问题

getResonseBodyAsString方法时会出现一个警告：   org.apache.commons.httpclient.HttpMethodBase getResponseBody警告: Going
jianlao888·2012-10-12 16:00

Going Home

说明：此题思路代码为网上他人思路与代码，忘记出处，故而抄袭与此。题意：给定一个N*M的地图，地图上有若干个man和house，且man与house的数量一致。man每移动一格需花费$1（即单位费用=单位距离），一间house只能入住一个man。现在要求所有的man都入住house，求最小费用。参考：MCMF模版题/KM模板题解题思路：费用流问题。 构图：       把man作为一个顶点集合U，h
sdjzujxc·2012-10-12 13:00

c# - Syntax Evolution form delegate to lambda expression

First let's see the code example upfront, to give readers the feeling of topic that we are going to cover
joe.bq.wang·2012-10-10 17:00

Linux 下Common Lisp编程环境搭建 [Getting Going With Modern Common Lisp on Linux]

原文链接：http://www.mohiji.org/2011/01/modern-common-lisp-on-linux/一、下载并安装Emacs和SBCLsudoapt-getinstallemacs sudoapt-getinstallsbcl二、下载Quicklisp.lisp文件 http://beta.quicklisp.org/quicklisp.lisp 三、运行SBCL，并输入
yang_7_46·2012-10-04 15:00

Crawl a website with scrapy

  Introduction In this article, we are going to see how to scrape information from a website, in
michaelh0226·2012-09-27 11:00

POJ 2195 Going Home 费用流模版题（附KM算法，转）

题意：给出一个n*m的图，其中m是人，H是房子，每个人移动一步需要一块，问所有人移动到房子里的最少花费。建图：建立一个超级源点和超级汇点，S=0，T=2*num+1。从源点到所有的人建立一条流，容量cap[S][i]=1,费用cost[S][i]=0；从房子到汇点建立一条流，容量cap[j][T]=1,费用cost[j][T]=0;建立所有人到所有房子的流，cap[i][j]=1,cost[i][
kdqzzxxcc·2012-09-27 00:00

c++ - template specialization and partial specialization

in this post, we are going to examining partialization.
joe.bq.wang·2012-09-26 22:00

HDU 1533 Going Home

GoingHomeTimeLimit:10000/5000MS(Java/Others)MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):1799AcceptedSubmission(s):871ProblemDescriptionOnagridmaptherearenlittlemenandnhouses.Ineachunittime
zhjchengfeng5·2012-09-17 23:00

java:struts2 tag->autocompleter

www.roseindia.net/struts/struts2/struts2uitags/autocompleter-example.shtml In this section, we are going
·2012-09-16 22:00

【php】怎样通过php程序返回xml格式的数据

$site[title] "; foreach($going_goodsas$key=>$val){ $defaultCity=getCity($val['cityid']); $starttime
yanhui_wei·2012-09-16 20:00

如何创建一个Sencha Touch 2应用_记事本案例(第四部分)

In this article, we are going to complete the following tasks:Add the delete note feature to the Note
yanwushu·2012-09-13 17:00

如何创建一个Sencha Touch 2应用_记事本案例(第三部分)

    In this third part of this tutorial on how to create a Sencha Touch application, we are going to 
yanwushu·2012-09-12 15:00

c++ - c++ iterator revisiting

In this post we are going to revist the iterator.
joe.bq.wang·2012-09-11 23:00

c# - reflection in the System.Reflection.Emit namespace - AssemblyBuilder

    In this code, we are going to show how to
joe.bq.wang·2012-09-10 22:00

c# - reflection in the System.Reflection.Emit namespace - ModuleBuilder

In this topic, we are going to discuss the how to use the ModuleBuilder from this particular namespace
joe.bq.wang·2012-09-10 19:00

12 Bash For Loop Examples for Your Linux Shell Scripting

Therearetwotypesofbashforloopsavailable.Oneusingthe“in”keywordwithlistofvalues,anotherusingtheCprogramminglikesyntax.Thisarticleispartofouron-going
liufei_learning·2012-08-30 17:00

c++ - template function specialization

In this post, we are going to discuss the template function specialiation ; so what is "template
joe.bq.wang·2012-08-29 23:00

mysql优化索引 —— Using filesort

The sort is done by going through all row
san_yun·2012-08-23 17:00

HDU-2195-Going Home

HDU-2195-GoingHomehttp://acm.hdu.edu.cn/showproblem.php?pid=1533之前用最小费用最大流做的，今天看了最大带权匹配的KM算法，套用了模板来做这题，将所有的H作为X集合，所有的m作为Y集合，构造二分图求最大带权匹配#include #include #include #include #include usingnamespacestd;
Cambridgeacm·2012-08-19 19:00

POJ 2762 Going from u to v or from v to u?(Tarjan)

题意：对任给的两个点x，y，是否一定有路，从x到y，或者从y到x，，，刚开始看错了，以为是赤裸裸的Tarjan，结果是或，不是且，，比较简单#include #include #include #include #include #include #include usingnamespacestd; constintN=1009; constintM=6009; constintINF=0x3f
binwin20·2012-08-17 15:00

poj 2762 Going from u to v or from v to u?

题意：给出一幅有向图，要求判断，判断在这幅图中的任意两点x,y，一定有一条路可以从x到y或从y到x。思路：缩点+拓扑，一个连通分量一定是满足要求的，那么把连通分量缩成点，拓扑排序，若是在删除某点后，有两个点的入度都为0，则输出No；若能全部删除输出Yes。#include usingnamespacestd; constintMAXN=1001; intDFN[MAXN]; intLOW[MAXN
rookie_Algo·2012-08-15 01:00

UVa 270 - Lining Up

com_onlinejudge&Itemid=8&category=113&page=show_problem&problem=206 原题： ``How am I ever going
king_tt·2012-08-14 10:00

POJ-2195-Going Home

POJ-2195-GoingHomehttp://poj.org/problem?id=2195最小费用最大流，假想一个源点，一个汇点代码模仿网上的写的，还要再好好研究哇#include #include #include #definemaxn300 #defineINF0x7fffffff intmin(intx,inty) { returnxdis[k]+map[k][i]) { dis[i
Cambridgeacm·2012-08-13 15:00

KM算法 最优匹配(最大权匹配) hdu 2255 奔小康赚大钱 最小权匹配 poj 2195 Going Home

  最大权二分匹配问题就是给二分图的每条边一个权值，选择若干不相交的边，得到的总权值最大。解决这个问题可以用KM算法。理解KM算法需要首先理解“可行顶标”的概念。可行顶标是指关于二分图两边的每个点的一个值lx[i]或ly[j]，保证对于每条边w[i][j]都有lx[i]+ly[j]-w[i][j]>=0。如果所有满足lx[i]+ly[j]==w[i][j]的边组成的导出子图中存在一个完美匹配，那么
qq172108805·2012-08-11 17:00

linux-压缩和解压缩

v is to be verbose about what is going on. f is to force overwriting if it wa
cheyonghong·2012-08-07 15:00

poj2195 Going Home

题义：在一个图上，n个人回n个家，可以路过家门而不进去，图中m代表人，H代表家，每人走一步，需要花费1元，求要是这些人都回家，最少花多少。分析：看到题目后首先可以想到的就是人和家是2个集合，人不能与人相连，家也不能与家相连，那么就可给人和家编号，从而构造出一幅2分图，由于可以过门而不入，就说明途中没有障碍物，这就意味着不必去广搜，直接找坐标之间的关系，来确定两点之间的开销。只是一道KM算法求最小匹
rookie_Algo·2012-07-28 13:00

Apple's Mountain Lion coming July 25?

for July 24, top to speculation that the firm's new Mac functioning system, OS X Mountain Lion, is going
sbguh·2012-07-24 17:00

VOA SE - 1 - 2012-07-24

Conflicts around the world are keeping tens of millions of young people from going to school.
rjw·2012-07-24 13:00

WPF Dynamically load resource

  Here we are going to discuss another approach, wher
joe.bq.wang·2012-07-18 18:00

hdu 1533 Going Home（KM算法）

GoingHomeTimeLimit:10000/5000MS(Java/Others)    MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):1415    AcceptedSubmission(s):698ProblemDescriptionOnagridmaptherearenlittlemenandnhouses.Ineach
gzhu_101majia·2012-07-12 23:00

poj 2762 Going from u to v or from v to u?

题目链接:http://poj.org/problem?id=2762题目大意:判断该图是否是单连通图(任意取两点a,b必然有a->b或b->a或ab).题目思路:先把每一个点的入度求出.寻找是否有入度为0的点,如果没有:该图肯定是强连通的(必然也是单连通).如果有且不止一个:因为从其中随便算两个入度为0的点,它们肯定不可互达.如果有且只有一个:把该点入度置为-1(或者一个很大的数)并把和该点相邻
gotoac·2012-07-07 17:00

poj 2195 Going Home--最小费用最大流--spfa--动态数组--或者用 最小权匹配

/* 题意：给定一个N*M的地图，地图上有若干个man和house，且man与house的数量一致。man每移动一格需花费$1（即单位费用=单位距离）， 一间house只能入住一个man。现在要求所有的man都入住house，求最小费用。 最小费用最大流用到了spfa求费用最小的可改进路径 仿写http://blog.csdn.net/lyy289065406/article/details/67
qq172108805·2012-07-04 16:00

学习日志2012-06-01~2012-06-19

msdn.com/blogs/adebruyn/techdays-2010-developer-keynote-by-anders-hejlsberghttp://channel9.msdn.com/Shows/Going
·2012-06-20 16:00

动感英语22

I'll have to take a rain check on going to the movies. I have too much work to do tonight.
zgq456·2012-06-16 22:00

Going to buffer response body of large or unknown size. Using getResponseBodyAsS

使用HttpClient，总是报出“Going to buffer response body of large or unknown size.
shmily2038·2012-06-08 08:00

delphi - 为 Frame 添加 OnShow 事件响应函数.

更具体的说明可以参看以下两处:http://manztiara.wordpress.com/2009/10/06/delphi-frame-whats-going-on/http://www.delphifr.com
sailtseng·2012-06-07 11:00

UESTC Training for Graph Theory——J、Going back home

GoingbackhomeTimeLimit: 1000ms MemoryLimit: 65536kB Solved: 31 Tried: 519DescriptionFinally,finallythissemesterisover.QiQiplanstogobackhome.QiQilivesinaworldconsistofncities.HeiscurrentlyatcitySforsch
zhjchengfeng5·2012-06-03 21:00

Solr Searching(一)

In this chapter, you are going to learn about: •     Request handlers •  
chenzehe·2012-05-24 08:00

Enabling SSL on JBoss

Step 1) First of all, we are going to make a keystore.
jiagou·2012-05-15 10:00
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